

Solution :
Question
2.
Solution :
Question
3.
Solution :
Taking
θ
as first function and sec
2
θ
as second function and integrating by parts, we obtain
Question
4.
Solution :
Question
5.
Solution :
Question
6.
Solution :
Question
7.
Solution :
Question
8.
Solution :
Question
9.
(A) 6
(B) 0
(C) 3
(D) 4
Solution :
Let cot
θ
=
t
⇒ −cosec2
θ
d
θ
=
dt
Question
10.
A. cos x + x sin x
B. x sin x
C. x cos x
D. sin x + x cos x
Solution : Let I =
Question
11.
Solution :
Integrate the function in Exercises 12 to 22.
Question
12.
Solution :
Question
13.
Solution :
Question
14.
Solution :
Question
15.
Solution :
Let I =
It can be seen that (
x
+ 2) ≤ 0 on [−5, −2] and (
x
+ 2) ≥ 0 on [−2, 5].
Question
16.
Solution :
Let I =
It can be seen that (
x
− 5) ≤ 0 on [2, 5] and (
x
− 5) ≥ 0 on [5, 8].
Question
17.
Solution :
Question
18.
Solution :
Question
19.
Solution :
Question
20.
Solution :
Question
21.
Solution :
Let I =
As sin
2
(−
x
) = (sin (−
x
))
2
= (−sin
x
)
2
= sin
2
x
, therefore, sin
2
x
is an even function.
Question
22.
Solution :
Evaluate the integrals in Exercises 23 and 24.
Question
23.
Solution :
Let I =
As sin
7
(−
x
) = (sin (−
x
))
7
= (−sin
x
)
7
= −sin
7
x
, therefore, sin
2
x
is an odd function.
Question
24.
Solution :
Evaluate the definite integrals in Exercise 25 to 33.
Question
25.
Solution :
Question
26.
Solution :
Adding (4) and (5), we obtain
Question
27.
Solution :
Question
28.
Solution :
Let I =
It can be seen that, (
x
− 1) ≤ 0 when 0 ≤
x
≤ 1 and (
x
− 1) ≥ 0 when 1 ≤
x
≤ 4
Question
29.Show that
if
f
and
g
are defined as f (x) = f(a - x) and g(x) + g(a - x) = 4
Solution :
Question
30.
A. 0
B. 2
C. π
D. 1
Solution :
= π
Question
31.
A.
2
B.
3/4
C.
0
D.
-2
Solution :
Question
32.
Solution :
From equation (1), we obtain
Question
33.
Solution :
Prove the following (Exercise 34 to 40).
Question
34.
[Hint: Put x = a/t]
Solution :
Question
35.
Solution :
Let I =
Question
36.
Solution :
Question
37.
Solution :
Question
38.
Solution :
Question
39.
Solution :
Question
40. Evaluate
as a limit of sum.
Solution :
Given:
It is known that,
Question
41. Choose the correct answer:
is equal to:
Solution :
Therefore, option (A) is correct.
Question
42. Choose the correct answer:
is equal to:
(A)
(B) log |sin x + cos x | + C
(C) log |sin x - cos x | + C
(D)
Solution :
Therefore, option (B) is correct.
Question
43.
Choose the correct answers If f (a + b – x) = f (x), then
Solution :
Therefore, option (D) is correct.
Question
44. The value of
is:
(A) 1
(B) 0
(C) -1
(D) π/4
Solution :
Therefore, option (B) is correct.
Solution :
Question
2.
Solution :
Question
3.
Solution :
Taking
θ
as first function and sec
2
θ
as second function and integrating by parts, we obtain
Question
4.
Solution :
Question
5.
Solution :
Question
6.
Solution :
Question
7.
Solution :
Question
8.
Solution :
Question
9.
(A) 6
(B) 0
(C) 3
(D) 4
Solution :
Let cot
θ
=
t
⇒ −cosec2
θ
d
θ
=
dt
Question
10.
A. cos x + x sin x
B. x sin x
C. x cos x
D. sin x + x cos x
Solution : Let I =
Question
11.
Solution :
Integrate the function in Exercises 12 to 22.
Question
12.
Solution :
Question
13.
Solution :
Question
14.
Solution :
Question
15.
Solution :
Let I =
It can be seen that (
x
+ 2) ≤ 0 on [−5, −2] and (
x
+ 2) ≥ 0 on [−2, 5].
Question
16.
Solution :
Let I =
It can be seen that (
x
− 5) ≤ 0 on [2, 5] and (
x
− 5) ≥ 0 on [5, 8].
Question
17.
Solution :
Question
18.
Solution :
Question
19.
Solution :
Question
20.
Solution :
Question
21.
Solution :
Let I =
As sin
2
(−
x
) = (sin (−
x
))
2
= (−sin
x
)
2
= sin
2
x
, therefore, sin
2
x
is an even function.
Question
22.
Solution :
Evaluate the integrals in Exercises 23 and 24.
Question
23.
Solution :
Let I =
As sin
7
(−
x
) = (sin (−
x
))
7
= (−sin
x
)
7
= −sin
7
x
, therefore, sin
2
x
is an odd function.
Question
24.
Solution :
Evaluate the definite integrals in Exercise 25 to 33.
Question
25.
Solution :
Question
26.
Solution :
Adding (4) and (5), we obtain
Question
27.
Solution :
Question
28.
Solution :
Let I =
It can be seen that, (
x
− 1) ≤ 0 when 0 ≤
x
≤ 1 and (
x
− 1) ≥ 0 when 1 ≤
x
≤ 4
Question
29.Show that
if
f
and
g
are defined as f (x) = f(a - x) and g(x) + g(a - x) = 4
Solution :
Question
30.
A. 0
B. 2
C. π
D. 1
Solution :
= π
Question
31.
A.
2
B.
3/4
C.
0
D.
-2
Solution :
Question
32.
Solution :
From equation (1), we obtain
Question
33.
Solution :
Prove the following (Exercise 34 to 40).
Question
34.
[Hint: Put x = a/t]
Solution :
Question
35.
Solution :
Let I =
Question
36.
Solution :
Question
37.
Solution :
Question
38.
Solution :
Question
39.
Solution :
Question
40. Evaluate
as a limit of sum.
Solution :
Given:
It is known that,
Question
41. Choose the correct answer:
is equal to:
Solution :
Therefore, option (A) is correct.
Question
42. Choose the correct answer:
is equal to:
(A)
(B) log |sin x + cos x | + C
(C) log |sin x - cos x | + C
(D)
Solution :
Therefore, option (B) is correct.
Question
43.
Choose the correct answers If f (a + b – x) = f (x), then
Solution :
Therefore, option (D) is correct.
Question
44. The value of
is:
(A) 1
(B) 0
(C) -1
(D) π/4
Solution :
Therefore, option (B) is correct.
