CSIR NET Mathematical Science Exam 2025: CSIR NET Mathematical Science Exam will take place on July 26, 27, and 28, 2025 (June session). The Council of Scientific and Industrial Research (CSIR) conducts this important national exam, which assesses candidates' knowledge and proficiency in the mathematical sciences. It is required for people pursuing jobs in research or teaching at Indian universities and research institutes.
CSIR NET Mathematical Science exam is used to find out eligibility for Junior Research Fellowship (JRF) and Lectureship positions. The exam is computer-based and consists of 120 multiple-choice questions divided into three sections: Part A, Part B, and Part C. Part A includes general aptitude, Part B covers key mathematical sciences areas, and Part C focuses on analytical and problem-solving abilities in the mathematical sciences.
National Testing Agency (NTA) administers the CSIR NET Mathematical Science Exam twice a year on a nationwide basis. The CSIR Exam Date for 2025 has been announced and will be held on July 26th, 27th, and 28th, 2025. The exam duration is 180 minutes and contains objective-type questions. Here's an overview of the CSIR NET Mathematical Science Exam 2025.
CSIR NET Mathematical Science Exam 2025 Overview | |
Exam Name | CSIR NET 2025 |
Exam Conducting Body | National Testing Agency |
Full Exam Name | Council of Scientific and Industrial Research National Eligibility Test |
CSIR NET 2025 Exam Date | 26,27,28 July 2025 |
Frequency of Exam | Twice a year |
Application Mode | Online |
Exam Mode | Computer-Based Test (Online) |
Subjects Name |
|
Exam Duration | 180 minutes |
Total Marks | 200 marks |
Language/Medium of Exam | English and Hindi |
Official Website | csirnet.nta.nic.in |
CSIR NET Mathematical Science Exam 2025 for the June session is set for July 26, 27, and 28 of 2025. The subject-by-subject exam schedule has yet to be officially confirmed. Candidates can check the CSIR and NTA's official websites for updates. This is an overview of the CSIR NET Exam Date 2025:
CSIR NET Mathematical Science Exam 2025 | |
Event | Date |
CSIR NET 2025 Exam Date | July 26, 27, and 28 |
To apply for the CSIR NET Mathematical Science Exam 2025, candidates must satisfy specific eligibility criteria. These requirements guarantee that applicants have the educational qualifications to work in Mathematical Sciences research or teaching. The following are complete CSIR NET Eligibility Criteria for the exam:
The age limit for CSIR NET varies according to the candidate's category and the fellowship for which they are seeking. The top CSIR NET age limit is 28 years.
To be eligible for the CSIR NET exam, applicants must have an M.Sc. or an equivalent degree, an Integrated BS-MS, a 4-year BS, a BE/B Tech, a B. Pharma, or an MBBS with at least 55% marks.
They must also have a minimum score of 55% in their credentials to be qualified to take the exam.
This exam is open to Indian citizens, candidates of other nationalities are not eligible to take it.
CSIR NET Mathematical Sciences Exam 2025 is separated into three Sections. Each part has multiple-choice questions, and applicants must answer a set number of questions. The question papers will be multilingual, including options in both Hindi and English. The following is the complete exam pattern for the CSIR NET Mathematical Sciences exam 2025:
CSIR NET Mathematical Science Exam Pattern 2025 | ||||
Part | Total Questions | Maximum to Attempt | Marks for Correct Answer | Marks for Incorrect Answer (Negative Marking) |
A | 20 | 15 | 2 | -0.5 |
B | 40 | 25 | 3 | -0.75 |
C | 60 | 20 | 4.75 | 0 |
Total | 120 | 60 | 200 | - |
CSIR NET Mathematical Science Syllabus 2025 contains different subjects to assess applicants' knowledge and comprehension of the mathematical sciences field. The CSIR NET 2025 Syllabus for Mathematical Sciences is divided into several sections. Candidates can check the CSIR NET Mathematical Sciences Syllabus 2025 by downloading the PDF from the provided link.
National Testing Agency (NTA) will publish the CSIR NET Mathematical Sciences Cut Off on its official website, carnet.nta.nic.in. The CSIR NET Cut Off are significant in deciding the selection status of candidates who take the CSIR NET Mathematical Sciences Exam. Candidates who get marks above the given cut off will be considered for Junior Research Fellowship (JRF) and Assistant Professor positions. The normalization method, raw score, and total percentile will be combined to create CSIR NET Mathematical Science Cut Off.