Jul 04, 2022, 16:45 IST
Speed of a body is a measure of rate of motion of the body . It is equal to distance travelled by the body in unit time.
It is measured in m/s or cm/s or km/h.
Velocity of a body is defined as the distance travelled by the body in a given direction in unit time. Thus,
Q1. Calculate the speed of z body in m/s and km/hr if it travles 30 kms in 6 hrs
Solution: Distance (s) = 30 km
Time (t) = 6 hrs
speed (in km/hr) = Total distance/Total time = 30/6 = 5 km/hr
30 km = 30 x 1000m = 30,000 m
6 hrs = 6 x 60 x 60 sec
speed (im m/s) = (30 x 1000)/ (4 x 60 x 60) = 1.6 m/s
Q2. During first half of a journey by a body it travel with a speed of 60 km/hr and in the next half it travels with a speed of 10 km/hr. Calculate the average speed of the whole journey.
Solution: Speed during first half (v1) = 60 km/hr
Speed during second half (v 2 ) = 10 km/hr
Average speed = (v1+v2)/2 = (60+10)/2 = 70/2 = 35
Average speed by an object (body) = 35 km/hr.
Q3. A car travels 30 km in first hour, 60 km in second hour and 10 km in third hour. Calculate the average speed of the train.
Solution: Speed in Ist hour = 30 km/hr
Distance travelled during 1st hr = 1×30= 30 km
Speed in 2nd hour = 40 km/hr
Distance travelled during 2nd hr = 1×60= 60 km
Speed in 3rd hour = 30 km/hr
Distance travelled during 3rd hr = 1×10= 10 km
Average speed = Total distance travelled/Total time taken
= (30+60+10)/3 = 100/3 = 33.3 km/hr
Acceleration of a body is defined as the rate of change of velocity of the body with time.
Unit of acceleration = m/s 2 , cm/s 2 , km/h 2
Q1. A car speed increases from 30 km/hr to 50 km/hr in 4 sec. Calculate the acceleration of car.
Solution: u = 30km/hr = (30×5)/18 = 25/3 = 8.33 m/s
v = 50 km/hr = (50×5)/18 = 150/9 = 13.8 m/s
t = 4 sec
a = (v-u)/t = (13.8 - 8.33)/5
= 5.47/5 = 1.094 ms-2
Q2. A car travelling with a speed of 30 km/hr comes into rest in 0.5 hrs. What will be the value of its retardation?
Solution: v = 0 km/hr
u = 30 km/hr
t = 0.5 hrs
Retardation, a’ = (v-u)/t = (0-30)/0.5
= -300/5 = -60 km hr-2
In physics, equations of motion are equation that describe the behavior of the physical system in terms of its motion as a function of time. Specifically, equation of motion define the behavior of the physical system as a set of mathematical functions depending on the variables.
Physics Wallah team and faculty members prepared all required Physics Formula for physics class 9 of chapter Motion in pdf sheet. NCERT text book is highly recommend to class 9 student do solve numerical and use as reference NCERT solutions for class 9 Science. Students can also visit CBSE class 9 Physics Notes as it will be very helpful for them to understand the concepts.
Download Free Pdf sheet of all formulas of Chapter - Motion Class 9 below.