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NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Exercise - Matrices

NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Exercise: Get inside detail NCERT Solutions for Class 12 Maths Chapter 3-Matrices Miscellaneous Exercise prepared by academic team of Physics Wallah all questions are solved in detail.
authorImageKrati Saraswat13 Jan, 2024
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NCERT Solution for Class 12 Maths Chapter 3 Miscellaneous Exercise

NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Exercise Matrices

NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Exercise Matrices is prepared by the academic team of Physics Wallah. We have prepared NCERT Solutions for all exercise of Chapter 3. Given below is the step by step solutions of all questions given in the NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Exercise Matrices.

NCERT Solutions for Class 12 Maths Chapter 3 Exercise 3.1

NCERT Solution for Class 12 Maths Chapter 3 Miscellaneous Exercise Overview

NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous Excercise  addresses these significant subjects. In order to fully comprehend the concepts presented in the chapter and make effective use of the provided solutions, it is recommended that students go over each topic in great detail. The instructors at Physics Wallah have put a lot of effort into helping students better understand the ideas presented in this chapter, as evidenced by these solutions. The intention is for students to effortlessly achieve excellent exam scores after reviewing and practicing these responses.

NCERT Solution for Class 12 Maths Chapter 3 Miscellaneous Exercise PDF

Educators at Physics Wallah has created NCERT Solutions for Class 12 Maths Chapter 3 Miscellaneous  Excercise comprehensive solutions for in order to assist students in comprehending and applying chapter themes. These questions are meant to help students understand explanations more easily. To download the NCERT Solutions for Class 12 Maths Chapter 3 PDF, click the following link:

NCERT Solutions Class 12 Maths Chapter 3 PDF Download Link

NCERT Solutions for Class 12 Maths Miscellaneous Exercise

Solve The Following Questions NCERT Solution for Class 12 Maths Chapter 3 Miscellaneous Exercise Matrices:

Question 1. Let A = chapter 3-Matrices Miscellaneous Exercise/image001.png show that chapter 3-Matrices Miscellaneous Exercise/image002.png where I is the identity matrix of order 2 and ∈ N. Solution : Given: chapter 3-Matrices Miscellaneous Exercise/image001.png chapter 3-Matrices Miscellaneous Exercise/image008.png

NCERT Solutions for Class 12 Maths Chapter 3 Exercise 3.2

Question 2. If A = chapter 3-Matrices Miscellaneous Exercise , prove that A n = chapter 3-Matrices Miscellaneous Exercise/image018.png ,n ∈ N. Solution : Given: A = chapter 3-Matrices Miscellaneous Exercise To show :P(n): A n chapter 3-Matrices Miscellaneous Exercise/image018.png ,n ∈ N We shall prove the result by using the principle of mathematical induction. For n = 1, we have: chapter 3-Matrices Miscellaneous Exercise

NCERT Solutions for Class 12 Maths Chapter 3 Exercise 3.3

Question 3. If A = chapter 3-Matrices Miscellaneous Exercise/image031.png then prove that A n = chapter 3-Matrices Miscellaneous Exercise/image032.png where n is any positive integer. Solution : Given: A n = chapter 3-Matrices Miscellaneous Exercise/image031.png To show :P(n): A n chapter 3-Matrices Miscellaneous Exercise/image032.png ,n ∈ N We shall prove the result by using the principle of mathematical induction. For n = 1, we have: chapter 3-Matrices Miscellaneous Exercise

NCERT Solutions for Class 12 Maths Chapter 3 Exercise 3.4

Question 4. If A and B are symmetric matrices, prove that AB – BA is a skew symmetric matrix. Solution : A and B are symmetric matrices. A’ = A and B’ = B  ……….(i) Now, (AB – BA)’ = (AB)’ – (BA)’          ∴ (AB – BA)’ = B’A’ – A’B’ [Reversal law] ∴ (AB – BA)’ = BA – AB   [Using eq. (i)] ∴ (AB – BA)’ = – (AB – BA) Therefore, (AB – BA) is a skew symmetric. Question 5. Show that the matrix B’AB is symmetric or skew symmetric according as A is symmetric or skew symmetric. Solution : (B’AB)’ = [B’(AB]’ = (AB)’ (B’)’   [∴ (CD)’ = D’C’] ∴  (B’AB)’ = B’A’B   ……….(i) Case I: A is a symmetric matrix, then   A’ = A From eq. (i)  (B’AB)’ = B’AB B’AB is a symmetric matrix. Case II: A is a skew symmetric matrix. A’ = – A Putting A’ = – A in eq. (i),  (B’AB)’ = B’(– A)B = – B’AB B’AB is a skew symmetric matrix.
NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.1 NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.2
NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.3 NCERT Solutions for Class 12 Maths Chapter 1 Exercise 1.4
NCERT Solutions for Class 12 Maths Chapter 1 Miscellaneous Exercise

Question 6. Find the values of x,y,z if the matrix chapter 3-Matrices Miscellaneous Exercise/image046.png satisfies the equation A’A = I.

Solution : Given: chapter 3-Matrices Miscellaneous Exercise/image046.png chapter 3-Matrices Miscellaneous Exercise/image047.png Question 7. For what value of x chapter 3-Matrices Miscellaneous Exercise/image061.png = O? Solution : chapter 3-Matrices Miscellaneous Exercise/image061.png
NCERT Solutions for Class 12 Maths Chapter 2 Exercise 2.1 NCERT Solutions for Class 12 Maths Chapter 2 Exercise 2.2
NCERT Solutions for Class 12 Maths Chapter 2 Miscellaneous Exercise
Question 8. If A = chapter 3-Matrices Miscellaneous Exercise/image068.png show that A 2 – 5A + 7I = 0. Solution : Given: A = chapter 3-Matrices Miscellaneous Exercise/image068.png chapter 3-Matrices Miscellaneous Exercise Question 9. Find x  if chapter 3-Matrices Miscellaneous Exercise/image077.png Solution : chapter 3-Matrices Miscellaneous Exercise/image078.png Question 10. A manufacturer produces three products, x,y,z  which he sells in two markets. Annual sales are indicated below:
Market Products
I. 10,000 2,000 18,000
II. 6,000 20,000 8,000
(a) If unit sales prices of x,y and z are ` 2.50, ` 1.50 and ` 1.00 respectively, find the total revenue in each market with the help of matrix algebra. (b) If the unit costs of the above three commodities are ` 2.00, ` 1.00 and 50 paise respectively. Find the gross profit. Solution : (a) The unit sale prices of x, y, and z are respectively given as Rs 2.50, Rs 1.50, and Rs 1.00. Consequently, the total revenue in market I can be represented in the form of a matrix as: chapter 3-Matrices Miscellaneous Exercise/image091.png = 10000 x 2.50 + 2000 x 1.50 + 18000 x 1.00 = 25000 + 3000 + 18000 = 46000 The total revenue in market II can be represented in the form of a matrix as: chapter 3-Matrices Miscellaneous Exercise/image091.png = 6000 x 2.50 + 20000 x 1.50 + 8000 x 1.00 = 15000 + 30000 + 8000 = 53000 Therefore, the total revenue in market I isRs 46000 and the same in market II isRs 53000. (b) The unit cost prices of x, y, and z are respectively given as Rs 2.00, Rs 1.00, and 50 paise. Consequently, the total cost prices of all the products in market I can be represented in the form of a matrix as: chapter 3-Matrices Miscellaneous Exercise/image095.png = 10000 x 2.00 + 2000 x 1.00 + 18000 x 0.50 = 20000 + 2000 + 9000 = 31000 Since the total revenue in market I isRs 46000, the gross profit in this marketis (Rs 46000 − Rs 31000) Rs 15000. chapter 3-Matrices Miscellaneous Exercise/image095.png = 6000 x 2.00 + 20000 x 1.00 + 8000 x 0.50 = 12000 + 20000 + 4000 = 36000 The total cost prices of all the products in market II can be represented in the form of a matrix as: Since the total revenue in market II isRs 53000, the gross profit in this market is (Rs 53000 − Rs 36000) Rs 17000. Question 11. Find the matrix X so that X chapter 3-Matrices Miscellaneous Exercise/image100.png Solution : Given: X chapter 3-Matrices Miscellaneous Exercise/image100.png ……….(i) The matrix given on the R.H.S. of the equation is a 2 × 3 matrix and the one given on the L.H.S. of the equation is a 2 × 3 matrix. Therefore, X has to be a 2 × 2 matrix. NCERT Solutions for Class 12 Math Chapter 3 - Matrices Question 12. If A and B are square matrices of the same order such that AB = BA, then prove by induction that AB’’ = B’’A. Further prove that (AB)’’ = A’’B’’ for all n ∈ N. Solution : Given: AB = BA …..(i) chapter 3-Matrices Miscellaneous Exercise/image019.png Now, we prove that the result is true for n = k + 1. chapter 3-Matrices Miscellaneous Exercise Therefore, the result is true for n = k + 1. Thus, by the principle of mathematical induction, we have (AB)’’ = A’’B’’, for all natural numbers. Question 13. If A = chapter 3-Matrices Miscellaneous Exercise/image122.png is such that A 2 = I, then: chapter 3-Matrices Miscellaneous Exercise/image123.png Solution : Given: chapter 3-Matrices Miscellaneous Exercise/image122.png and A 2 = I NCERT Solutions for Class 12 Math Chapter 3 - Matrices Equating corresponding entries, we haveTherefore, option (C) is correct. Question 14. If the matrix A is both symmetric and skew symmetric, then: (A) A is a diagonal matrix (B) A is a zero matrix (C) A is a square matrix (D) None of these Solution : Since, A is symmetric, therefore, A’ = A ……..(i) And A is skew-symmetric, therefore, A’ = – A A = – A  [From eq. (i)] A + A = 0 ⇒2A = 0  ⇒A = 0 Therefore, A is zero matrix. Therefore, option (B) is correct. Question 15. If A is a square matrix such that A 2 = A, then (I + A) 3 – 7A is equal to: (A) A (B) I – A (C) I (D) 3A Solution : Given: A 2 = A    …..(i) Multiplying both sides by A,  A 3 = A 2 = A [From eq. (i)]  ……(ii) Also given (I + A) 3 – 7A = I 3 + A 3 + 3I 2 A + 3IA 2 – 7A Putting A 2 = A [from eq. (i)] and A 3 = A [from eq. (ii)], = I + A + 3IA + 3IA – 7A = I + A + 3A + 3A – 7A   [ IA = A] = I + 7A – 7A = I Therefore, option (C) is correct.

NCERT Solution for Class 12 Maths Chapter 3 Miscellaneous Exercise FAQs

What types of problems are covered in the Miscellaneous Exercise for Class 12 Maths Chapter 3 on Matrices?

The Miscellaneous Exercise typically includes a variety of problems covering topics such as matrix operations, determinants, inverse of matrices, and applications of matrices.

How do you perform matrix multiplication, and what are the key rules to remember?

Matrix multiplication involves multiplying the elements of rows and columns following a specific pattern. The key rule is ensuring the number of columns in the first matrix matches the number of rows in the second matrix.

Can you explain the concept of the inverse of a matrix and its significance?

The inverse of a matrix is another matrix that, when multiplied with the original matrix, gives the identity matrix. It is crucial for solving systems of linear equations and other mathematical problems.

What are the steps involved in finding the inverse of a 2x2 matrix?

For a 2x2 matrix, the inverse can be found using a formula involving the determinant and matrix adjugate.

How are matrices used in real-life applications?

Matrices are used in various fields such as computer science, physics, economics, and engineering for tasks like solving systems of linear equations, image processing, and modeling.
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