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RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 Operations on Algebraic Expressions

Here, we have provided RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2. Students can view these RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 before exams for better understanding.
authorImageAnanya Gupta31 Jul, 2024
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RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2: RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 have been prepared by subject experts of Physics Wallah. These solutions provide comprehensive, step-by-step explanations for solving complex algebraic expressions.

With detailed guidance students can learn to manage multiplication and division of algebraic terms, as well as handle expressions involving brackets with confidence. The expert insights ensure that students grasp the concepts effectively, improving their problem-solving skills and reinforcing their understanding of algebraic operations.

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RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 Operations on Algebraic Expressions Overview

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 provide a detailed overview of operations involving algebraic expressions with brackets. In this exercise, students work on expanding and simplifying expressions where algebraic terms are enclosed within parentheses. The problems are designed to enhance students skills in applying the distributive property, combining like terms, and managing complex algebraic structures. Through this exercise students learn to handle multi-step problems and perform operations such as multiplication and division on algebraic expressions. The solutions provide clear, step-by-step explanations to help students understand how to approach and solve these types of problems. This exercise is important for developing a solid foundation in algebra preparing students for more advanced topics in mathematics.

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 PDF

The PDF link for RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 is available below. By referring to this PDF students can gain a clearer understanding of how to simplify and expand algebraic expressions, reinforcing their skills in this area. This will help improve their problem-solving abilities and overall performance in mathematics.

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 PDF

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.1 (Exercise 6B)

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 are available below. This resource provides detailed solutions and explanations for problems related to operations on algebraic expressions.

Find each the following products:

(Question 1) (5x + 7) × (3x + 4)

Solution:

= (5x × 3x) + (7 × 3x) + (5x × 4) + (7 × 4) = 15x 2 + 21x + 20x + 28 = 15x 2 + 41x + 28

(Question 2) (4x + 9) × (x – 6)

Solution:

= (4x × x) + (9 × x) – (4x × 6) – (9 × 6) = 4x 2 + 9x – 24x – 54 = 4x 2 – 15x – 54

(Question 3) (2x + 5) × (4x – 3)

Solution:

= (2x × 4x) + (5 × 4x) – (2x × 3) – (5 × 3) = 8x 2 + 20x – 6x – 15 = 8x 2 + 14x – 15

(Question 4) (3y – 8) × (2m – 3n)

Solution:

= (3y × 2m) – (8 × 2m) – (3y × 3n) + (8 × 3n) = 6ym – 16m – 9yn + 24n

(Question 5) (7x + 2y) × (x + 4y)

Solution:

= (7x × x) + (2y × x) + (7x × 4y) + (2y × 4y) = 7x 2 + 2xy + 28xy + 8y 2 = 7x 2 + 30xy + 8y 2

(Question 6) (9x + 5y) × (4x × 3y)

Solution:

= (9x × 4x) + (5y × 4x) + (9x × 3y) + (5y × 3y) = 36x 2 + 20xy + 27xy + 15y 2

(Question 7) (3m – 4n) × (2m – 3n)

Solution:

= (3m × 2m) – (4n × 2m) – (3m × 3n) + (4n × 3n) = 6m 2 – 8mn – 9mn + 12n 2 = 6m 2 – 17mn + 12n 2

(Question 8) (x 2 – a 2 ) × (x – a)

Solution:

= (x 2 × x) – (a 2 × x) – (x 2 × a) + (a 2 × a) = x 3 + a 2 x – ax 2 + a 3

(Question 9) (x 2 – y 2 ) × (x + 2y)

Solution:

= (x 2 × x) – (y 2 × x) + (x 2 × 2y) – (y 2 × y) = x 3 – xy 2 + 2x 2 y – y 3

(Question 10) (3p 2 + q 2 ) × (2p 2 – 3q 2 )

Solution:

= (3p 2 × 2p 2 ) + (q 2 × 2p 2 ) – (3p 2 × 3q 2 ) – (q 2 × 3q 2 ) = 6p 4 + 2p 2 q 2 – 9p 2 q 2 – 3q 4 = 6p 4 – 7p 2 q 2 – 3q 4

(Question 11) (2x 2 – 5y 2 ) × (x 2 + 3y 2 )

Solution:

= (2x 2 × x 2 ) – (5y 2 × x 2 ) + (2x 2 × 3y 2 ) – (5y 2 × 3y 2 ) = 2x 4 – 5x 2 y 2 + 6x 2 y 2 – 15y 4 = 2x 4 + x 2 y 2 – 15y 4

(Question 12) (x 3 – y 3 ) × (x 2 + y 2 )

Solution:

= (x 3 × x 2 ) – (y 3 × x 2 ) + (x 3 × y 2 ) – (y 3 × y 2 ) = x 5 – x 2 y 3 + x 3 y 2 – y 5

(Question 13) (x 4 + y 4 ) × (x 2 – y 2 )

Solution:

= (x 4 × x 2 ) + (y 4 × x 2 ) – (x 4 × y 2 ) – (y 4 × y 2 ) = x 6 + x 2 y 4 – x 4 y 2 – y 6

Find each of the following products:

(Question 15) (x 2 – 3x + 7) × (2x + 3)

Solution:

= (x 2 × 2x) – (3x × 2x) + (7 × 2x) + (x 2 × 3) – (3x × 3) + (7 × 3) = 2x 3 – 6x 2 + 14x + 3x 2 – 9x + 21 = 2x 3 – 3x 2 + 5x + 21

(Question 16) (3x 2 + 5x – 9) × (3x – 5)

Solution:

= (3x 2 × 3x) + (5x × 3x) – (9 × 3x) – (3x 2 × 5) – (5x × 5) + (9 × 5) = 9x 3 + 15x 2 – 27x – 15x 2 – 25x + 45 = 9x 3 – 52x + 45

(Question 17) (x 2 – xy + y 2 ) × (x + y)

Solution:

= (x 2 × x) – (xy × x) + (y 2 × x) + (x 2 × y) – (xy × y) + (y 2 × y) = x 3 – x 2 y + y 2 x + x 2 y – xy 2 + y 3 = (x 3 + y 3 )

(Question 18) (x 2 + xy + y 2 ) × (x – y)

Solution:

= (x 2 × x) + (xy × x) + (y 2 × x) – (x 2 × y) – (xy × y) – (y 2 × y) = x 3 + x 2 y + xy 2 – x 2 y – xy 2 – y 3 = (x 3 – y 3 )

(Question 19) (x 3 – 2x 2 + 5) × (4x – 1)

Solution:

= (x 3 × 4x) – (2x 2 × 4x) + (5 × 4x) – x 3 + 2x 2 – 5 = 4x 4 – 8x 3 + 20x – x 3 + 2x 2 – 5 = 4x 4 – 9x 3 + 2x 2 + 20x – 5

(Question 20) (9x 2 – x + 15) × (x 2 – 3)

Solution:

= (9x 2 × x 2 ) – (x × x 2 ) + (15 × x 2 ) – (9x 2 × 3) + 3x – 45 = 9x 4 – x 3 + 15x 2 – 27x 2 + 3x – 45 = 9x 4 – x 3 – 12x 2 + 3x – 45

(Question 21) (x 2 – 5x + 8) × (x 2 + 2)

Solution:

= (x 2 × x 2 ) – (5x × x 2 ) + 8x 2 + 2x 2 – 10x + 16 = x 4 – 5x 3 + 10x 2 – 10x + 16

(Question 22) (x 3 – 5x 2 + 3x + 1) × (x 2 – 3)

Solution:

= (x 3 × x 2 ) – (5x 2 × x 2 ) + (3x × x 2 ) + x 2 – 3x 3 + 15x 2 – 9x – 3 = x 5 – 5x 4 + 3x 3 + x 2 – 3x 3 + 15x 2 – 9x – 3 = x 5 – 5x 4 + 16x 2 – 9x – 3

(Question 23) (3x + 2y – 4) × (x – y + 2)

Solution:

= 3x 2 + 2xy – 4x – 3xy – 2y 2 + 4y + 6x + 4y – 8 = 3x 2 – xy + 2x – 2y 2 + 8y – 8

(Question 24) (x 2 – 5x + 8) × (x 2 + 2x – 3)

Solution:

= x 4 – 5x 3 + 8x 2 + 2x 3 – 10x 2 + 16x – 3x 2 + 15x – 24 = x 4 – 3x 3 – 5x 2 + 31x – 24

(Question 25) (2x 2 + 3x – 7) × (3x 2 – 5x + 4)

Solution:

= 6x 4 + 9x 3 – 21x 2 – 10x 3 – 15x 2 + 35x + 8x 2 + 12x – 28 = 6x 4 – x 3 – 28x 2 + 47x – 28

(Question 26) (9x 2 – x + 15) × (x 2 – x – 1)

Solution:

= 9x 4 – x 3 + 15x 2 – 9x 3 + x 2 – 15x – 9x 2 + x – 15 = 9x 4 – 10x 3 + 7x 2 – 14x – 15

Benefits of RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2

  • In-Depth Understanding : These solutions provide clear step-by-step explanations of algebraic operations, helping students grasp complex concepts such as simplifying and expanding expressions with brackets.
  • Enhanced Problem-Solving Skills : By working through the detailed solutions students learn effective techniques for handling various algebraic expressions, which boosts their problem-solving skills and confidence.
  • Clarification of Doubts : The solutions address common errors and misconceptions, allowing students to clear any doubts and gain a solid understanding of algebraic principles.
  • Improved Exam Preparation : Practicing with these solutions helps students become familiar with the types of problems they may encounter in exams, leading to better preparation and performance.
  • Efficient Learning : The structured approach of the solutions helps students learn efficiently, as they can follow logical steps to solve problems and reinforce their learning through practice.

RS Aggarwal Solutions for Class 8 Maths Chapter 6 Exercise 6.2 FAQs

What does Exercise 6.2 cover in RS Aggarwal Class 8 Maths Chapter 6?

Exercise 6.2 focuses on performing algebraic operations involving expressions with brackets. It includes problems on simplifying complex expressions, expanding brackets, and combining like terms.

How can the solutions in Exercise 6.2 help with understanding algebraic expressions?

The solutions provide step-by-step explanations for each problem, helping students understand the process of expanding and simplifying algebraic expressions.

How can students use these solutions to improve their problem-solving skills?

By studying the detailed solutions, students can learn how to approach and solve similar problems.

What should students do if they find a problem challenging?

Students should refer to the solutions for detailed explanations and work through similar problems to build their skills. If they still have difficulties, they may consider additional practice or seek help from teachers or tutors.
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