A cube number (or a cube) is a number you can write as a product of three equal factors of natural numbers. Formula: k=a×a×a=a³ (k and a stand for integers.)
Cube number results by multiplying an integer by itself three times.
Formula: a×a×a=a³=k (a and k stand for integers.)
To cube a number, just use it in a multiplication 3 times ...
question 1. What is 3 Cubed?
Solution: 3 Cubed = 3 × 3 × 3 = 27
Note: we write down "3 Cubed" as 33 (the little "3" means the number appears three times in multiplying)
4 cubed 
= 
43 
= 
4 × 4 × 4 
= 
64 
5 cubed 
= 
53 
= 
5 × 5 × 5 
= 
125 
6 cubed 
= 
63 
= 
6 × 6 × 6 
= 
216 
The Cube of a negative integer is always negative.
Example:
etc.
We have,
Hence,
For example:
The cube roots of a number x are the numbers y which satisfy the equation
y3 = x
A cube root of a number, denoted or x1/3, is a number a such that a3 = x. All real numbers (except zero) have exactly one real cube root and a pair of roots.
For example, the real cube root of 8 is 2, because 23 = 8.
A cube root goes the other direction:
3 cubed is 27, so the cube root of 27 is 3
3 

27 
The cube root of a number is ...... the special value that when cubed gives the original number.
The cube root of 27 is 3, because when 3 is cubed you get 27.
question 1. What is the Cube root of 125?
Solution: Well, we just happen to know that 125 = 5 × 5 × 5 (if you use 5 three times in a multiplication you will get 125) ...
... so the answer is 5
The Cube Root Symbol

This is the special symbol that means "cube root", it is the "radical"symbol (used for square roots) with a little three to mean cube root. 
You can use it like this: (you would say "the cube root of 27 equals 3")
You Can Also Cube Negative Numbers
Have a look at this:
If you cube 5 you get 125: 5 × 5 × 5 = 125
If you cube 5 you get 125: 5 × 5 × 5 = 125
So the cube root of 125 is 5
Perfect Cubes
The Perfect Cubes are the cubes of the whole numbers:

1 
2 
3 
4 
5 
6 
7 
8 
9 
10 
11 
12 
13 
14 
15 
etc 
Perfect Cubes: 
1 
8 
27 
64 
125 
216 
343 
512 
729 
1000 
1331 
1728 
2197 
2744 
3375 
... 
Cube Root Of A Negative Perfect Cube
Let a be positive integer. Then, (–a) is a negative integer. We know that
∴
Thus, cube root of (cube root of a3)
e.g.
∴
question 2. Cube Root Of A Product Of Integers
Solution: We have,
e.g.
= 5 x 4
= 20
question 3. Cube Root of A Rational Number
Solution: We have,
e.g.
question 4. The cube root operation is not associative or distributive with addition or subtraction.
question 5. The cube root operation is associative with exponentiation and distributive with multiplication and division if considering only real numbers, but not always if considering complex numbers, for example:
Properties of perfect cubes and cube roots:
question 6. The relationship between unit’s digit of cube and its cube root is as follows:
Unit’s digits of cube 
0,1,4,5,6,9 
2 
8 
3 
7 
Unit’s digit of cube root 
Same as that of unit’s digits of cube 
8 
2 
7 
3 
Shortcut method for finding the cube of a two digit number:
We have,
For finding the cube of a twodigit number with the tens digit = a and the unit s digit = b, we made four columns, headed by and




question 1. Find the cubes of 35 by the shortcut method.
Solution: Here a = 3 and b = 5




∴
question 2. Find the smallest whole number by which each of the following numbers must be divided to obtain a perfect cube:
(a) 81 (b) 128 (c) 135 (d) 192 (e) 704
Solution:(a) 81 = 3 × 3 × 3 × 3
The prime factor 3 does not appear in a group of three. So if we divide 81 by 3, then the prime factorisation of the quotient will not contain 3.
81 ÷ 3 = 3 × 3 × 3
Hence the smallest whole number by which 81 should be divided to make it perfect cube is 3.
(b) 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2
The prime factor 2 does not appear in a group of three. So if we divide 128 by 2, then the prime factorisation of the quotient will not contain 2.
128 ÷ 2 = 2 × 2 × 2 × 2 × 2 × 2
Hence the smallest whole number by which 128 should be divided to make it perfect cube is 2.
(c) 135 = 3 × 3 × 3 × 5
In the factorization 5 appears only one time. So if we divide 135 by 5, then the prime factorization of the quotient will not contain 5.
135 ÷ 5 = 3 × 3 × 3
Hence the smallest whole number by which 135 should be divided to make it perfect cube is 5.
(d) 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3
In the factorization 3 appears only one time. So, if we divide 192 by 3, then the prime factorization of the quotient will not contain 3.
192 ÷ 3 = 2 × 2 × 2 × 2 × 2 × 2
Hence, the smallest whole numbers by which 192 should be divided to make it perfect cube is 3.
(e) 704 = 2 × 2 × 2 × 2 × 2 × 2 × 11
In the factorization 11 appears only one time. So if we divide 704 by 11, then the prime factorization of the quotient will not contain 11.
704 ÷ 11 = 2 × 2 × 2 × 2 × 2 × 2
Hence the smallest whole number by which 704 should be divided to make it perfect cube is 11.
question 4. State true or false.
(a) Cube of any odd number is even
(b) A perfect cube does not end with two zeros
(c) If square of a number ends with 5, then its cube ends with 25.
(d) There is not perfect cube which ends with8.
(e) The cube of a two digit number may be a three digit number.
(f) The cube of a two digit number may have seven or more digits.
(g) The cube of a single digit number may be a single digit number.
Solution: (a) False (b) True (c) True (d) False
(e) False (f) False (g) True
question 5. Is 53240 a perfect cube? If not, then by which smallest natural number should 53240 be divided so that the quotient is a perfect cube?
Solution: 53240 = 2 × 2 × 2 × 11 × 11 × 11 × 5
The prime factor 5 does not appear in a group of three, So, 53240 is not a perfect cube. In the factorization 5 appears only one time. If we divide the number by 5, then the prime factorization of the quotient will not contain 5.
Hence the smallest number by which 53240 should be divided to make it a perfect cube is 5.
The perfect cube in that case is = 10648.
question 6. Observe the following pattern of sums of odd numbers:
1 = 1 = 13
3 + 5 = 8 = 23
7 + 9 + 11 = 27 = 33
13 + 15 + 17 + 19 = 64 = 43
21 + 23 + 25 + 27 + 29 = 125 = 53
31 + 33 + 35 + 37 + 39 + 41= 216 = 63
——————— = 343 = 73
——————— = 512 = 83
——————— = 729 = 93
——————— = 1000 = 103
Express the following numbers as the sum of odd numbers using the above pattern?
(a) 6^{3}
(b) 7^{3}
(c) 8^{3}
Solution: According to above pattern, we have
(a)
(b)
(c)
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