

NCERT Solutions for Class 12 Maths Chapter 11 Miscellaneous Exercise
Solve The Following Questions of NCERT Solutions for Class 12 Maths Chapter 11 Exercise 11.1
Question 1.If a line makes angles 90°, 135°, 45° with x ,y and z axes respectively, find its direction cosines. Solution : A-line makes 90°, 135°, 45°with x, y and z axes respectively. Therefore, Direction cosines of the line are cos 90°, cos135°, and cos45° ⇒ Direction cosines of the line are 0,-1/√2 and 1/√2NCERT Solutions for Class 12 Maths Chapter 11 Exercise 11.2
Question 2.Find the direction cosines of a line which makes equal angles with the co-ordinate axes. Solution : Let the direction cosines of the line make an angle α with each of the coordinate axes. ∴ l = cos α , m = cos α , n = cos α
Thus, the direction cosines of the line, which is equally inclined to the coordinate axes, are
NCERT Solutions for Class 12 Maths Chapter 11 Exercise 11.3
Question 3.If a line has direction ratios −18, 12, −4, then what are its direction cosines? Solution : The direction ratios of the lines are -18, 12, -4 Direction cosines of the lines are
Hence, direction cosine of line are -9/11, 6/11 -2/11.
Question
4.Show that the points (2, 3, 4), (−1, −2, 1), (5, 8, 7) are collinear.
Solution :
The given points are A (2, 3, 4), B(−1, −2, 1) and C (5, 8, 7)
It is known that the direction ratios of line joining the points, (
x
1
,
y
1
,
z
1
) and (
x
2
,
y
2
,
z
2
), are given by,
x
2
−
x
1
,
y
2
−
y
1
, and
z
2
−
z
1
.
The direction ratios of AB are (−1 − 2), (−2 − 3), and (1 − 4) i.e., −3, −5, and −3.
The direction ratios of BC are (5 − (− 1)), (8 − (− 2)), and (7 − 1) i.e., 6, 10, and 6.
It can be seen that the direction ratios of BC are −2 times that of AB i.e., they are proportional.
Therefore, AB is parallel to BC. Since point B is common to both AB and BC, points A, B, and C are collinear.
Question
5.Find the direction cosines of the sides of the triangle whose vertices are (3, 5, − 4), (− 1, 1, 2) and (− 5, − 5, − 2)
Solution :
The vertices of ΔABC are A (3, 5, −4), B (−1, 1, 2), and C (−5, −5, −2).
The direction ratios of side AB are (−1 − 3), (1 − 5), and (2 − (−4)) i.e., −4, −4, and 6.
Therefore, the direction cosines of AB are
The direction ratios of BC are (−5 − (−1)), (−5 − 1), and (−2 − 2) i.e., −4, −6, and −4.
Therefore, the direction cosines of BC are
The direction ratios of CA are 3−(−5), 5−(−5) and −4−(−2) i.e. 8, 10 and -2.
Therefore the direction cosines of CA are
