Physics Wallah

NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller

Here we have provided NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller for the ease of the students so that they can prepare better for their examinations.
authorImageNeha Tanna14 Sept, 2024
Share

Share

NCERT Solutions for Class 4 Maths Chapter 6

NCERT Solutions for Class 4 Maths Chapter 6: The NCERT Class 4 Maths book's Chapter 6, "The Junk Seller," uses real-world examples to teach students about money, profit, and loss. It teaches students the fundamentals of business transactions, including how to calculate expenses, prices, and income, through the story of a trash merchant who gathers and sells a variety of goods.

Students gain knowledge of word problem-solving, money addition and subtraction, and object valuation through fun activities. NCERT Solutions for Class 4 Maths Chapter 6 enhances the student's understanding of daily financial operations by emphasizing practical math abilities like mental calculations and budgeting.

NCERT Solutions for Class 4 Maths

NCERT Solutions for Class 4 Maths Chapter 6 Overview

The NCERT Class 4 Maths book's Chapter 6, "The Junk Seller," uses the engaging tale of a trash the supplier to introduce students to the basic ideas of money, profit, and loss. The chapter includes actual situations where a junk seller gathers used, neglected goods and resells them for a profit. Students gain knowledge of financial computations through this story, including how to add and subtract prices, understand profits and losses, and figure out the cost of things. Additionally, NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller clarifies for students the concept of value, how things can be recycled or reused, and why different items have varied costs depending on their utility or condition. Through real-world situations, the exercises and activities aim to enhance fundamental math abilities, particularly mental math. By the end of the chapter, students have a better grasp of common financial transactions, which helps them apply mathematical ideas to practical scenarios and improves their ability to solve problems.

CBSE Class 4 Maths Syllabus

NCERT Solutions for Class 4 Maths Chapter 6 PDF

Below we have provided NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller pdf for the ease of students so that they can download the pdf and access it offline.

NCERT Solutions for Class 4 Maths Chapter 6 PDF

NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller

Below we have provided NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller -

NCERT book Page No: 60

NCERT Solutions Mathematics Class 4 Chapter 6 - 1

Question: 1

(a) What about you? Do you also find Maths difficult?

(b) What is the most difficult thing in your Maths book?

(c) What do you think is the easiest lesson?

Answer:

(a) No, maths is not hard if you practise it properly. (a) I find all of the subjects simple. (c) The practice determines this. It will become easier the more you practise.

NCERT book Page No: 61

Find out: how much for a cup of tea?

Question: 2

Ask people and find out the cost of a cup of tea

(a) At a tea stall.

(b) At a hotel.

Answer:

(a) The cost of tea at a tea stall is Rs 5. (b) The cost of tea at a hotel is Rs 10.

Question: 3

(a) If a person who runs a tea stall earns Rs 30 in a day, how much will he earn in 10 days?

(b) And in a month?

Answer:

(a) Earning in a day = Rs 30 × 1 Hence, earnings in two days will be = Rs 30 × 2 Earnings in 3 days will be = Rs 30 × 3 Earnings in 10 days will be = Rs 30 × 10 = Rs 300 (b) In a month, there are 30 days. If earning in a day costs Rs 30, Then, earnings in 30 days will cost = Rs 30 × 30 = Rs 900

Question: 4

Find out: what is a loan?

(a) Have you ever heard of someone taking a loan? For what?

(b) How much loan was taken?

(c) How much money was paid back?

Answer:

Yes, I am familiar with someone who borrowed money to pay for his son's schooling. (c) He took one lakh rupees. (c) After a year, he returned the sum of Rs. 1,50,000. NCERT Solutions Mathematics Class 4 Chapter 6 - 3

Question: 5

Who has to pay back more – Hariya or Babu?

Answer: For six months, Hariya should pay Rs 51.

Total money paid by Hariya = Rs 51 × 6 = Rs 306 However, after six months, Babu pays Rs 360. As a result, Babu pays Hariya less money.

NCERT book Page No: 62

NCERT Solutions Mathematics Class 4 Chapter 6 - 4

Question: 6

How much does Kiran earn from 9 rickshaws in a day?

Answer: From 1 rickshaw, she earns = Rs 20

So, from 2 rickshaws, she earns = Rs 20 × 2 = Rs 40 Similarly, from 9 rickshaws, she earns = Rs 20 × 9 = Rs 180

Question: 7

For 10 rickshaws, she will get Rs 20 × 10 = Rs 200

So, for 9 rickshaws, she will get Rs 200 – _______ = _______

Answer: For 9 rickshaws, she will get Rs 200 – 20

= Rs 180

NCERT Books for Class 4 Maths 2024-25

NCERT book Page No: 63

Question: 8

In a week, how much does Kiran earn from one rickshaw?

Answer: We know in a week, there are 7 days.

Money earned by Kiran in a day = Rs 20 Hence, money earned by Kiran in a week from one rickshaw = Rs 20 × 7 = Rs 140

Question: 9

Do it mentally and write the answers.

NCERT Solutions Mathematics Class 4 Chapter 6 - 5

Answer:

2 × 6 = 12 20 × 6 = 120 2 × 60 = 120 3 × 42 = 126 4 × 80 = 320 4 × 81 = 324 9 × 25 = 225 31 × 9 = 279

How Much to Pay for this Junk?

Kiran has bought some junk from junk collectors

Question: 10

How much will Kiran pay for 31 kg newspaper?

Answer: 1 kg newspaper cost = Rs 5

31 kg newspaper cost = Rs 5 × 31 = Rs 155 Hence, the cost of 31 kg newspaper is Rs 155.

NCERT book Page No: 64

NCERT Solutions Mathematics Class 4 Chapter 6 - 6

Question: 11

How much will Kiran pay for 42 kg newspaper?

Answer: For 1 kg newspaper Kiran pays = Rs 5

For 42 kg of newspaper, she will pay = Rs 5 × 42 = Rs 210 Hence, Kiran pays Rs 210 for 42 kg of newspaper.

Question: 12

Also, find the cost of

(a) 22 kg of plastic.

(b) 23 kg of waste paper.

(c) 12 kg of iron.

Answer:

(a) The cost of 1 kg of plastic = Rs 10 So, the cost of 22 kg of plastic will be = Rs 10 × 22 = Rs 220 (b) Rate of 1 kg of waste paper = Rs 4 Hence, the cost of 23 kg of waste paper = Rs 4 × 23 = Rs 92 (c) The cost of 1 kg of iron = Rs 12 Hence, the cost of 12 kg of iron will be = Rs 12 × 12 = Rs 144

Question: 13

Guess the total money Kiran will pay to the junk collectors. Will it be

– More than 600?

– Less than 600?

Answer: Total money Kiran pays to the junk collectors are

Cost of 42 kg of newspaper = Rs 210 Cost of 22 kg of plastic = Rs 220 Cost of 23 kg of waste paper = Rs 92 Cost of 12 kg of iron = Rs 144 Therefore, the total cost of all the junk = Rs 666 So, Kiran pays more than Rs 600.

NCERT book Page No: 64-66

Smart Kiran Sells the Junk

NCERT Solutions Mathematics Class 4 Chapter 6 - 7

Question: 14

Kiran bought 1 kg plastic for Rs 10 but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg plastic?

Answer: The cost of 1 kg of plastic that Kiran bought = Rs 10

She sold 1 kg of plastic for Rs 12. Hence, she earned = Rs 12 – Rs 10 = Rs 2

Question: 15

So, how much money does she earn for 63 kg?

Answer: She earns Rs 2 for 1 kg of plastic.

For 63 kg of plastic, she earns = Rs 2 × 63 = Rs 126 Therefore, Kiran earns Rs 126 for 63 kg of plastic. This can be calculated as follows:
60 3
2 60 × 2 3 × 2
120 6
By adding the digits in the last row, we will get 126.

Kiran sells 32 kg iron

Question: 16

How much money will Dinu pay for 32 kg iron?

Answer: The amount by which 1 kg of plastic is sold = Rs 14

Hence, the cost of 32 kg of plastic = Rs 14 × 32 = Rs 448 This can be calculated as follows:
30 2
10 30 × 10 2 × 10
300 20
4 30 × 4 2 × 4
120 8
By adding the bold numbers, we get the desired number. 300 + 20 + 120 + 8 = 448 Hence, the money paid by Dinu for 32 kg of plastic is Rs 448.

Question: 17

Kiran buys 1 kg iron for Rs 12 but sells it for Rs 14. How much does she earn when she sells 32 kg of iron?

Answer: Money earned by Kiran by selling 1 kg of iron = Rs 14 – Rs 12

= Rs 2 Hence, money earned by her by selling 32 kg of iron = Rs 2 × 32 = Rs 64 This can be calculated as follows:
30 2
2 30 × 2 2 × 2
60 4
By adding the numbers in the last row, we can find the desired number. 60 + 4 = 64 Therefore, by selling 32 kg of iron, Kiran earn Rs 64.

What will Dinu pay for 152 kg newspaper?

Question: 18

I bought 1 kg newspaper for Rs 5 but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper?

Answer: Money earned by selling 1 kg of newspaper = Selling price of newspaper – Purchasing price of newspaper

= Rs 6 – Rs 5 = Rs 1 Money earned by her by selling 152 kg of newspaper = Rs 1 × 152 = Rs 152 Therefore, she earns Rs 152 by selling 152 kg of newspaper.

What does Dinu pay for brass?

Question: 19

How much money will Dinu pay for 4 kg brass?

Answer: As per Dinu’s price list, the cost of 1 kg of brass = Rs 180

For 4 kg of brass, Dinu will pay = Rs 180 × 4 = Rs 720 This can also be calculated as follows:
100 80
4 100 × 4 80 × 4
400 320
We get the desired result by adding the digits in the last row. 400 + 320 = 720 Hence, for 4 kg brass Dinu pays Rs 720.

Related Links -

NCERT Solutions for Class 4 Maths Chapter 1 NCERT Solutions for Class 4 Maths Chapter 8
NCERT Solutions for Class 4 Maths Chapter 2 NCERT Solutions for Class 4 Maths Chapter 9
NCERT Solutions for Class 4 Maths Chapter 3 NCERT Solutions for Class 4 Maths Chapter 10
NCERT Solutions for Class 4 Maths Chapter 4 NCERT Solutions for Class 4 Maths Chapter 11
NCERT Solutions for Class 4 Maths Chapter 5 NCERT Solutions for Class 4 Maths Chapter 12
NCERT Solutions for Class 4 Maths Chapter 6 NCERT Solutions for Class 4 Maths Chapter 13
NCERT Solutions for Class 4 Maths Chapter 7 NCERT Solutions for Class 4 Maths Chapter 14

NCERT book Page No: 67

Question: 20

First, guess the answer and then calculate.

(a) 37 × 18 =

(b) 45 × 24 =

(c) 69 × 52 =

(d) 77 × 55 =

(e) 142 × 5 =

(f) 382 × 3 =

(g) 2 × 175 =

(h) 4 × 206 =

Answer:

(a) Here, the number will be near 40 × 20, i.e., about 800. Calculation:
30 7
10 30 × 10 7 × 10
300 70
8 30 × 8 7 × 8
240 56
Now, add the digits in the third and fifth rows, and we get 300 + 70 + 240 + 56 = 666 Therefore, 37 × 18 = 666 (b) 45 × 24 This number will be near 40 × 25 = 1000 Calculation:
40 5
20 40 × 20 5 × 20
800 100
4 40 × 4 5 × 4
160 20
Add the digits in the third and fifth rows, and we get 800 + 100 + 160 + 20 = 1080 Hence, 45 × 24 = 1080 (c) 69 × 52 Here, the number will be near 70 × 50 = 3500 Calculation:
60 9
50 60 × 50 9 × 50
3000 450
2 60 × 2 9 × 2
120 18
On adding the digits in the third and fifth rows, we get 3000 + 450 + 120 + 18 = 3588 Hence, 69 × 52 = 3588 (d) By guessing 77 × 55 The number will be near 80 × 50 = 4000 Calculation:
70 7
50 70 × 50 7 × 50
3500 350
5 70 × 5 7 × 5
350 35
On adding the numbers in the third and fifth rows, we get 3500 + 350 + 350 + 35 = 4235 Therefore, 77 × 35 = 4235 (e) On guessing 142 × 5 The number will be near 140 × 5 = 700 Calculation:
100 40 2
5 100 × 5 40 × 5 2 × 5
500 200 10
By adding the numbers in the last row, we get 500 + 200 + 10 = 710 Therefore, 142 × 5 = 710 (f) 382 × 3 The number will be near 380 × 3 = 1140 on guessing. Calculation:
300 80 2
3 300 × 3 80 × 3 2 × 3
900 240 6
On adding the digits in the last row, we will get 900 + 240 + 6 = 1146 So, 382 × 3 = 1146 (g) 2 × 175 On guessing this number will be near 2 × 175 = 350 Calculation:
100 70 5
2 100 × 2 70 × 2 5 × 2
200 140 10
On adding the digits in the last row, we get 200 + 140 + 10 = 350 (h) 4 × 206 This number will be near 5 × 200 = 1000 on guessing. Calculation:
200 6
4 200 × 4 6 × 4
800 24
On adding the digits in the last row, we get 800 + 24 = 824 Therefore, 4 × 206 = 824

Fill My Diary

NCERT Solutions Mathematics Class 4 Chapter 6 - 8 NCERT Solutions Mathematics Class 4 Chapter 6 - 9

Later, she paid Rs 919 to the junk collectors. When she sold the junk, she got these notes and coins from Dinu.

NCERT Solutions Mathematics Class 4 Chapter 6 - 10

Question: 21

Find out how much she earned this time.

Answer:

18 March 2007 Money paid by Kiran = Rs 919 Money she got from Dinu Rs 100 × 5 = Rs 500 Rs 50 × 1 = Rs 50 Rs 20 × 9 = Rs 180 Rs 10 × 18 = Rs 180 Rs 5 × 28 = Rs 140 Total money she got from Dinu = Rs 1050 Rs 1050 – Rs 919 ___________ Total money she earned = Rs 131 = Rs 131

___________

Benefits of NCERT Solutions for Class 4 Maths Chapter 6

The NCERT Solutions for Class 4 Maths Chapter 6, "The Junk Seller," offer various benefits to students:

Practical Application of Math : The solutions help students relate mathematical concepts to real-life situations like buying, selling, and managing money.

Improves Financial Literacy : Students learn about basic financial transactions, including profit, loss, and budgeting, which enhances their understanding of money management.

Enhanced Problem-Solving Skills : By working through the chapter’s exercises, students develop logical thinking and problem-solving abilities, especially in the context of word problems.

Strengthens Mental Math : The chapter involves frequent use of addition, subtraction, and mental calculations, helping students improve their arithmetic skills.

Engaging and Relatable Learning : The use of a junk seller’s story makes learning more engaging, allowing students to connect mathematical concepts with everyday activities.

NCERT Solutions for Class 4 Maths Chapter 6 The Junk Seller FAQs

What is the junk seller concept?

Junk seller begins by purchasing some stuff from rubbish collectors. They have their own price list for which they purchase the junk. Then they later sell their stuff to a large store. They compare prices on their phone and only sells when they find a good deal.

How much money will Dinu pay for 32 kg iron?

Cost of 1 kg Iron is Rs 14. So, Dinu needs to pay Rs 448 for 32 kg iron.

How much will Kiran pay for 42 kg of newspaper?

For 1 kg newspaper Kiran pays = Rs 5 For 42 kg of newspaper she will pay = Rs 5 × 42 = Rs 210 Hence, Kiran pays Rs 210 for 42 kg of newspaper.

What is the main selling concept?

The selling concept is founded on the belief that customers will not purchase an adequate quantity of a product or service unless they are actively persuaded to do so.

How much does Kiran earn from 9 rickshaws in a day?

For 1 rickshaw she gets Rs 20 per day. So, for 9 rickshaws she will earn Rs 180.
Join 15 Million students on the app today!
Point IconLive & recorded classes available at ease
Point IconDashboard for progress tracking
Point IconMillions of practice questions at your fingertips
Download ButtonDownload Button
Banner Image
Banner Image
Free Learning Resources
Know about Physics Wallah
Physics Wallah is an Indian edtech platform that provides accessible & comprehensive learning experiences to students from Class 6th to postgraduate level. We also provide extensive NCERT solutions, sample paper, NEET, JEE Mains, BITSAT previous year papers & more such resources to students. Physics Wallah also caters to over 3.5 million registered students and over 78 lakh+ Youtube subscribers with 4.8 rating on its app.
We Stand Out because
We provide students with intensive courses with India’s qualified & experienced faculties & mentors. PW strives to make the learning experience comprehensive and accessible for students of all sections of society. We believe in empowering every single student who couldn't dream of a good career in engineering and medical field earlier.
Our Key Focus Areas
Physics Wallah's main focus is to make the learning experience as economical as possible for all students. With our affordable courses like Lakshya, Udaan and Arjuna and many others, we have been able to provide a platform for lakhs of aspirants. From providing Chemistry, Maths, Physics formula to giving e-books of eminent authors like RD Sharma, RS Aggarwal and Lakhmir Singh, PW focuses on every single student's need for preparation.
What Makes Us Different
Physics Wallah strives to develop a comprehensive pedagogical structure for students, where they get a state-of-the-art learning experience with study material and resources. Apart from catering students preparing for JEE Mains and NEET, PW also provides study material for each state board like Uttar Pradesh, Bihar, and others

Copyright © 2025 Physicswallah Limited All rights reserved.