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Solution :
(ii)
Solution :
(i)
then show that |2A| = 4|A|
Hence, proved.
then show that 3|A| = 27|A|
Solution :
Given: A =
Hence, proved.
(ii)
(iii)
(iv)
Solution :
Evaluate the determinants:
(i) Given:
(ii) Given:
(iii) Given:
= 0 + 6 – 6 = 0
(iv) Given:
= -10 + 15 = 5
find |A|
Solution :
Given: A =
(ii)
Solution :
(i) Given:
then x is equal to:
(A) 6
(B) ± 6
(C) - 6
(D) 0
Solution :
Given:
