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ICSE Class 8 Maths Selina Solutions Chapter 14 Linear Equations in One Variable

In this article we have provided ICSE Class 8 Maths Selina Solutions Chapter 14 prepared by our experts to help students to prepare better for their examinations.
authorImageAnanya Gupta28 Jun, 2024
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ICSE Class 8 Maths Selina Solutions Chapter 14

ICSE Class 8 Maths Selina Solutions Chapter 14: ICSE Class 8 Maths Selina Solutions for Chapter 14, "Linear Equations in One Variable," provide detailed explanations and solutions to problems involving linear equations.

This chapter focuses on understanding and solving equations where there is only one variable. The solutions guide students through each step of the process, from setting up the equation to finding the value of the variable.

ICSE Class 8 Maths Selina Solutions Chapter 14 Overview

ICSE Class 8 Maths Selina Solutions for Chapter 14, "Linear Equations in One Variable," are prepared by subject experts from Physics Wallah. These solutions give clear, step-by-step explanations for solving equations with one variable.

These solutions are a great help for students, providing easy-to-follow instructions and lots of practice. This makes it easier to learn the basics of linear equations, which is important for more advanced math studies.

ICSE Class 8 Maths Selina Solutions Chapter 14 PDF

The PDF link provided below contains the ICSE Class 8 Maths Selina Solutions for Chapter 14, "Linear Equations in One Variable."

By following these solutions, students can easily understand how to set up and solve these equations, making it a valuable resource for exam preparation and strengthening their math skills. Download the PDF to access comprehensive guidance and practice problems for mastering linear equations.

ICSE Class 8 Maths Selina Solutions Chapter 14 Linear Equations in One Variable PDF

Linear Equations in One Variable

Linear equations in one variable are algebraic equations that involve a single variable, usually denoted by xx , and can be written in the form ax+b=0ax + b = 0 , where aa and bb are constants. The goal is to find the value of xx that makes the equation true. Here’s a detailed explanation with examples:

Understanding Linear Equations in One Variable

  • Form : The general form is ax+b=0ax + b = 0 .
  • Goal : Solve for xx by isolating it on one side of the equation.

Steps to Solve Linear Equations

  1. Simplify Both Sides : Combine like terms on both sides of the equation if necessary.
  2. Isolate the Variable : Move the terms involving the variable to one side and constant terms to the other side.
  3. Solve for the Variable : Divide or multiply to solve for the variable.

Example 1: Solving a Simple Linear Equation

3x+5=113x + 5 = 11

Answer Step-by-Step Solution :

  1. Subtract 5 from both sides: 3x+5−5=11−53x + 5 - 5 = 11 - 5 3x=63x = 6
  2. Divide by 3: x=63x = \frac{6}{3} x=2x = 2

ICSE Class 8 Maths Selina Solutions for Chapter 14 Linear Equations in One Variables Exercise 1

Below we have provided ICSE Class 8 Maths Selina Solutions Chapter 14 Linear Equations in One Variable for the ease of the students –

Solve the following equations:

Question 1

20 = 6+2x

Solution:-

Simplifying we get 20 = 6 + 2x 20 – 6 = 2x 14 = 2x 7 = x x = 7

Question 2

15 + x = 5x + 3

Solution:-

Simplifying we get 15 – 3 = 5x – x 12 = 4x 3 = x x = 3

Question 3

(3x+2)/(x−6) =−7

Solution:-

By cross multiplying 3x + 2 = – 7(x-6) 3x + 2 = -7x + 42 3x + 7x = 42 – 2 10x = 40 x = 4

Question 4

3a – = 2 (4 – a)

Solution:-

3a – 4 = 8 – 2a 3a + 2a = 8 + 4 5a = 12 a = 2.4

Question 5

3(b – 4) = 2 (4 – b)

Solution:-

3b – 12 = 8 – 2b 3b + 2b = 8 + 12 5b = 20 b = 20/5 b = 4

Question 6

(x+2)/9 = (x+4)/11

Solution:-

By cross multiplying 11(x+2) = 9(x+4) 11x + 22 = 9x + 36 11x – 9x = 36 – 22 2x =14 x = 14/2 ⇒ x = 7

Question 7

(x − 8)/5 = (x − 12)/9

Solution:-

By cross multiplying 9(x – 8) = x(x – 12) 9x – 72 = 5x – 60 9x – 5= -60 + 72 4x = 12 x = 12/4 x = 3

Question 8

5(8x + 3) = 9(4x + 7)

Solution:-

40x + 15 = 36x + 63 40x – 36x = 63 – 15 4x = 48 x = 48/4 x = 12

Question 9

3(x + 1) = 12 + 4 (x – 1)

Solution:-

3(x+1) = 12 + 4(x-1) 3x + 3 = 12 + 4x – 4 3x – 4x = 12 – 4 – 3 -x = 5 ⇒ x = – 5

Question 10

3x/4− ¼ (x − 20) = x/4 +32

Solution:-

3x/4 – x/4 + 5 = x/4 + 32 3x/4 – x/4 –x/4 = 32 − 5 (3x – x – x)/4 = 27 x/4 = 27 x = 27 × 4 x = 108

Question 11.

ICSE Class 8 Maths Selina Solutions Chapter 14 Image 1

Solution:-

ICSE Class 8 Maths Selina Solutions Chapter 14 Image 2 3a – a/5 = 27/5 + 1/5 (Multiplying each term by 5) ⇒ (3a × 5) – (a/5) × 5 = (27/5) × 5 + (1/5) × 5 15a – a = 27 + 1 14a = 28 a = 28/14 a = 2

Question 12.

x/3 −2½ = 4x/9 − 2x/3

Solution:-

x/3 – 5/2 = 4x/9 − 2x/3 Since, L.C.M. of denominators 3, 2, 9 and 3=18 [Multiplying each term by 18] ⇒ (x/3) × 18 – (5/2) × 18 = (4x/9) × 18 – (2x/3) × 18 6x -45 = 8x – 12x 6x + 12x – 8x = 45 18x – 8x = 45 10x = 45 x = 45/10 x = 4·5

Question 13:

(4(y + 2))/5 = 7 + 5y/13

Solution:-

(4y + 8)/5 = 7 + 5y/13 (4y + 8)/5 = (91 + 5y)/13 (By cross multiplying) 13(4y + 8) = 5(91 + 5y) 52y + 104 = 455 + 25y 52y – 25y = 455 – 104 27y = 351 y = 351/27 y = 13

Question 14.

(a + 5)/6 – (a + 1)/9 = (a + 3)/4

Solution:-

Since, L.C.M. of denominators 6, 9 and 4=36 Multiplying each term by 36 ⇒ ((a + 5)/6) × 36 – ((a + 1)/9) × 36 = ((a + 3)/4) × 36 6(a + 5) – 4(a + 1) = 9(a + 3) 6a + 30 – 4a – 4 = 9a + 27 6a – 4a – 9a = 27 -30 + 4 6a – 13a =1 -7a = 1 a = −1/7

Question 15:

(2x – 13)/5 – (x − 3)/11 = (x – 9)/5 + 1

Solution:-

(2x – 13)/5 – (x – 3)/11 = (x – 9)/5 + 11 Since, L.C.M. of denominators 5, 11, 5 and 1=55 ∴((2x − 13)/5) × 55 – ((x – 3)/11) × 55 = ((x – 9)/5) × 55 + (1/1) × 55 11(2x – 13) – 5(x – 3) = 11 (x – 9) + 55 22x – 143 – 5x + 15 = 71x – 99 + 55 22x – 5x – 11x = -99 + 55 + 143 – 15 6x = 198 – 114 6x = 84 x = 84/6 x = 14

Benefits of ICSE Class 8 Maths Selina Solutions for Chapter 14 Linear Equations in One Variable

  • Clear Explanations : The solutions provide detailed, step-by-step explanations for solving linear equations, making it easier for students to understand the process.
  • Conceptual Understanding : These solutions help students grasp the fundamental concepts of linear equations, such as isolating the variable and balancing both sides of the equation.
  • Problem-Solving Skills : Regular practice with these solutions enhances students' problem-solving skills, enabling them to tackle various types of linear equations with confidence.
  • Exam Preparation : The solutions are aligned with the ICSE curriculum, helping students prepare effectively for exams by practicing similar types of questions they might encounter.
  • Foundation for Advanced Topics : Mastering linear equations in one variable lays a strong foundation for more advanced mathematical topics, such as quadratic equations and algebraic expressions.
  • Self-Study Aid : The solutions are a valuable resource for self-study, allowing students to review and practice at their own pace, reinforcing their learning outside the classroom.
  • Error Correction : By comparing their answers with the provided solutions, students can identify and correct their mistakes, leading to better learning and retention.
ICSE Class 8 Maths Selina Solutions Chapter wise List
Chapter 1 Rational Numbers Chapter 10 Direct and Inverse Variations
Chapter 2 Exponents Powers Chapter 11 Algebraic Expressions
Chapter 3 Squares and Square Roots Chapter 12 Algebraic Identities
Chapter 4 Cubes and Cube Roots Chapter 13 Factorisation
Chapter 5 Playing With Number Chapter 14 Linear Equations in One Variable
Chapter 6 Sets Chapter 15 Linear Inequations
Chapter 7 Percent and Percentage Chapter 16 Understanding Shapes
Chapter 8 Profit Loss and Discount Chapter 17 Special Types of Quadrilaterals
Chapter 9 Simple and Compound Interest Chapter 18 Constructions
Chapter 19 Representing 3D in 2D Chapter 21 Surface Area, Volume and Capacity
Chapter 20 Area of Trapezium and Polygon Chapter 22 Data Handling

ICSE Class 8 Maths Selina Solutions Chapter 14 FAQs

How do you solve a linear equation in one variable?

To solve a linear equation in one variable, follow these steps: Simplify both sides of the equation (combine like terms). Isolate the variable term on one side of the equation. Solve for the variable by performing the necessary arithmetic operations.

What are some common mistakes to avoid when solving linear equations?

Common mistakes include: Not performing the same operation on both sides of the equation. Combining unlike terms incorrectly. Forgetting to distribute multiplication over addition or subtraction. Neglecting to check the solution by substituting it back into the original equation.

Why is it important to learn about linear equations in one variable?

earning about linear equations in one variable is crucial because it forms the foundation for more advanced algebraic concepts. It also develops critical problem-solving skills and is widely applicable in various real-life situations, such as budgeting, calculating distances, and understanding relationships between quantities.

What is a linear equation in one variable?

A linear equation in one variable is an algebraic equation that involves only one variable and can be written.
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