CSIR NET Mathematical Science Exam 2024, Eligibility, Syllabus, Cut Off
CSIR NET Mathematical Science Exam 2024 Notification has been released by NTA on its official website @csirnet.nta.nic.in. Check here for the CSIR NET Mathematical Science Exam 2024, Eligibility, Syllabus, etc.
Dr. Kar30 Dec, 2024
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CSIR NET Mathematical Science Exam 2024: The CSIR NET Mathematical Science Exam 2024 notification has been released on 9th December 2024. This prestigious national-level exam, conducted by the Council of Scientific and Industrial Research (CSIR), assesses candidates' understanding and knowledge of Mathematical Science subjects. It is essential for those aiming for careers in research or teaching at Indian universities and research institutes. Candidates can check here for detailed information on eligibility criteria, exam structure, and syllabus for the CSIR NET 2024 Mathematical Sciences Exam.
CSIR NET Mathematical Science Exam 2024
The notification for the CSIR NET 2024 December session has been released on 9th December 2024. This competitive exam is designed to determine the eligibility of candidates for the posts of Assistant Professor or Junior Research Fellowship (JRF) in Mathematical Sciences at Indian universities and research institutes. The notification includes details about the application process, eligibility criteria, exam pattern, and syllabus for the CSIR NET Mathematical Sciences Exam 2024.CSIR NET Mathematical Science Exam 2024 Overview
The National Testing Agency (NTA) conducts the CSIR NET Mathematical Science Exam twice a year at the national level. The exam date for 2024 has been announced. The minimum age limit for applicants is 28 years, with age relaxation available for specified categories. There is no maximum age limit for applicants applying for lectureship. Here is an overview of the CSIR NET Mathematical Science Exam 2024.| CSIR NET Mathematical Science 2024 Overview | |
| Exam Name | CSIR NET 2024 December |
| Exam Conducting Body | National Testing Agency |
| Full Exam Name | Council of Scientific and Industrial Research National Eligibility Test |
| Frequency of Exam | Twice a year |
| Application Mode | Online |
| Exam Mode | Computer-Based Test (Online) |
| Subjects Name |
|
| Exam Duration | 180 minutes |
| Total Marks | 200 marks |
| Language/Medium of Exam | English and Hindi |
| Official Website | csirnet.nta.nic.in |
CSIR NET Mathematical Science Exam 2024 Eligibility Criteria
To apply for the CSIR NET Mathematical Science Exam 2024, candidates must meet certain eligibility criteria. These criteria ensure that applicants have the necessary educational qualifications to pursue a career in research or teaching in Mathematical Sciences. Below are the detailed CSIR NET Eligibility Criteria requirements for the exam:- To be eligible for the CSIR NET Mathematical Science Exam 2024, candidates must have a Master's degree in Mathematical Sciences or related disciplines from a recognized university.
- A Master of Science (M.Sc.) degree or its equivalent in Mathematics, Statistics, or a related subject with Mathematics or Statistics as a significant component. You should have secured a minimum of 55% marks (50% for candidates belonging to the Scheduled Caste (SC), Scheduled Tribe (ST), or Other Backward Class (OBC) categories).
- Alternatively, you can have a Bachelor of Technology (B.Tech.) degree in Engineering with a minimum of 55% marks (50% for SC, ST, and OBC candidates).
- Those enrolled for M.Sc. or who have completed 10+2+3 years of the qualifying examination as of the closing date of online application submission can apply under the "Result Awaited" category.
- B.Sc. (Hons.) or equivalent degree holders or students enrolled in Integrated M.Sc.-Ph.D. programs with the required percentage of marks are also eligible to apply. However, candidates with a Bachelor's degree will only be eligible for Junior Research Fellowship (JRF) and not for Lectureship (LS)/Assistant Professor.
- Final year/result awaited candidates in B.E./B.S./B.Tech./B.Pharma/MBBS are eligible to apply for fellowship opportunities but not for Lectureship/Assistant Professor. In contrast, B.Sc. (Hons.) final year/result awaited candidates are not eligible to apply.
CSIR NET Mathematical Science Exam 2024 Age Limit
CSIR NET Mathematical Science Exam 2024 sets the upper age limit for Junior Research Fellowship (JRF) candidates at 28 years. However, there are relaxations for certain categories. SC/ST, Third gender, PwD, and female candidates can have a 5-year relaxation, while OBC (NCL) candidates get a 3-year relaxation. There is no age limit for Lectureship/Assistant Professor. Here is an overview of the CSIR NET Mathematical Science Exam 2024 Age Limit.| CSIR NET Mathematical Science Exam 2024 Age Limit | |
| Posts | Upper Age Limit |
| JRF |
|
| Lectureship/Assistant Professor |
No upper age limit |
CSIR NET Mathematical Science Exam Pattern 2024
CSIR NET Mathematical Sciences Exam 2024 is divided into three sections. Each section contains multiple-choice questions, and candidates must attempt a specific number of questions. Below is the detailed exam pattern for the CSIR NET Mathematical Sciences Exam 2024:| CSIR NET Mathematical Science Exam Pattern 2024 | ||||
| Part | Total Questions | Maximum to Attempt | Marks for Correct Answer | Marks for Incorrect Answer (Negative Marking) |
| A | 20 | 15 | 2 | -0.5 |
| B | 40 | 25 | 3 | -0.75 |
| C | 60 | 20 | 4.75 | 0 |
| Total | 120 | 60 | 200 | - |
CSIR NET Mathematical Science Syllabus 2024
The CSIR NET Mathematical Science Syllabus 2024 covers a comprehensive range of topics to evaluate the knowledge and understanding of aspirants in the field of Mathematical Sciences. The CSIR NET 2024 Syllabus for Mathematical Sciences is categorized into multiple sections. To check CSIR NET Mathematical Sciences Syllabus 2024, candidates can download the PDF by clicking on the given link.| CSIR NET Exam 2024 | |
| CSIR NET Chemical Science Exam 2024 | CSIR NET Life Science Exam 2024 |
| CSIR NET Physical Science Exam 2024 | CSIR NET Mathematical Science Exam 2024 |
CSIR NET Mathematical Science Answer Key 2024
The CSIR NET Mathematical Science Answer Key 2024 will be released by the National Testing Agency (NTA) shortly after the examination. Candidates can access the answer key on the official website @csirnet.nta.ac.in. It will contain the correct answers to all questions asked in the exam, enabling candidates to estimate their scores before the results are announced. The NTA will initially release a provisional answer key, allowing candidates to raise objections if they find discrepancies. After reviewing the challenges submitted, the final answer key will be published. Stay tuned to the official website for updates on the release date and objection submission process.CSIR NET Mathematical Science Cut Off 2024
The National Testing Agency (NTA) will release the CSIR NET Mathematical Sciences Cut Off 2024 on its official website, which can be accessed at csirnet.nta.nic.in. CSIR NET Cut Off marks play an important role in determining the selection status of candidates appearing for the CSIR NET Mathematical Sciences examination. Candidates scoring marks above the specified cutoff will be considered eligible for Junior Research Fellowship (JRF) and Assistant Professor posts. The CSIR NET Mathematical Science Cut Off 2024 will be determined using a combination of the normalization method, raw score, and overall percentile. Candidates can check the CSIR NET Mathematical Science Cut Off 2024 on the official website after the CSIR NET 2024 Result are announced.CSIR NET Mathematical Science Exam 2024 Normalization Procedure
The CSIR NET Mathematical Science Exam 2024 will follow a normalization procedure to convert the raw marks obtained by candidates from different shifts/sessions into NTA Scores or percentiles. This process ensures fairness and accurate comparison of performances across various shifts. The normalization procedure involves the following steps:- Conversion of raw marks to NTA Scores (percentiles) : The raw marks obtained by each candidate in their respective shifts/sessions will be converted to a common NTA Score or percentile. This step helps in standardizing the scores across different shifts.
- Amalgamation of NTA Scores for further processing : After converting the raw marks to NTA Scores, these scores will be combined for all shifts/sessions. This step allows for a comprehensive evaluation of candidates' performances across all shifts.
- Determination of eligibility cutoffs : The NTA Scores (percentiles) from all shifts/sessions will be used to determine the eligibility cutoffs for each category. The lowest percentile from all shifts will be considered as the cutoff for that category for all candidates across all shifts/sessions.
CSIR NET Mathematical Science Exam 2024 FAQs
What are the eligibility criteria for the CSIR NET Mathematical Science Exam 2024?
Candidates must have a Master's degree in Mathematical Sciences or related disciplines with a minimum of 55% marks (50% for SC/ST/OBC candidates).
Where can I download the syllabus for CSIR NET Mathematical Sciences Exam 2024?
The syllabus for the CSIR NET Mathematical Sciences Exam can be downloaded from the official website or accessed through the provided PDF link.
What is the age limit for Junior Research Fellowship (JRF) candidates in the CSIR NET Mathematical Science Exam 2024?
The maximum age limit for JRF candidates is 28 years, with relaxations available for certain categories.
What is the procedure for challenging answers in the CSIR NET Mathematical Science Exam 2024?
The provisional answer key is displayed on the official website, allowing candidates to challenge any answers they believe are incorrect by paying a non-refundable processing fee per challenged question.
What is the duration of the CSIR NET Mathematical Science Exam 2024?
The CSIR NET Mathematical Science Exam 2024 duration is 180 minutes.
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