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Solution :
Solution :
Solution :
Solution :
Solution :
Solution :
It can be seen that the given integrand is not a proper fraction.
Therefore, on dividing (1 −
x
2
) by
x
(1 − 2
x
), we obtain
Solution :
Solution :
Solution :
Question10.
Solution :
Question11.
Solution :
Question12.
Solution :
It can be seen that the given integrand is not a proper fraction.
Therefore, on dividing (
x
3
+
x
+ 1) by
x
2
− 1, we obtain
Integrate the following function in Exercises 13 to 17.
Question13.
Solution :
Question 14.
Solution :
Question15.
Solution :
Question16.
[Hint: multiply numerator and denominator by
x
n
− 1
and put
x
n
=
t
]
Solution :
[Hint: Put sin
x
=
t
]
[Hint: Put
e
x
=
t
]
equals:
equals:
Therefore, option (A) is correct.
