Important Questions for Class 8 Maths Chapter 3: The important questions for Maths Class 8 Chapter 3 Understanding Quadrilaterals are very useful for students in their exam preparation. These questions cover essential topics such as the properties of different types of quadrilaterals, polygons, the angle sum property, and how to identify and classify shapes based on their sides and angles.
By solving these questions students can understand the concepts more clearly and practice applying them to solve problems. Regular practice also helps students improve their accuracy and speed, making it easier for them to tackle exam questions. These questions also highlight important areas where students should focus helping them prepare effectively and perform well in their exams.Important Questions for Class 8 Maths Chapter 3 PDF
Q.1: A quadrilateral has three acute angles, each measure 80°. What is the measure of the fourth angle?
Solution:
Let x be the measure of the fourth angle of a quadrilateral. Sum of the four angles of a quadrilateral = 360° 80° + 80° + 80° + x = 360° x = 360° – (80° + 80° + 80°) x = 360° – 240° x = 120° Hence, the fourth angle is 120°.Q,2: In a quadrilateral ABCD, the measure of the three angles A, B and C of the quadrilateral is 110°, 70° and 80°, respectively. Find the measure of the fourth angle.
Solution: Let,
∠A = 110° ∠B = 70° ∠C = 80° ∠D = x We know that the sum of all internal angles of quadrilateral ABCD is 360°. ∠A + ∠B+ ∠C+∠D = 360° 110° + 70° + 80° + x = 360° 260° + x = 360° x = 360° – 260° x = 100° Therefore, the fourth angle is 100°.Q.3: In a quadrilateral ABCD, ∠D is equal to 150° and ∠A = ∠B = ∠C. Find ∠A, ∠B and ∠C.
Solution: Given,
∠D = 150° Let ∠A = ∠B = ∠C = x By angle sum property of quadrilateral, ∠A + ∠B + ∠C + ∠D = 360° x + x +x+∠D = 360° 3x+∠D = 360° 3x = 360° – ∠D 30 = 360° – 150° 3x = 210° x = 70° Hence, ∠A = ∠B = ∠C = 70°.Q.4: The angles of a quadrilateral are in the ratio of 1 : 2 : 3 : 4. What is the measure of the four angles?
Solution: Given,
The ratio of the angles of quadrilaterals = 1 : 2 : 3 : 4 Let the four angles of the quadrilateral be x, 2x, 3x, and 4x respectively. The sum of four angles of a quadrilateral is 360°. Therefore, x + 2x + 3x + 4x = 360° 10x = 360° x = 360°/10 x = 36° Therefore, First angle = x = 36° Second angle = 2x = 2 × 36 = 72° Third angle = 3x = 3 × 36 = 108° Fourth angle = 4x = 4 × 36 = 144° Hence, the measure of four angles is 36°, 72°, 108° and 144°.Q.5. Choose the quadrilaterals with their properties
Quadrilaterals |
Properties |
(a) Parallelogram (b) Rhombus (c) Rectangle (d) Square (e) Kite |
(i) Opposite sides equal (ii) Opposite angles equal (iii) diagonals bisect each other (iv) diagonals are perpendicular to each other (v) each angle is a right angle (vi) diagonals are equal (vii) one of the diagonal bisects the other |
Solution:
a) Parallelogram-
(i) Opposite sides equal
(ii) Opposite angles equal
(iii) diagonals bisect each other
(b) Rhombus-
(i) Opposite sides equal
(ii) Opposite angles equal
(iii) diagonals bisect each other
(iv) diagonals are perpendicular to each
other
(c) Rectangle-
(i) Opposite sides equal
(ii) Opposite angles equal
(iii) diagonals bisect each other
(v) each angle is a right angle
(vi) diagonals are equal
(d) Square
(i) Opposite sides equal
(ii) Opposite angles equal
(iii) diagonals bisect each other
(iv) diagonals are perpendicular to each Other
(v) each angle is a right angle
(vi) diagonals are equal
(e) Kite
(iv) diagonals are perpendicular to each other
(vi) diagonals are equal
Q.6: Length and breadth of a rectangular wire are 9 cm and 7 cm respectively. If the wire is bent into a square, find the length of its side.
Solution:
Perimeter of the rectangle = 2 [length + breadth] = 2[9 + 7] = 2 × 16 = 32 cm.
Now perimeter of the square = Perimeter of rectangle = 32 cm. Side of the square = 32 4 = 8 cm. Hence, the length of the side of square = 8 cm.Q. 7: The opposite angles of a parallelogram are (3x + 5)° and (61 – x)°. Find the measure of four angles.
Solution:
Given, (3x + 5)° and (61 – x)° are the opposite angles of a parallelogram. We know that the opposite angles of a parallelogram are equal. Therefore, (3x + 5)° = (61 – x)° 3x + x = 61° – 5° 4x = 56° x = 56°/4 x = 14° ⇒ 3x + 5 = 3(14) + 5 = 42 + 5 = 47 61 – x = 61 – 14 = 47 The measure of angles adjacent to the given angles = 180° – 47° = 133° Hence, the measure of four angles of the parallelogram are 47°, 133°, 47°, and 133°.Q. 8: ABCD is a parallelogram with ∠A = 80°. The internal bisectors of ∠B and ∠C meet each other at O. Find the measure of the three angles of ΔBCO.
Solution:
Given, ∠A = 80°Q. 9: Find the measure of all four angles of a parallelogram whose consecutive angles are in the ratio 1 : 3.
Solution:
Given, The ratio of two consecutive angles of a parallelogram = 1 : 3 Let x and 3x be the two consecutive angles. We know that the sum of interior angles on the same side of the transversal is 180°. Therefore, x + 3x = 180° 4x = 180° x = 180°/4 x = 45° ⇒ 3x = 3(45°) = 135° Thus, the measure of two consecutive angles is 45° and 135°. As we know, the opposite angles of a parallelogram are equal. Hence, the measure of all the four angles is 45°, 135°, 45°, and 135°.Q. 10: A diagonal and a side of a rhombus are of equal length. Find the measure of the angles of the rhombus.
Solution:
Let ABCD be the rhombus. Thus, AB = BC = CD = DA