RS Aggarwal Solutions Class 9 Maths Chapter 15 Volume and Surface Area of Solids
Here, we have provided RS Aggarwal Solutions Class 9 Maths Chapter 15. Students can view these RS Aggarwal Solutions Class 9 Maths Chapter 15 before exams for better understanding of the chapter.
Neha Tanna13 Apr, 2024
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RS Aggarwal Solutions Class 9 Maths Chapter 15: Being the first higher class in the students' lives and giving some weight to the academics of class 10, class 9 is crucial. For more advanced study in class 10, the majority of the 9th class chapters are extended.
Because maths is the hardest subject, it takes more practice than the other subjects combined. The topic of Chapter 15 Maths Class 9 RS Aggarwal is broad and encompasses several key ideas for the students. The RS Aggarwal solutions for the mensuration, volume, and surface area of solids in class 9 serve as a foundation for the extensive mensuration syllabus for class 10.RS Aggarwal Solutions Class 9 Maths Chapter 15 PDF
For students in the CBSE, we provide RS Aggarwal Maths Class 9 solutions chapter 15 so they can improve their learning resources and do well on their exams. Every idea in the class 9 curriculum must be thoroughly practiced by the students, as they are also useful in several competitive studies. Also, use our updated NCERT Book Solutions to review and complete the key problems for the Class 9 Maths (RS Aggarwal) exam.RS Aggarwal Solutions Class 9 Maths Chapter 15 PDF
RS Aggarwal Solutions Class 9 Maths Chapter 15
Here is Chapter 15 Solution by RS Aggarwal's class 9. Please use these as a reference only; do not duplicate the solutions. Maths is a practice topic. Use Physics Wallah's NCERT solutions for class 9 Maths to help you solve problems from the NCERT Exercise.RS Aggarwal Solutions Class 9 Maths Chapter 15 Exercise 15.1
Question 1.
Solution:
(i) length =12cm, breadth = 8 cm and height = 4.5 cm ∴ Volume of cuboid = l x b x h = (12 x 8 x 4.5) cm3= 432 cm3 ∴ Lateral surface area of a cuboid = 2(l + b) x h = [2(12 + 8) x 4.5] cm2 = (2 x 20 x 4.5) cm2 = 180 cm2 ∴ Total surface area cuboid = 2(lb +b h+ l h) = 2(12 x 8 + 8 x 4.5 + 12 x 4.5) cm2 = 2(96 +36 +54) cm2 = (2 x186) cm2 = 372 cm2 (ii) Length 26 m, breadth =14 m and height =6.5 m ∴ Volume of a cuboid = l x b x h = (26 x 14 x 6.5) m3 = 2366 m3 ∴ Lateral surface area of a cuboid =2 (l + b) x h = [2(26+14) x 6.5] m2 = (2 x 40 x 6.5) m2 = 520 m2 ∴ Total surface area = 2(lb+ bh + lh) = 2(26 x 14+14 x6.5 +26 x6.5) = 2 (364+91+169) m2 = (2 x 624) m2= 1248 m2 (iii) Length = 15 m, breadth = 6m and height = 5 dm = 0.5 m ∴ Volume of a cuboid = l x b x h = (15 x 6 x 0.5) m3=45 m3 ∴ Lateral surface area = 2(l + b) x h = [2(15 + 6) x 0.5] m2 = (2 x 21×0.5) m2=21 m2 ∴ Total surface area =2(lb+ bh + lh) = 2(15 x 6 +6 x 0.5+ 15 x 0.5) m2 = 2(90+3+7.5) m2 = (2 x 100.5) m2 =201 m2Question 2.
Solution:
Length of Cistern = 8 m Breadth of Cistern = 6 m And Height (depth) of the Cistern =2.5 m ∴ Capacity of the Cistern = Volume of cistern ∴ Volume of Cistern = (l x b x h) = (8 x 6 x2.5) m3 =120 m3 Area of the iron sheet required = Total surface area of the system. ∴ Total surface area = 2(lb +bh +lh) = 2(8 x 6 + 6×2.5+ 2.5×8) m2 = 2(48 + 15 + 20) m2 = (2 x 83) m2=166 m2Question 3.
Solution:
Length of a room =9m, Breadth of a room = 8m And height of the room = is 6.5 m ∴ Area of 4 walls = Lateral surface area = 2 (l+ b) x h = [2 (9+8) x 6.5] m2 = (2 x 17 x 6.5) m2 =221 m2 ∴ Area not be whitewashed = (area of 1 door) + (area of 2 windows) = (2 x 1.5) m2 + (2 x 1.5 x 1) m2 = 3m2 + 3m2 =6m2 ∴ Area to be whitewashed = (221-6) m2 =215 m2 ∴ The cost of whitewashing the walls at the rate of Rs.6.40 per Square meter = Rs. (6.40 x 215) = Rs. 1376
RS Aggarwal Solutions Class 9 Maths Chapter 15 Exercise 15.2
RS Aggarwal Solutions Class 9 Maths Chapter 15 Exercise 15.3
Benefits of RS Aggarwal Solutions Class 9 Maths Chapter 15
The RS Aggarwal Class 9th Maths Solutions are available for easy download to help you get ready for the academic year. These solutions include difficult exercises to help you understand the material and approach problems successfully and have been carefully chosen by professional professors. With every update, a fresh collection of problems from past years is added to the RS Aggarwal Class 9 Maths Solutions. This guarantees that the information you need for your preparation is up-to-date and pertinent.| CBSE Class 9 Maths Syllabus | CBSE Class 9 Science Syllabus |
| CBSE Class 9 Computer Application Syllabus | CBSE Class 9 Social Science Syllabus |
RS Aggarwal Solutions Class 9 Maths Chapter 15 FAQs
Which is the hardest chapter in maths class 9?
Some students find Geometry difficult whereas others may find the Surface area and Volume, Constructions or Statistics. But, in general, maximum students find Geometry as the most difficult topic. Also, under the geometry section Triangles is the most disliked chapter of class IX maths.
Which is better RS Aggarwal or RD Sharma?
Yes, both the books are standard and the best books for the Class 9 Mathematics.
Is RS Aggarwal easy?
Solving all the problems of RS Aggarwal is a privilege of the highest order! However, not all problems are easy to solve.
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