
RS Aggarwal Solutions for Class 10 Maths Chapter 9 Exercise 9.2: RS Aggarwal Solutions for Class 10 Maths Chapter 9 Exercise 9.2 provide detailed explanations to help students solve problems related to cumulative frequency distribution and drawing ogive curves.
By working through these exercises, students can improve their ability to create cumulative frequency tables and graphs, which are important for analyzing data. These solutions are a great resource for students to practice and prepare for their math exams effectively.
⇒ N/2 = 150/2 = 75
The cumulative frequency just greater than (N/2 = ) 75 is 120, so
the corresponding median class is 200 - 300 and accordingly we
get Cf = 72(cumulative frequency before the median class).
Now, since median class is 200 - 300.
∴ l = 200, h = 100, f = 48, N/2 = 75 and Cf = 72
Median is given by,
Median = l + (
N
2
− Cf
f
) × h
⇒ Median = 200 + (
75−72
48 ) × 100
= 200 + 6.25
= 206.25
Thus, median wage is Rs. 206.25.
To find median, Assume
Σfi = N = Sum of frequencies,
l = lower boundary of the median class,
f = frequency of median class
and Cf = cumulative frequency
Lets form a table.
Now, since median class is 15 - 20.
∴ l = 15, h = 5, f = 15, N/2 = 24.5 and Cf = 11
Median is given by,
Median = l + (
N
2
− Cf
f
) × h
⇒ Median = 15 + (
24.5−11
15 ) × 5
= 15 + 4.5
= 19.5
Thus, median is 19.5.
To find median, Assume
Σfi = N = Sum of frequencies,
h = length of median class,
l = lower boundary of the median class,
f = frequency of median class
and Cf = cumulative frequency
Lets form a table.
∴ l = 125, h = 20, f = 20, N/2 = 33.5 and Cf = 22
Median is given by,
Median = l + (
N
2
− Cf
f
) × h
⇒ Median = 125 + (
33.5−22
20 ) × 20
= 125 + 11.5
= 136.5
Thus, median is 136.5.
To find median, Assume
Σfi = N = Sum of frequencies,
h = length of median class,
l = lower boundary of the median class,
f = frequency of median class
and Cf = cumulative frequency
Median(given) = 24, Assume
Σfi = N = Sum of frequencies,
h = length of median class,
l = lower boundary of the median class,
f = frequency of median class
and Cf = cumulative frequency
Lets form a table, where x is the unknown frequency.
⇒ (4)(2x) = 10x – 50
⇒ 8x = 10x – 50
⇒ 10x – 8x = 50
⇒ 2x = 50
⇒ x = 25
Thus, the unknown frequency is 25.
