CBSE Class 11 Maths Notes Chapter 10: CBSE Class 11 Maths Notes Chapter 10 Straight Lines is all about understanding lines in the coordinate plane.
The chapter covers various forms of equations that represent straight lines, making it easier to work with them. For instance, you'll learn about slope-intercept form, where the equation looks like y = mx + b, and point-slope form, which is useful for finding equations when you have a point and the slope of a line. There's the two-point form, handy when you have two points and need to find the equation of the line passing through them. Understanding these forms helps you draw and analyze lines better.CBSE Class 11 Maths Notes Chapter 10 PDF
The straight - line equation in slope-intercept form is given as:
Y = mx + C
Where m represents the slope of the line and C is the y-intercept.
The shortest straight line distance between two points say P and Q having coordinates (P₁, Q₁) and (P₂, Q₂) is expressed as:
Question: If the three lines 2x + y – 3 =0 , 5x + ky – 3 = 0 and 3x – y – 2 = 0 are concurrent then find the Value of k.
Solution: If three lines are said to be concurrent when they pass through a common point. It means that the point of intersection of two lines lies on the third line.
Given equation : 2x + y – 3 =0 ……(1) 5x + ky – 3 = 0 ……(2) 3x – y – 2 = 0 ……..(3) By solving the line equation (1) and (3) using cross multiplication method,Question: Find the equation of the line which is at a distance 3 from the origin and the perpendicular from the origin to the line makes on angle of 30 ∘ 30∘ with positive direction of x-axis
Solution: Given, p = 3 𝑝=3 and ω = 30 ∘ 𝜔=30∘
Equation of line is given by
Question: Find the angle between x-y=2 and x-3y=6.
Solution: Given lines: x − y = 2 𝑥−𝑦=2 and x − 3 y = 6 𝑥−3𝑦=6
Slopes are 1 and 1 3 13 .
Angle between the lines:
Question: Find the slope of the line passing through the point (-3,6) and the middle point of the line joining the points (4,-5) and (-2,9).
Solution: Mid-point of the line segment joining the points (4,−5)
and (−2,9) is (4−22,−5+92)=(1,2) Slope of the line passing through the points (1,2) and (−3,6) is m=6−2−3−1=4−4=−1.Understanding Basic Geometry : This chapter provides a foundational understanding of straight lines, which is fundamental to coordinate geometry and analytical geometry.
Graphical Representation : Learning about straight lines helps students understand how to plot and interpret graphs, which is essential for visualizing mathematical concepts.
Equation Forms : Understanding different forms of equations for straight lines, such as slope-intercept form, point-slope form, and two-point form, enhances problem-solving skills and flexibility in mathematical representations.
Geometric Concepts : Concepts like angle between two lines, distance between a point and a line, and collinearity of points deepen students' understanding of geometric properties and relationships.