Physics Wallah is an Indian edtech platform that provides accessible & comprehensive learning experiences to students from Class 6th to postgraduate level. We also provide extensive NCERT solutions, sample paper, NEET, JEE Mains, BITSAT previous year papers & more such resources to students. Physics Wallah also caters to over 3.5 million registered students and over 78 lakh+ Youtube subscribers with 4.8 rating on its app.
We Stand Out because
We provide students with intensive courses with India’s qualified & experienced faculties & mentors. PW strives to make the learning experience comprehensive and accessible for students of all sections of society. We believe in empowering every single student who couldn't dream of a good career in engineering and medical field earlier.
Our Key Focus Areas
Physics Wallah's main focus is to make the learning experience as economical as possible for all students. With our affordable courses like Lakshya, Udaan and Arjuna and many others, we have been able to provide a platform for lakhs of aspirants. From providing Chemistry, Maths, Physics formula to giving e-books of eminent authors like RD Sharma, RS Aggarwal and Lakhmir Singh, PW focuses on every single student's need for preparation.
What Makes Us Different
Physics Wallah strives to develop a comprehensive pedagogical structure for students, where they get a state-of-the-art learning experience with study material and resources. Apart from catering students preparing for JEE Mains and NEET, PW also provides study material for each state board like Uttar Pradesh, Bihar, and others
What are the basic concepts of statistics class 10?
The basics of statistics include the measure of central tendency and the measure of dispersion. The central tendencies are mean, median and mode and dispersions comprise variance and standard deviation. Mean is the average of the observations. Median is the central value when observations are arranged in order.
What are the question in statistics?
A statistical question is a question that can be answered by collecting data that vary.
What are the three methods of statistics class 10?
The three measures of central tendency are Mean, Median, and Mode.
RD Sharma Solutions Class 10 Maths Chapter 7 Exercise 7.2 Statistics has been provided here. Students can refer to these questions before their examinations for better preparation.
Neha Tanna15 Nov, 2024
Share
RD Sharma Solutions Class 10 Maths Chapter 7 Exercise 7.2:
In RD Sharma Class 10 Maths Chapter 7, Exercise 7.2 on Statistics, students learn about organizing, interpreting, and analyzing data effectively. This exercise focuses on calculating measures of central tendency, including mean, median, and mode, for grouped and ungrouped data. It introduces methods like the assumed mean and direct method for finding the mean, equipping students with tools to simplify complex data sets.
The exercise emphasizes practical applications, helping students understand how statistical data is analyzed in real life. Overall, Exercise 7.2 builds a foundation for understanding data trends and patterns, essential for advanced statistical concepts.
Chapter 7, Exercise 7.2 in RD Sharma’s Class 10 Maths book focuses on Statistics, specifically on measures like mean, median, and mode. These concepts are vital because they help students understand how data can be organized, analyzed, and interpreted, which is essential for making informed decisions. Mean represents an average value, median is the central point, and mode is the most frequent observation.
Understanding these measures aids in summarizing large data sets and finding patterns. This foundational knowledge is critical in various fields such as economics, social sciences, and data analysis, enhancing students’ analytical and problem-solving skills.
RD Sharma Solutions Class 10 Maths Chapter 7 Exercise 7.2 PDF
Below, we have provided the PDF for RD Sharma Solutions for Class 10 Maths Chapter 7, Exercise 7.2 on Statistics. This resource is designed to help students understand concepts like mean, median, mode, and other statistical measures with step-by-step solutions to textbook questions. These solutions are ideal for thorough practice and will assist in building a strong foundation in statistics, ensuring success in exams. Download the PDF for easy access and effective learning.
1. The number of telephone calls received at an exchange per interval for 250 successive one- minute intervals are given in the following frequency table:
No. of calls (x):
0
1
2
3
4
5
6
No. of intervals (f):
15
24
29
46
54
43
39
Compute the mean number of calls per interval.
Solution:
Let the assumed mean(A) = 3
No. of calls x
i
No. of intervals f
i
u
i
= x
i
– A = x
i
– 3
f
i
u
i
0
15
-3
-45
1
24
-2
-48
2
29
-1
-29
3
46
0
0
4
54
1
54
5
43
2
86
6
39
3
117
N = 250
Σ f
i
x
i
= 135
Mean number of calls = A + Σ f
i
x
i
/ N
= 3 + 135/250
= (750 + 135)/ 250 = 885/ 250
= 3.54
2. Five coins were simultaneously tossed 1000 times, and at each toss the number of heads was observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.
No. of heads per toss (x):
0
1
2
3
4
5
No. of tosses (f):
38
144
342
287
164
25
Solution:
Let the assumed mean(A) = 2
No. of heads per toss x
i
No of intervals f
i
u
i
= x
i
– A = x
i
– 2
f
i
u
i
0
38
-2
-76
1
144
-1
-144
2
342
0
0
3
287
1
287
4
164
2
328
5
25
3
75
N = 1000
Σ f
i
x
i
= 470
Mean number of heads per toss = A + Σ f
i
x
i
/ N
= 2 + 470/1000
= 2 + 0.470
= 2.470
3. The following table gives the number of branches and number of plants in the garden of a school.
No of branches (x):
2
3
4
5
6
No of plants (f):
49
43
57
38
13
Calculate the average number of branches per plant.
Solution:
Let the assumed mean (A) = 4
No of branches xi
No of plants f
i
u
i
= x
i
− A = x
i
− 4
f
i
u
i
2
49
-2
-98
3
43
-1
-43
4
57
0
0
5
38
1
38
6
13
2
26
N = 200
Σ f
i
x
i
= -77
Average number of branches per plant = A + Σ f
i
x
i
/ N = 4 + (-77/200)
= 4 -77/200
= (800 -77)/200
= 3.615
4. The following table gives the number of children of 150 families in a village
No of children (x):
0
1
2
3
4
5
No of families (f):
10
21
55
42
15
7
Find the average number of children per family.
Solution:
Let the assumed mean (A) = 2
No of children x
i
No of families f
i
u
i
= x
i
− A = x
i
− 2
f
i
u
i
0
10
-2
-20
1
21
-1
-21
2
55
0
0
3
42
1
42
4
15
2
30
5
7
3
21
N = 150
Σ f
i
x
i
= 52
Average number of children for family = A + Σ f
i
x
i
/ N = 2 + 52/150
= (300 +52)/150
= 352/150
= 2.35 (corrected to neat decimal)
Benefits of Solving RD Sharma Solutions Class 10 Maths Chapter 7 Exercise 7.2
Solving RD Sharma Solutions for Class 10 Maths, Chapter 7, Exercise 7.2 on Statistics offers several benefits, particularly for building foundational knowledge in statistics and enhancing problem-solving skills. Here are the key benefits:
Strengthens Conceptual Understanding
: This exercise covers key statistical concepts, such as mean, median, and mode, which are essential for understanding data analysis. Practicing these helps students grasp the underlying principles of data interpretation.
Builds Analytical Skills
: By working through various problems, students develop the ability to analyze and interpret data. This exercise includes different types of questions that encourage critical thinking, which is valuable for exams and real-life applications.
Improves Calculation Skills
: Statistics involves various calculations, and this exercise provides ample practice in performing accurate and quick calculations, especially with averages, cumulative frequency, and measures of central tendency.
Prepares for Board Exams
: The Class 10 Maths curriculum aligns with board exam requirements. Solving RD Sharma's Exercise 7.2 provides targeted practice, as the types of questions in the exercise are often similar to those seen in exams, aiding in better preparation.
Enhances Problem-Solving Techniques
: The exercise teaches students efficient problem-solving techniques. For instance, calculating the assumed mean or using mid-point in grouped data simplifies complex calculations, making it easier to tackle challenging problems.
Boosts Confidence
: Regular practice with RD Sharma solutions builds confidence. By solving a variety of problems, students become familiar with different question patterns, helping reduce anxiety and improve their overall performance in the subject.
Talk to a counsellorHave doubts? Our support team will be happy to assist you!
