

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.1: NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Exercise 3.1 focuses on solving linear equations with two variables using different methods such as substitution and elimination.
The exercise introduces students to the concept of a pair of linear equations, which are equations of the form Ax + By = C and Dx + Ey = F, where A, B, C, D, E, and F are constants. Students learn how to solve these equations by substitution, elimination, and graphically. The exercise emphasizes finding the values of the two variables that satisfy both equations simultaneously. Through this practice, students understand the geometric interpretation of solutions and how the lines represented by the equations intersect. The exercise provides a strong foundation for solving real-world problems involving two variables and helps build proficiency in algebraic methods.NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.1 PDF
Answer:
Let the present age of Aftab and his daughter be x and y respectively. Seven years ago, Age of Aftab = x – 7 and Age of his daughter = y – 7 According to the given condition,
Thus, the given conditions can be algebraically represented as:
x – 7y = –42
And x – 3y = 6
The graphical representation is as follows:
2. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and graphically.
Answer:<.
Let the cost of a bat and a ball be Rs x and Rs y respectively. The given conditions can be algebraically represented as: 3x + 6y = 3900 x + 2y = 1300
Three solutions of this equation can be written in a table as follows:
| x | 3900 | 1300 | -1300 |
| y | -1300 | 0 | 1300 |
Three solutions of this equation can be written in a table as follows:
| x | 3900 | 1300 | -1300 |
| y | -1300 | 0 | 1300 |
3. The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.
Answer:
Let cost of 1 kg of apples = Rs x and let cost of 1 kg of grapes= Rs y According to given conditions, we have 2x + y = 160… (1) 4x + 2y = 300 ⇒ 2x + y = 150… (2) So, we have equations (1) and (2), 2x + y = 160 and 2x + y = 150 which represent given situation algebraically. For equation 2x + y = 160, we have following points which lie on the line
We plot the points for both of the equations and it is the graphical representation of the given situation.
