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NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers

Here, we have provided NCERT Solutions for Class 7 Maths Chapter 9. Students can refer to these solutions before exams to gain a better understanding of the chapter's concepts and themes.
authorImageAnanya Gupta28 Feb, 2024
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NCERT Solutions for Class 7 Maths Chapter 9

NCERT Solutions for Class 7 Maths Chapter 9

NCERT Solutions for Class 7 Maths Chapter 9: Physics Wallah experts have provided detailed solutions for NCERT Solutions for Class 7 Maths Chapter 9. This chapter is all about Rational Numbers, an important topic in math. These solutions are made simple and easy to understand. They show step-by-step how to do things like add, subtract, multiply, and divide rational numbers. They also explain how to represent these numbers on a number line and simplify fractions. With Physics Wallah help, students can understand rational numbers better and do well in their math studies.

NCERT Solutions for Class 7 Maths Chapter 9 PDF

You can find the PDF link for NCERT Solutions for Class 7 Maths Chapter 9 below. These solutions are designed to help you understand Rational Numbers better. They explain things step by step, making it easier for you to solve problems. By using this PDF, you can improve your skills in dealing with rational numbers and do well in your exams.

NCERT Solutions for Class 7 Maths Chapter 9 PDF

NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers

Exercise 9.1 Page: 182

1. List five rational numbers between:

(i) -1 and 0

Solution:-

The five rational numbers between -1 and 0 are, -1< (-2/3) < (-3/4) < (-4/5) < (-5/6) < (-6/7) < 0

(ii) -2 and -1

Solution:-

The five rational numbers between -2 and -1 are, -2 < (-8/7) < (-9/8) < (-10/9) < (-11/10) < (-12/11) < -1

(iii) -4/5 and -2/3

Solution:-

The five rational numbers between -4/5 and -2/3 are, -4/5 < (-13/12) < (-14/13) < (-15/14) < (-16/15) < (-17/16) < -2/3

(iv) -1/2 and 2/3

Solution:-

The five rational numbers between -1/2 and 2/3 are, -1/2 < (-1/6) < (0) < (1/3) < (1/2) < (20/36) < 2/3

2. Write four more rational numbers in each of the following patterns:

(i) -3/5, -6/10, -9/15, -12/20, …..

Solution:-

In the above question, we can observe that the numerator and denominator are multiples of 3 and 5. = (-3 × 1)/ (5 × 1), (-3 × 2)/ (5 × 2), (-3 × 3)/ (5 × 3), (-3 × 4)/ (5 × 4) Then, the next four rational numbers in this pattern are, = (-3 × 5)/ (5 × 5), (-3 × 6)/ (5 × 6), (-3 × 7)/ (5 × 7), (-3 × 8)/ (5 × 8) = -15/25, -18/30, -21/35, -24/40 ….

(ii) -1/4, -2/8, -3/12, …..

Solution:-

In the above question, we can observe that the numerator and denominator are multiples of 1 and 4. = (-1 × 1)/ (4 × 1), (-1 × 2)/ (4 × 2), (-1 × 3)/ (1 × 3) Then, the next four rational numbers in this pattern are, = (-1 × 4)/ (4 × 4), (-1 × 5)/ (4 × 5), (-1 × 6)/ (4 × 6), (-1 × 7)/ (4 × 7) = -4/16, -5/20, -6/24, -7/28 ….

(iii) -1/6, 2/-12, 3/-18, 4/-24 …..

Solution:-

In the above question, we can observe that the numerator and denominator are multiples of 1 and 6. = (-1 × 1)/ (6 × 1), (1 × 2)/ (-6 × 2), (1 × 3)/ (-6 × 3), (1 × 4)/ (-6 × 4) Then, the next four rational numbers in this pattern are, = (1 × 5)/ (-6 × 5), (1 × 6)/ (-6 × 6), (1 × 7)/ (-6 × 7), (1 × 8)/ (-6 × 8) = 5/-30, 6/-36, 7/-42, 8/-48 ….

(iv) -2/3, 2/-3, 4/-6, 6/-9 …..

Solution:-

In the above question, we can observe that the numerator and denominator are the multiples of 2 and 3. = (-2 × 1)/ (3 × 1), (2 × 1)/ (-3 × 1), (2 × 2)/ (-3 × 2), (2 × 3)/ (-3 × 3) Then, the next four rational numbers in this pattern are, = (2 × 4)/ (-3 × 4), (2 × 5)/ (-3 × 5), (2 × 6)/ (-3 × 6), (2 × 7)/ (-3 × 7) = 8/-12, 10/-15, 12/-18, 14/-21 ….

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3. Give four rational numbers equivalent to:

(i) -2/7

Solution:-

The four rational numbers equivalent to -2/7 are, = (-2 × 2)/ (7 × 2), (-2 × 3)/ (7 × 3), (-2 × 4)/ (7 × 4), (-2 × 5)/ (7× 5) = -4/14, -6/21, -8/28, -10/35

(ii) 5/-3

Solution:-

The four rational numbers equivalent to 5/-3 are, = (5 × 2)/ (-3 × 2), (5 × 3)/ (-3 × 3), (5 × 4)/ (-3 × 4), (5 × 5)/ (-3× 5) = 10/-6, 15/-9, 20/-12, 25/-15

(iii) 4/9

Solution:-

The four rational numbers equivalent to 5/-3 are, = (4 × 2)/ (9 × 2), (4 × 3)/ (9 × 3), (4 × 4)/ (9 × 4), (4 × 5)/ (9× 5) = 8/18, 12/27, 16/36, 20/45

4. Draw the number line and represent the following rational numbers on it:

(i) ¾

Solution:-

We know that 3/4 is greater than 0 and less than 1. ∴ it lies between 0 and 1. It can be represented on the number line as,

NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 1

(ii) -5/8

Solution:-

We know that -5/8 is less than 0 and greater than -1. ∴ it lies between 0 and -1. It can be represented on the number line as,

NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 2

(iii) -7/4

Solution:-

Now, the above question can be written as, = (-7/4) = NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 3 We know that (-7/4) is less than -1 and greater than -2. ∴ it lies between -1 and -2. It can be represented on the number line as,

NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 4

(iv) 7/8

Solution:-

We know that 7/8 is greater than 0 and less than 1. ∴ it lies between 0 and 1. It can be represented on the number line as, NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 5

5. The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S.

NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 6

Solution:-

By observing the figure, we can say that, The distance between A and B = 1 unit And it is divided into 3 equal parts = AP = PQ = QB = 1/3 P = 2 + (1/3) = (6 + 1)/ 3 = 7/3 Q = 2 + (2/3) = (6 + 2)/ 3 = 8/3 Similarly, The distance between U and T = 1 unit And it is divided into 3 equal parts = TR = RS = SU = 1/3 R = – 1 – (1/3) = (- 3 – 1)/ 3 = – 4/3 S = – 1 – (2/3) = – 3 – 2)/ 3 = – 5/3
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6. Which of the following pairs represents the same rational number?

(i) (-7/21) and (3/9)

Solution:-

We have to check if the given pair represents the same rational number . Then, -7/21 = 3/9 -1/3 = 1/3 ∵ -1/3 ≠ 1/3 ∴ -7/21 ≠ 3/9 So, the given pair does not represent the same rational number .

(ii) (-16/20) and (20/-25)

Solution:-

We have to check if the given pair represents the same rational number . Then, -16/20 = 20/-25 -4/5 = 4/-5 ∵ -4/5 = -4/5 ∴ -16/20 = 20/-25 So, the given pair represents the same rational number.

(iii) (-2/-3) and (2/3)

Solution:-

We have to check if the given pair represents the same rational number . Then, -2/-3 = 2/3 2/3= 2/3 ∵ 2/3 = 2/3 ∴ -2/-3 = 2/3 So, the given pair represents the same rational number.

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(iv) (-3/5) and (-12/20)

Solution:-

We have to check if the given pair represents the same rational number . Then, -3/5 = – 12/20 -3/5 = -3/5 ∵ -3/5 = -3/5 ∴ -3/5= -12/20 So, the given pair represents the same rational number.

(v) (8/-5) and (-24/15)

Solution:-

We have to check if the given pair represents the same rational number . Then, 8/-5 = -24/15 8/-5 = -8/5 ∵ -8/5 = -8/5 ∴ 8/-5 = -24/15 So, the given pair represents the same rational number.

(vi) (1/3) and (-1/9)

Solution:-

We have to check if the given pair represents the same rational number . Then, 1/3 = -1/9 ∵ 1/3 ≠ -1/9 ∴ 1/3 ≠ -1/9 So, the given pair does not represent the same rational number.

(vii) (-5/-9) and (5/-9)

Solution:-

We have to check if the given pair represents the same rational number . Then, -5/-9 = 5/-9 ∵ 5/9 ≠ -5/9 ∴ -5/-9 ≠ 5/-9 So, the given pair does not represent the same rational number.

7. Rewrite the following rational numbers in the simplest form:

(i) -8/6

Solution:-

The given rational numbers can be simplified further, Then, = -4/3 … [∵ Divide both numerator and denominator by 2]

(ii) 25/45

Solution:-

The given rational numbers can be simplified further, Then, = 5/9 … [∵ Divide both numerator and denominator by 5]

(iii) -44/72

Solution:-

The given rational numbers can be simplified further, Then, = -11/18 … [∵ Divide both numerator and denominator by 4]

(iv) -8/10

Solution:-

The given rational numbers can be simplified further, Then, = -4/5 … [∵ Divide both numerator and denominator by 2]

8. Fill in the boxes with the correct symbol out of >, <, and =.

(i) -5/7 [ ] 2/3

Solution:-

The LCM of the denominators 7 and 3 is 21 ∴ (-5/7) = [(-5 × 3)/ (7 × 3)] = (-15/21) And (2/3) = [(2 × 7)/ (3 × 7)] = (14/21) Now, -15 < 14 So, (-15/21) < (14/21) Hence, -5/7 [<] 2/3

(ii) -4/5 [ ] -5/7

Solution:-

The LCM of the denominators 5 and 7 is 35 ∴ (-4/5) = [(-4 × 7)/ (5 × 7)] = (-28/35) And (-5/7) = [(-5 × 5)/ (7 × 5)] = (-25/35) Now, -28 < -25 So, (-28/35) < (- 25/35) Hence, -4/5 [<] -5/7

Related Links -

NCERT Solutions for Class 7 Maths Chapter 1 NCERT Solutions for Class 7 Maths Chapter 7
NCERT Solutions for Class 7 Maths Chapter 2 NCERT Solutions for Class 7 Maths Chapter 10
NCERT Solutions for Class 7 maths Chapter 3 NCERT Solutions for Class 7 Maths Chapter 11
NCERT Solutions for Class 7 Maths Chapter 4 NCERT Solutions for Class 7 Maths Chapter 12
NCERT Solutions for Class 7 Maths NCERT Solutions for Class 7 Maths Chapter 13
NCERT Solutions for Class 7 Maths Chapter 5 NCERT Solutions for Class 7 Maths Chapter 14
NCERT Solutions for Class 7 Maths Chapter 6 NCERT Solutions for Class 7 Maths Chapter 15
NCERT Solutions for Class 7 Maths Chapter 8

(iii) -7/8 [ ] 14/-16

Solution:-

14/-16 can be simplified further, Then, 7/-8 … [∵ Divide both numerator and denominator by 2] So, (-7/8) = (-7/8) Hence, -7/8 [=] 14/-16

(iv) -8/5 [ ] -7/4

Solution:-

The LCM of the denominators 5 and 4 is 20 ∴ (-8/5) = [(-8 × 4)/ (5 × 4)] = (-32/20) And (-7/4) = [(-7 × 5)/ (4 × 5)] = (-35/20) Now, -32 > – 35 So, (-32/20) > (- 35/20) Hence, -8/5 [>] -7/4

(v) 1/-3 [ ] -1/4

Solution:-

The LCM of the denominators 3 and 4 is 12 ∴ (-1/3) = [(-1 × 4)/ (3 × 4)] = (-4/12) And (-1/4) = [(-1 × 3)/ (4 × 3)] = (-3/12) Now, -4 < – 3 So, (-4/12) < (- 3/12) Hence, 1/-3 [<] -1/4

(vi) 5/-11 [ ] -5/11

Solution:-

Since, (-5/11) = (-5/11) Hence, 5/-11 [=] -5/11

(vii) 0 [ ] -7/6

Solution:-

Since every negative rational number is less than 0, We get: = 0 [>] -7/6

9. Which is greater in each of the following:

(i) 2/3, 5/2

Solution:-

The LCM of the denominators 3 and 2 is 6 (2/3) = [(2 × 2)/ (3 × 2)] = (4/6) And (5/2) = [(5 × 3)/ (2 × 3)] = (15/6) Now, 4 < 15 So, (4/6) < (15/6) ∴ 2/3 < 5/2 Hence, 5/2 is greater.

(ii) -5/6, -4/3

Solution:-

The LCM of the denominators 6 and 3 is 6 ∴ (-5/6) = [(-5 × 1)/ (6 × 1)] = (-5/6) And (-4/3) = [(-4 × 2)/ (3 × 2)] = (-12/6) Now, -5 > -12 So, (-5/6) > (- 12/6) ∴ -5/6 > -12/6 Hence, – 5/6 is greater.

(iii) -3/4, 2/-3

Solution:-

The LCM of the denominators 4 and 3 is 12 ∴ (-3/4) = [(-3 × 3)/ (4 × 3)] = (-9/12) And (-2/3) = [(-2 × 4)/ (3 × 4)] = (-8/12) Now, -9 < -8 So, (-9/12) < (- 8/12) ∴ -3/4 < 2/-3 Hence, 2/-3 is greater.

(iv) -¼, ¼

Solution:-

The given fraction is like friction, So, -¼ < ¼ Hence ¼ is greater, (v) NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 7 , NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 8 Solution:- First, we have to convert mixed fractions into improper fractions, NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 9 = -23/7 NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 10 = -19/5 Then, The LCM of the denominators 7 and 5 is 35 ∴ (-23/7) = [(-23 × 5)/ (7 × 5)] = (-115/35) And (-19/5) = [(-19 × 7)/ (5 × 7)] = (-133/35) Now, -115 > -133 So, (-115/35) > (- 133/35) ∴ NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 11 > NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 12 Hence, NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 13 is greater.

10. Write the following rational numbers in ascending order:

(i) -3/5, -2/5, -1/5

Solution:-

The given rational numbers are in the form of like fractions, Hence, (-3/5)< (-2/5) < (-1/5)

(ii) -1/3, -2/9, -4/3

Solution:-

To convert the given rational numbers into like fractions, we have to find the LCM, The LCM of 3, 9, and 3 is 9 Now, (-1/3)= [(-1 × 3)/ (3 × 9)] = (-3/9) (-2/9)= [(-2 × 1)/ (9 × 1)] = (-2/9) (-4/3)= [(-4 × 3)/ (3 × 3)] = (-12/9) Clearly, (-12/9) < (-3/9) < (-2/9) Hence, (-4/3) < (-1/3) < (-2/9)

(iii) -3/7, -3/2, -3/4

Solution:-

To convert the given rational numbers into like fractions, we have to find LCM, The LCM of 7, 2, and 4 is 28 Now, (-3/7)= [(-3 × 4)/ (7 × 4)] = (-12/28) (-3/2)= [(-3 × 14)/ (2 × 14)] = (-42/28) (-3/4)= [(-3 × 7)/ (4 × 7)] = (-21/28) Clearly, (-42/28) < (-21/28) < (-12/28) Hence, (-3/2) < (-3/4) < (-3/7) Exercise 9.2 Page: 190

1. Find the sum:

(i) (5/4) + (-11/4)

Solution:-

We have: = (5/4) – (11/4) = [(5 – 11)/4] … [∵ denominator is same in both the rational numbers] = (-6/4) = -3/2 … [∵ Divide both numerator and denominator by 3]

(ii) (5/3) + (3/5)

Solution:-

Take the LCM of the denominators of the given rational numbers. The LCM of 3 and 5 is 15 Express each of the given rational numbers with the above LCM as the common denominator. Now, (5/3)= [(5×5)/ (3×5)] = (25/15) (3/5)= [(3×3)/ (5×3)] = (9/15) Then, = (25/15) + (9/15) … [∵ denominator is same in both the rational numbers] = (25 + 9)/15 = 34/15

(iii) (-9/10) + (22/15)

Solution:-

Take the LCM of the denominators of the given rational numbers. The LCM of 10 and 15 is 30 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-9/10)= [(-9×3)/ (10×3)] = (-27/30) (22/15)= [(22×2)/ (15×2)] = (44/30) Then, = (-27/30) + (44/30) … [∵ denominator is same in both the rational numbers] = (-27 + 44)/30 = (17/30)

(iv) (-3/-11) + (5/9)

Solution:-

We have, = 3/11 + 5/9 Take the LCM of the denominators of the given rational numbers. The LCM of 11 and 9 is 99 Express each of the given rational numbers with the above LCM as the common denominator. Now, (3/11)= [(3×9)/ (11×9)] = (27/99) (5/9)= [(5×11)/ (9×11)] = (55/99) Then, = (27/99) + (55/99) … [∵ denominator is same in both the rational numbers] = (27 + 55)/99 = (82/99)

(v) (-8/19) + (-2/57)

Solution:-

We have = -8/19 – 2/57 Take the LCM of the denominators of the given rational numbers. The LCM of 19 and 57 is 57 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-8/19)= [(-8×3)/ (19×3)] = (-24/57) (-2/57)= [(-2×1)/ (57×1)] = (-2/57) Then, = (-24/57) – (2/57) … [∵ denominator is same in both the rational numbers] = (-24 – 2)/57 = (-26/57)

(vi) -2/3 + 0

Solution:-

We know that if any number or fraction is added to zero, the answer will be the same number or fraction. Hence, = -2/3 + 0 = -2/3

(vii) NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 14 + NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 15

Solution:-

First, we have to convert mixed fractions into improper fractions. = NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 16 = -7/3 = NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 17 = 23/5 We have, -7/3 + 23/5 Take the LCM of the denominators of the given rational numbers. The LCM of 3 and 5 is 15 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-7/3)= [(-7×5)/ (3×5)] = (-35/15) (23/5)= [(23×3)/ (15×3)] = (69/15) Then, = (-35/15) + (69/15) … [∵ denominator is same in both the rational numbers] = (-35 + 69)/15 = (34/15)

2. Find the value of:

(i) 7/24 – 17/36

Solution:-

Take the LCM of the denominators of the given rational numbers. The LCM of 24 and 36 is 72 Express each of the given rational numbers with the above LCM as the common denominator. Now, (7/24)= [(7×3)/ (24×3)] = (21/72) (17/36)= [(17×2)/ (36×2)] = (34/72) Then, = (21/72) – (34/72) … [∵ denominator is same in both the rational numbers] = (21 – 34)/72 = (-13/72)

(ii) 5/63 – (-6/21)

Solution:-

We can also write -6/21 = -2/7 = 5/63 – (-2/7) We have, = 5/63 + 2/7 Take the LCM of the denominators of the given rational numbers. The LCM of 63 and 7 is 63 Express each of the given rational numbers with the above LCM as the common denominator. Now, (5/63)= [(5×1)/ (63×1)] = (5/63) (2/7)= [(2×9)/ (7×9)] = (18/63) Then, = (5/63) + (18/63) … [∵ denominator is same in both the rational numbers] = (5 + 18)/63 = 23/63

(iii) -6/13 – (-7/15)

Solution:-

We have, = -6/13 + 7/15 The LCM of 13 and 15 is 195 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-6/13)= [(-6×15)/ (13×15)] = (-90/195) (7/15)= [(7×13)/ (15×13)] = (91/195) Then, = (-90/195) + (91/195) … [∵ denominator is same in both the rational numbers] = (-90 + 91)/195 = (1/195)

(iv) -3/8 – 7/11

Solution:-

Take the LCM of the denominators of the given rational numbers. The LCM of 8 and 11 is 88 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-3/8)= [(-3×11)/ (8×11)] = (-33/88) (7/11)= [(7×8)/ (11×8)] = (56/88) Then, = (-33/88) – (56/88) … [∵ denominator is same in both the rational numbers] = (-33 – 56)/88 = (-89/88)

(v) – NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 18 – 6

Solution:-

First, we have to convert the mixed fraction into an improper fraction, – NCERT Solutions for Class 7 Maths Chapter 9 Rational Numbers Image 19 = -19/9 We have, -19/9 – 6 Take the LCM of the denominators of the given rational numbers. The LCM of 9 and 1 is 9 Express each of the given rational numbers with the above LCM as the common denominator. Now, (-19/9)= [(-19×1)/ (9×1)] = (-19/9) (6/1)= [(6×9)/ (1×9)] = (54/9) Then, = (-19/9) – (54/9) … [∵ denominator is same in both the rational numbers] = (-19 – 54)/9 = (-73/9)

3. Find the product:

(i) (9/2) × (-7/4)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) The above question can be written as (9/2) × (-7/4) We have, = (9×-7)/ (2×4) = -63/8

(ii) (3/10) × (-9)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) The above question can be written as (3/10) × (-9/1) We have, = (3×-9)/ (10×1) = -27/10

(iii) (-6/5) × (9/11)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) We have, = (-6×9)/ (5×11) = -54/55

(iv) (3/7) × (-2/5)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) We have, = (3×-2)/ (7×5) = -6/35

(v) (3/11) × (2/5)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) We have, = (3×2)/ (11×5) = 6/55

(vi) (3/-5) × (-5/3)

Solution:-

The product of two rational numbers = (product of their numerator)/(product of their denominator) We have, = (3×-5)/ (-5×3) On simplifying, = (1×-1)/ (-1×1) = -1/-1 = 1

4. Find the value of:

(i) (-4) ÷ (2/3)

Solution:-

We have, = (-4/1) × (3/2) … [∵ reciprocal of (2/3) is (3/2)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-4×3) / (1×2) = (-2×3) / (1×1) = -6

(ii) (-3/5) ÷ 2

Solution:-

We have, = (-3/5) × (1/2) … [∵ reciprocal of (2/1) is (1/2)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-3×1) / (5×2) = -3/10

(iii) (-4/5) ÷ (-3)

Solution:-

We have, = (-4/5) × (1/-3) … [∵ reciprocal of (-3) is (1/-3)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-4× (1)) / (5× (-3)) = -4/-15 = 4/15

(iv) (-1/8) ÷ 3/4

Solution:-

We have, = (-1/8) × (4/3) … [∵ reciprocal of (3/4) is (4/3)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-1×4) / (8×3) = (-1×1) / (2×3) = -1/6

(v) (-2/13) ÷ 1/7

Solution:-

We have, = (-2/13) × (7/1) … [∵ reciprocal of (1/7) is (7/1)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-2×7) / (13×1) = -14/13

(vi) (-7/12) ÷ (-2/13)

Solution:-

We have, = (-7/12) × (13/-2) … [∵ reciprocal of (-2/13) is (13/-2)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (-7× 13) / (12× (-2)) = -91/-24 = 91/24

(vii) (3/13) ÷ (-4/65)

Solution:-

We have, = (3/13) × (65/-4) … [∵ reciprocal of (-4/65) is (65/-4)] The product of two rational numbers = (product of their numerator)/(product of their denominator) = (3×65) / (13× (-4)) = 195/-52 = -15/4

NCERT Solutions for Class 7 Maths Chapter 9 FAQs

What are rational numbers?

Rational numbers are numbers that can be expressed as a fraction, where the numerator and denominator are both integers and the denominator is not zero.

How are rational numbers different from whole numbers?

Whole numbers are a subset of rational numbers, consisting of all positive integers and zero. Rational numbers, on the other hand, include fractions and decimals that can be expressed as fractions.

How do you add and subtract rational numbers?

To add or subtract rational numbers, you simply add or subtract the numerators while keeping the denominators the same.

Can you provide examples of rational numbers?

Examples of rational numbers include 1/2, -3/4, 5, and -7.2.
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Physics Wallah's main focus is to make the learning experience as economical as possible for all students. With our affordable courses like Lakshya, Udaan and Arjuna and many others, we have been able to provide a platform for lakhs of aspirants. From providing Chemistry, Maths, Physics formula to giving e-books of eminent authors like RD Sharma, RS Aggarwal and Lakhmir Singh, PW focuses on every single student's need for preparation.
What Makes Us Different
Physics Wallah strives to develop a comprehensive pedagogical structure for students, where they get a state-of-the-art learning experience with study material and resources. Apart from catering students preparing for JEE Mains and NEET, PW also provides study material for each state board like Uttar Pradesh, Bihar, and others

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