The Integration of UV Formula helps simplify the process of integrating the product of two functions, such as algebraic, trigonometric, or logarithmic expressions. The Integral UV formula is written as:
∫u dv=uv−∫v du
This method, also called integration by parts , breaks down complex integrals into simpler parts using the relationship between differentiation and integration. It’s a practical tool for solving problems where traditional methods may not work easily.
In this blog, we’ll explore the UV formula step-by-step, learn how it’s derived, and look at some examples to help you apply it confidently.
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The integral uv formula is a rule used to find the integral of the product of two functions, u and v. It helps simplify complicated integrals by breaking them into smaller parts. The formula is written as ∫u dv = uv - ∫v du. Here, u and v are functions of x, du is the derivative of u, and dv is the derivative of v. This method is useful when directly integrating the product of the two functions seems difficult. The formula is derived from the product rule of differentiation. It is one of the basic integration techniques in calculus.
In integration, the uv formula is also called integration by parts. It states that the integral of u times dv equals u times v minus the integral of v times du. Simply put, it transforms an integral of a product into simpler integrals. This formula is helpful when one function is easier to differentiate (u) and the other is easier to integrate (dv). By choosing u and dv wisely, problems that look hard at first become easier to solve. This formula is widely used in solving calculus problems with complicated products of functions.
∫uv dx=u∫v dx−∫(u′∫v dx)dx
or equivalently,∫u dv=uv−∫v du
Here:The uv rule in integration is a technique to find the integral of two multiplied functions. It says ∫u dv = uv - ∫v du, where u is a function, and dv is a derivative function. First, you choose which part of the product is u and which is dv. Then you find du by differentiating u and v by integrating dv. Substitute these values into the formula to get a simpler integral to solve. This method saves time and effort when direct integration is tough. It is essential for many calculus problems.
The uv rule in integration helps calculate the integral of the product of two functions by breaking it into smaller, easier integrals. The rule is ∫u dv = uv - ∫v du, where u and dv are parts of the original integrand. You differentiate u to get du and integrate dv to get v. Then use the formula to rewrite the integral. This technique is especially useful when one function can be easily differentiated and the other easily integrated. It turns complex integrals into manageable tasks.
Step 1: Identify the functions u(x) and v(x) :
Use the LIATE rule to choose u(x):Step 2. Find the derivative of u(x) :
Compute du/dx, the derivative of u(x), which is written as du. This step simplifies one part of the integral.Step 3: Integrate v :
Find the integral of dv , which gives v(x) . For example, if dv=e x dx, then v=e xStep 4: Substitute into the formula:
Use the integration of UV formula: ∫u⋅v dx=uv−∫v⋅du Plug u(x) , v(x) , and du into the formula to transform the original integral into a simpler one.Step 5: Simplify and Solve:
Compute the remaining integral ∫v⋅du. Combine all terms to get the final solution, including the constant of integration C .Read More - Combustion and Flame
Step 1: Choose u(x) and dv :
Based on the LIATE rule: u(x)= (algebraic function) dv=sin(x)dx (trigonometric function)Step 2: Differentiate u(x) :
u=x ⟹ du=dxStep 3: Integrate dvdv :
dv=sin(x)dx ⟹ v=−cos(x)Step 4: Substitute into the formula:
∫x sin(x)dx=u⋅v−∫v⋅duSubstituting the values:
∫x sin(x)dx=x⋅(−cos(x))−∫(−cos(x))⋅dx ∫x sin(x)dx=−xcos(x)+∫cos(x)dxStep 5: Simplify and solve:
Integrate ∫cos(x)dx ∫x sin(x)dx=−x cos(x)+sin(x)+C or ∫x sin(x)dx=sin(x) −cos(x) +CThe u/v rule is commonly associated with differentiation rather than integration. It refers to differentiating a function that is a quotient of two functions. However, when integrating expressions involving u over v, special methods like substitution or partial fractions may be necessary instead of a direct u/v formula. The integral of u/v isn't straightforward and usually requires breaking down the fraction or using advanced calculus techniques for proper integration.
Integrating u/v, where u and v are functions, often needs special strategies because direct integration is not easy. This type of integral usually requires methods like substitution, partial fractions, or integration by parts if it fits. The integral of u/v dx cannot simply use a formula like uv integration. Careful manipulation of the expression is needed to simplify before integrating. In some cases, integrating u/v means rewriting it so the functions become easier to handle.
To integrate u/v dx, where u and v are functions of x, you often need to simplify the expression first. Direct integration is difficult, so methods like substitution or partial fractions are usually applied. Sometimes, rewriting the integral by separating terms or using algebra helps. In other cases, integration by parts might help if u/v can be expressed in forms suitable for this rule. This kind of integral generally requires more steps than usual integrals but can be solved with careful algebra and calculus methods.
Here, we will learn the derivation of the integration of UV Formula using the product rule of differentiation:
Step 1: Start with the product rule of differentiation
Consider two differentiable functions, u and v , such that: y=u⋅vy = Using the product rule of differentiation:Step 2: Rearrange the equation to isolate u dv/dx on one side:
Step 3: Integrate both sides with respect to x:
Step 4: Simplify using the fundamental theorem of calculus
The integral of a derivative, ∫d/dx (uv) is simply the original function uv. This gives:Read More - Motion and measurement of Distance
Example 1: Find the integral of x 2 ⋅ex
Solution:
Identify u and dv : Let u= x 2 , so du=2xdx Let dv=e x dx, so v=∫e x dx=e x Apply the formula ∫u dv=uv−∫v du ∫x 2 e x dx=x 2 e x −∫(2xe x )dx Solve the remaining integral ∫2x ex dx Let u=x, du=d , , v=e Multiply by 2: ∫2xe dx=2(x ex −e x ) Substitute back: ∫x 2 e dx = x 2 e −2(xe −e ) Simplify: ∫x 2 e dx = x 2 e − 2 x e x + 2 e x + CAnswer:
∫x 2 e x 2 − 2 x + 2 ) + C dx = e (Example 2: Find the integral of ln(x)⋅e x
Solution:
Identify u and dv : Let u=ln(x), so du=1/xdx Let dv=e x dx , so v=∫e x dx=e x vApply the formula ∫u dv=uv−∫v du:
∫ln(x)e x dx=ln(x)⋅e x −∫e x × 1/x dxSimplify the terms:
∫ln(x)e x dx=ln(x)⋅e x −∫e x / xdx The second integral ∫e x dx cannot be expressed in elementary functions, so the answer remains: ∫ln(x)e x dx=ln(x)⋅e x −∫e x /x dx+CDifferential Equations: Integration by parts is frequently used to solve linear differential equations and boundary value problems where the integrals involve complex functions.
Fourier Series and Transforms: This UV formula simplifies the derivation and evaluation of Fourier coefficients, a cornerstone for signal processing and analyzing periodic functions.
Quantum Mechanics and Physics: In physics, integration by parts appears in the solution of wave equations, Schrödinger's equation, and problems involving energy states.
Numerical Methods: It forms the theoretical base for various approximation methods used in numerical integration and computational calculus.
Machine Learning and AI: The UV formula helps solve integrals of probability density functions and loss functions, essential in algorithms like backpropagation.
By mastering the integration of UV formula, you'll gain a versatile mathematical tool applicable across a wide range of fields, extending its utility far beyond textbook problems. Join Kids Online Tuition Class Now !!