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Refraction on Curved Surfaces

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Refraction on Curved Surfaces

Optics of Class 12

Refraction on Curved Surfaces

Consider a spherical surface of radius R separating the two media 1 and 2 as shown in figure. A point object O is placed on the principal axis and we have to find the position of its image I from the pole P of the boundary surface.

Using geometry, we have

i = α + γ (i)

andγ = r + β (ii)

From Snell’s law

μ 1 sin i = μ 2 sin r

Refraction on Curved Surfaces

Applying paraxial approximation : sin i ≈ i and sin r  ≈ r

Thusμ 1 i = μ 2 r

Eliminating i and r from equation (i) and (ii), we get

μ 1 α + μ 2 β = (μ 2 - μ 1

Since α ≈ AP/x ;β = AP/y ;γ = AP/R

Refraction on Curved Surfaces

Applying Cartesian Sign Convention the above equation may be obtained from the general formula given as:

Refraction on Curved Surfaces (15.20)

whereu is the position of the object from the pole

v is the position of the image from the pole

R is the radius of curvature of the surface

μ 1 is the medium which comes before the boundary, and

μ 2 is the medium which comes after the boundary if we move in the direction of the incident light.

Lateral Magnification for Refracting Spherical Surface

Magnification is defined as

m = height of image/height of object

Using Cartesian convention,

m = -a'b'/ab

From Snell’s law, we know that

μ 1 sin i = μ 2 sin r

Applying paraxial ray assumption

sin i ≈ i   and sin r ≈ r

Thus μ 1 i = μ 2 r

or r/i = μ 1 2

Alsoab = ui        and      a′b′ = vr

Thusm  = -vr/ui

Refraction on Curved Surfaces

Substituting the value of (r/i) , we get

m = Refraction on Curved Surfaces (15.21)

Refraction on Curved Surfaces

Example 15.13

A parallel beam of light travelling in water (μ = 4/3 ) is refracted through a spherical air bubble of the final image formed.

(a)Find the position of the final image formed.

(b) Draw the ray diagram

Refraction on Curved Surfaces

Solution

(a)Refraction at the first surface:

u = -∞ ; μ 1 = 4/3 ;  μ 2 = 1;  R = +R

Using the equation (15.20)

Refraction on Curved Surfaces

orv = -3R

The image is at a distance 3R from P 1 in water.

Refraction at the second surface.

μ 2 = 4/3 ;  μ 1 = 1; u = -(3R + 2R) = -5R;   R = -R

Refraction on Curved Surfaces

or v = -5R/3

The final image is at a distance 5R/2 from P 2 towards left, as shown in the figure.

(b)

Refraction on Curved Surfaces

Example 15.14

For the optical arrangement shown in the figure.

Solution

According to Cartesian sign convention

u = -40cm,   R = -20 cm

μ = 1,   μ 2 = 1.33

Applying equation (15.2), we get

Refraction on Curved Surfaces

Refraction on Curved Surfaces

After solving,  v = -32 cm.

The magnification is  m = Refraction on Curved Surfaces

Refraction on Curved Surfaces orh 2 = 0.6 cm

The positive sign shows that the image is erect.

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