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NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 (Relations and Functions)

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4: Get accurate error free NCERT Solutions for Class 12 Maths chapter 1-Relations and Functions Exercise 1.4.
authorImageKrati Saraswat18 Jan, 2024
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NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 (Relations and Functions)

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 Relations and Functions is prepared by academic team of Physics Wallah. We have prepared NCERT Solutions for all exercise of chapter 1. Given below is step by step solutions of all questions given in NCERT textbook for Chapter 1 Relations and Functions.

NCERT Solutions for Class 12 Physics

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 Overview

These crucial subjects are covered in NCERT Solutions Class 12 Maths Chapter 1. To fully grasp the concepts presented in the chapter and make effective use of the provided solutions, students are urged to look over each topic in detail. The teachers at Physics Wallah have been working very hard to help students better understand the concepts that are taught in this chapter, and the result is these solutions. The intention is for students to achieve excellent exam scores with ease after reviewing and practicing these answers.

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 PDF

For NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4, our team of teachers at Physics Wallah has created comprehensive solutions to aid students in comprehending and applying chapter themes. These questions aim to facilitate students' understanding of explanations. The NCERT Solutions for Class 12 Maths, Chapter 1 PDF may be downloaded by clicking the following link:

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NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4

Solve The Following Questions NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4

Question 1. Determine whether or not each of the definition of given below gives a binary operation. In the event that * is not a binary operation, give justification for this. (i) On Z + , define * by a * b = a − b (ii) On Z + , define * by a * b = ab (iii) On R, define * by a * b = ab 2 (iv) On Z + , define * by a * b = |a − b| (v) On Z + , define * by a * b = a Solution : (i) On Z + , * is defined by a * b = a − b. It is not a binary operation as the image of (1, 2) under * is 1 * 2 = 1 − 2 = −1 ∉ Z + . (ii) On Z + , * is defined by a * b = ab. It is seen that for each a, b ∈ Z + , there is a unique element ab in Z + . This means that * carries each pair (a, b) to a unique element a * b = ab in Z + . Therefore, * is a binary operation. (iii) On R, * is defined by a * b = ab 2 . It is seen that for each a, b ∈ R, there is a unique element ab 2 in R. This means that * carries each pair (a, b) to a unique element a * b = ab 2 in R. Therefore, * is a binary operation. (iv) On Z + , * is defined by a * b = |a − b|. It is seen that for each a, b ∈ Z + , there is a unique element |a − b| in Z + . This means that * carries each pair (a, b) to a unique element a * b = |a − b| in Z + . Therefore, * is a binary operation. (v) On Z + , * is defined by a * b = a. * carries each pair (a, b) to a unique element a * b = a in Z + . Therefore, * is a binary operation.

NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.1

Question 2. For each binary operation * defined below, determine whether * is commutative or associative:

(i) On Z, define a * b = a b

(ii) On Q, define a * b = ab + 1

(iii) On Q, define a * b =ab/2

(iv) On Z + , define a * b = 2 ab

(v) On Z + , define a * b = a b

(vi) On R − {−1}, define  a.b = a/b+1

Solution : (i) On Z , * is defined by a * b = a − b . It can be observed that 1 * 2 = 1 − 2 = 1 and 2 * 1 = 2 − 1 = 1. ∴1 * 2 ≠ 2 * 1; where 1, 2 ∈ Z Hence, the operation * is not commutative. Also we have: (1 * 2) * 3 = (1 − 2) * 3 = −1 * 3 = −1 − 3 = −4 1 * (2 * 3) = 1 * (2 − 3) = 1 * −1 = 1 − (−1) = 2 ∴(1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3 ∈ Z Hence, the operation * is not associative. (ii) On Q , * is defined by a * b = ab + 1. It is known that: ab = ba &mnForE; a, b Q ab + 1 = ba + 1 &mnForE; a, b Q a * b = a * b &mnForE; a, b Q Therefore, the operation * is commutative. It can be observed that: (1 * 2) * 3 = (1 × 2 + 1) * 3 = 3 * 3 = 3 × 3 + 1 = 10 1 * (2 * 3) = 1 * (2 × 3 + 1) = 1 * 7 = 1 × 7 + 1 = 8 ∴(1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3 ∈ Q Therefore, the operation * is not associative. (iii) On Q , * is defined by a * b = ab/2 It is known that: ab = ba &mnForE; a, b Q ⇒ ab/2 = ba/2 &mn ForE; a, b Q a * b = b * a &mnForE; a, b Q Therefore, the operation * is commutative. For all a, b , c Q , we have: ncert solution Therefore, the operation * is associative. (iv) On Z + , * is defined by a * b = 2 ab . It is known that: ab = ba &mnForE; a, b Z + ⇒ 2 ab = 2 ba &mnForE; a, b Z + a * b = b * a &mnForE; a, b Z + Therefore, the operation * is commutative. It can be observed that: ncert solution ∴(1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3 ∈ Z + Therefore, the operation * is not associative. (v) On Z + , * is defined by a * b = a b . It can be observed that: 1 x2 = 1 2 =1 and 2x 1 =2 1 = 2 ∴ 1 * 2 ≠ 2 * 1 ; where 1, 2 ∈ Z + Therefore, the operation * is not commutative. It can also be observed that: ncert solution ∴(2 * 3) * 4 ≠ 2 * (3 * 4) ; where 2, 3, 4 ∈ Z + Therefore, the operation * is not associative. (vi) On R , * − {−1} is defined by a.b = a/b+1 It can be observed that 1 x 2 = 1/2+1 = 1/2 and 2 x 1 = 2/1+1 = 2/2 ∴1 * 2 ≠ 2 * 1 ; where 1, 2 ∈ R − {−1} Therefore, the operation * is not commutative. It can also be observed that: ncert solution ∴ (1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3 ∈ R − {−1} Therefore, the operation * is not associative.

NCERT Solutions for Class 12 Maths Chapter 1 Miscellaneous Exercise

Question 3. Consider the binary operation ∨ on the set {1, 2, 3, 4, 5} defined by a ∨b = min {a, b}. Write the operation table of the operation∨. Solution : The binary operation ∨ on the set {1, 2, 3, 4, 5} is defined as a ∨ b = min {a, b} & mn For E; a, b ∈ {1, 2, 3, 4, 5}. Thus, the operation table for the given operation ∨ can be given as:
1 2 3 4 5
1 1 1 1 1 1
2 1 2 2 2 2
3 1 2 3 3 3
4 1 2 3 4 4
5 1 2 3 4 5

NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.2

4. Consider a binary operation * on the set {1, 2, 3, 4, 5} given by the following multiplication table. (i) Compute (2 * 3) * 4 and 2 * (3 * 4) (ii) Is * commutative? (iii) Compute (2 * 3) * (4 * 5). (Hint: use the following table)
* 1 2 3 4 5
1 1 1 1 1 1
2 1 2 1 2 1
3 1 1 3 1 1
4 1 2 1 4 1
5 1 1 1 1 5
Solution : (i) (2 * 3) * 4 = 1 * 4 = 1 2 * (3 * 4) = 2 * 1 = 1 (ii) For every a, b ∈{1, 2, 3, 4, 5}, we have a * b = b * a. Therefore, the operation * is commutative. (iii) (2 * 3) = 1 and (4 * 5) = 1 ∴(2 * 3) * (4 * 5) = 1 * 1 = 1

NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.3

Question 5. Let*′ be the binary operation on the set {1, 2, 3, 4, 5} defined by a *′ b = H.C.F. of a and b. Is the operation *′ same as the operation * defined in Exercise 4 above? Justify your answer. Solution : The binary operation *′ on the set {1, 2, 3 4, 5} is defined as a *′ b = H.C.F of a and b. The operation table for the operation *′ can be given as:
*′ 1 2 3 4 5
1 1 1 1 1 1
2 1 2 1 2 1
3 1 1 3 1 1
4 1 2 1 4 1
5 1 1 1 1 5
We observe that the operation tables for the operations * and *′ are the same. Thus, the operation *′ is same as the operation*. Question 6. Let * be the binary operation on N given by a * b = L.C.M. of a and b. Find (i) 5 * 7, 20 * 16 (ii) Is * commutative? (iii) Is * associative? (iv) Find the identity of * in N (v) Which elements of N are invertible for the operation *? Solution : The binary operation * on N is defined as a * b = L.C.M. of a and b. (i) 5 * 7 = L.C.M. of 5 and 7 = 35 20 * 16 = L.C.M of 20 and 16 = 80 (ii) It is known that: L.C.M of a and b = L.C.M of b and a &mnForE; a, b ∈ N. ∴a * b = b * a Thus, the operation * is commutative. (iii) For a, b, c ∈ N, we have: (a * b) * c = (L.C.M of a and b) * c = LCM of a, b, and c a * (b * c) = a * (LCM of b and c) = L.C.M of a, b, and c ∴(a * b) * c = a * (b * c) Thus, the operation * is associative. (iv) It is known that: L.C.M. of a and 1 = a = L.C.M. 1 and a &mnForE; a ∈ N ⇒ a * 1 = a = 1 * a &mnForE; a ∈ N Thus, 1 is the identity of * in N. (v) An element a in N is invertible with respect to the operation * if there exists an element b in N, such that a * b = e = b * a. Here, e = 1 This means that: L.C.M of a and b = 1 = L.C.M of b and a This case is possible only when a and b are equal to 1. Thus, 1 is the only invertible element of N with respect to the operation *. Question 7. Is * defined on the set {1, 2, 3, 4, 5} by a * b = L.C.M. of a and b a binary operation? Justify your answer. Solution : The operation * on the set A = {1, 2, 3, 4, 5} is defined as a * b = L.C.M. of a and b. Then, the operation table for the given operation * can be given as:
* 1 2 3 4 5
1 1 2 3 4 5
2 2 2 6 4 10
3 3 6 3 12 15
4 4 4 12 4 20
5 5 10 15 20 5
It can be observed from the obtained table that: 3 * 2 = 2 * 3 = 6 ∉ A, 5 * 2 = 2 * 5 = 10 ∉ A, 3 * 4 = 4 * 3 = 12 ∉ A 3 * 5 = 5 * 3 = 15 ∉ A, 4 * 5 = 5 * 4 = 20 ∉ A Hence, the given operation * is not a binary operation. Question 8. Let * be the binary operation on N defined by a * b = H.C.F. of a and b. Is * commutative? Is * associative? Does there exist identity for this binary operation on N? Solution : The binary operation * on N is defined as: a * b = H.C.F. of a and b It is known that: H.C.F. of a and b = H.C.F. of b and a &mnForE; a, b ∈ N. ∴a * b = b * a Thus, the operation * is commutative. For a, b, c ∈ N, we have: (a * b)* c = (H.C.F. of a and b) * c = H.C.F. of a, b, and c a *(b * c)= a *(H.C.F. of b and c) = H.C.F. of a, b, and c ∴(a * b) * c = a * (b * c) Thus, the operation * is associative. Now, an element e ∈ N will be the identity for the operation * if a * e = a = e* a ∈ a ∈ N. But this relation is not true for any a ∈ N. Thus, the operation * does not have any identity in N. Question 9. Let * be a binary operation on the set Q of rational numbers as follows: (i) a * b = a − b (ii) a * b = a 2 + b 2 (iii) a * b = a + ab (iv) a * b = (a − b) 2

(v) a * b = ab/4  (vi) a * b = ab 2

Find which of the binary operations are commutative and which are associative. Ans. NCERT Solutions for Class 12 Maths Relations and Functions /image086.png NCERT Solutions for Class 12 Maths Relations and Functions NCERT Solutions for Class 12 Maths Relations and Functions /image087.png NCERT Solutions for Class 12 Maths Relations and Functions /image088.png

10. Find which of the operations given above has identity.

Solution : Let the identity be I. NCERT Solutions for Class 12 Maths Relations and Functions /image107.png Question 11. Let A = N × N and * be the binary operation on A defined by (a, b) * (c, d) = (a + c, b + d) Show that * is commutative and associative. Find the identity element for * on A, if any. Solution : A = N × N * is a binary operation on A and is defined by: (a, b) * (c, d) = (a + c, b + d) Let (a, b), (c, d) ∈ A Then, a, b, c, d ∈ N We have: (a, b) * (c, d) = (a + c, b + d) (c, d) * (a, b) = (c + a, d + b) = (a + c, b + d) [Addition is commutative in the set of natural numbers] ∴(a, b) * (c, d) = (c, d) * (a, b) Therefore, the operation * is commutative. Now, let (a, b), (c, d), (e, f) ∈A Then, a, b, c, d, e, f ∈ N We have: NCERT Solutions for Class 12 Maths Relations and Functions Question 12. State whether the following statements are true or false. Justify. (i) For an arbitrary binary operation * on a set N, a * a = a ∀ a * N. (ii) If * is a commutative binary operation on N, then a * (b * c) = (c * b) * a Solution : (i) Define an operation * on N as: a * b = a + b  a, b ∈ N Then, in particular, for b = a = 3, we have: 3 * 3 = 3 + 3 = 6 ≠ 3 Therefore, statement (i) is false. (ii) R.H.S. = (c * b) * a = (b * c) * a [* is commutative] = a * (b * c) [Again, as * is commutative] = L.H.S. ∴ a * (b * c) = (c * b) * a Therefore, statement (ii) is true. Question 13. Consider a binary operation * on N defined as a * b = a 3 + b 3 . Choose the correct answer. (A) Is * both associative and commutative? (B) Is * commutative but not associative? (C) Is * associative but not commutative? (D) Is * neither commutative nor associative? Solution : On N, the operation * is defined as a * b = a 3 + b 3 . For, a, b, ∈ N, we have: a * b = a 3 + b 3 = b 3 + a 3 = b * a [Addition is commutative in N] Therefore, the operation * is commutative. It can be observed that: (1*2)*3 = (1 3 +2 3 )*3 = 9 * 3 = 93 + 33 = 729 + 27 = 756 Also, 1*(2*3) = 1*(2 3 +3 3 ) = 1*(8 +27) = 1 × 35 = 1 3 +35 3 = 1 +(35) 3 = 1 + 42875 = 42876. ∴(1 * 2) * 3 ≠ 1 * (2 * 3) ; where 1, 2, 3 ∈ N Therefore, the operation * is not associative. Hence, the operation * is commutative, but not associative. Thus, the correct answer is B.

NCERT Solutions for Class 12 Maths Chapter 1 Excercise 1.4 FAQs

What are the 4 types of relation in math?

The different types of relations are empty relation, universal relation, reflexive relation, symmetric relation, and transitive relation.

How many relations are functions?

Functions can be one-to-one relations or many-to-one relations. A many-to-one relation associates two or more values of the independent (input) variable with a single value of the dependent (output) variable.

What does F of G mean in math?

In mathematics, (f ∘ g) represents the composition of two functions. This means that you apply the function g to the input, and then apply the function f to the output of g. Mathematically, (f ∘ g)(x) = f(g(x)). This notation is used to denote the combination of two functions in a specific order.

What is universal relation?

A universal (or full relation) is a type of relation in which every element of a set is related to each other. Consider set A = {a, b, c}. Now one of the universal relations will be R = {x, y} where, |x – y| ≥ 0. For universal relation, R = A × A.

What is a relation called in math?

A relation is a relationship between sets of values. In math, the relation is between the x-values and y-values of ordered pairs.
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