

Step 1:
Identify the Limit Value
:
The inequality x<3 means x can take any value smaller than 3, but
not 3 itself
. On the number line, the number 3 is the
limit value
.
Step 2: Mark the limit value with an open circle:
Draw an open circle at 3. The open circle indicates that 3 is not included in the solution.
Step 3: Draw the Arrow for Smaller Values
:
Starting from the open circle at 3, draw an arrow extending to the
left
toward smaller numbers. This shows that all values less than 3 are part of the solution.
Note:
Here, the open circle represents that the limit value (in this case, 3) is
excluded
from the solution. This is because x<3 strictly means x is smaller than 3, not equal to 3.
| Symbol/Sign | Name | Indicates | Example | Explanation |
|---|---|---|---|---|
| < | Less than | The left value is smaller than the right value | 4 < 6 | 4 is less than 6 |
| - | Equal to | The left and right values are the same | 10 =10 | 10 is equal to 10 |
| ≠ | Not Equal To ≠ | The "not equal to" symbol is used to indicate that two values are not the same or do not hold equality. | 4 ≠ 7 | 4 is not equal to 7 |
| > | Greater than | The left value is larger than the right value | 12 > 8 | 12 is greater than 8 |
1: Solve for x in 5x < 25 .
Solution:
To find the value of x , divide both sides of the inequality by 5: 5x < 25 x < 25/ x < So, the solution is x<5x.Example 2: A library has two sections for books. The first section contains 120 books, and the second section contains 95 books. Which section has fewer books?
Solution:
To compare the number of books in both sections:Example 3: Ravi’s savings in May were at least ₹20 less than his savings in April. If Ravi saved ₹180 in May, determine his savings in April.
Solution:
The given statement is: "Ravi’s savings in May were at least ₹20 less than his savings in April. Let S represent Ravi’s savings in April. The inequality expression becomes: S− 20 ≥180 Add 20 to both sides of the inequality: S ≥ 200 Therefore, Ravi’s savings in April were at least ₹200.