# NCERT Solutions for Class 8 Maths chapter 4 - Practical Geometry

**NCERT solutions for class 8 maths** chapter 4 Practical Geometry is prepared by academic team of Physics Wallah. We have prepared solutions for all exercise of chapter 4. Given below is step by step solutions of all questions given in NCERT textbook for chapter 4. Read chapter 4 theory make sure you have gone through the theory part of chapter 4 from NCERT textbook and you have learned the **maths formula** of the given chapter. Physics Wallah prepared a detail **class 8 notes** and additional questions for class 8 maths with short notes of all maths formula of class 8 maths. Do read these contents before moving to solve the exercise of NCERT chapter 4

### NCERT Solutions for Class 8 Maths Exercise 4.1

**Question 1.**

Construct the following quadrilaterals:(i) Quadrilateral ABCD

AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm,

AD = 6 cm, AC = 7 cm

(ii) Quadrilateral JUMP

JU = 3.5 cm, UM = 4 cm, MP = 5 cm,

PJ = 4.5 cm, PU = 6.5 cm

(iii) Parallelogram MORE

OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm

(iv) Rhombus BEST

BE = 4.5 cm, ET = 6 cm

**Solution :**

### NCERT Solutions for Class 8 Maths Exercise 4.2

**Question 1.**

Construct the following quadrilaterals:

(i) Quadrilateral LIFT

LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm, DE = 6.5 cm

**Solution :**

(i) Given:; LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm

To construct: A quadrilateral LIFT

Steps of construction:

(a) Draw a line segment LI = 4 cm.

(b) Taking radius 4.5 cm, draw an arc taking L as centre.

(c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.

(d) Join FI and FL.

(e) Draw another arc of radius 2.5 cm taking L as centre and 4 cm taking I as centre which intersect at T.

(f) Join TF, Tl and TI.

It is the required quadrilateral LIFT.

(ii) Given:; OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm

To construct: A quadrilateral GOLD

Steps of construction:

(a) Draw a line segment OL = 7.5 cm

(b) Draw an arc of radius 5 cm taking L as centre and another arc of radius 10 cm taking O as centre which intersect the first arc point at D.

(c) Join LD and OD.

(d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G.

(e) Join GD and GO.

It is the required quadrilateral GOLD.

(iii) Given:; BN = 5.6 cm, DE = 6.5 cm

To construct: A rhombus BEND.

Steps of construction:

(a) Draw DE = 6.5 cm.

(b) Draw perpendicular bisector of line segment DE.

(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.

(d) Join BE, BD as well as ND and NE.

It is the required rhombus BEND.

NCERT Solutions for Class 8 Maths Exercise 4.3

(i) Quadrilateral MORE

MO = 6 cm, OR = 4.5 cm,

∠ M = 60^{0 }; ∠ O =105^{0}; ∠R =105^{0}

(ii) Quadrilateral PLAN

PL = 4 cm, LA = 6.5 cm,

∠ P =90^{0}; ∠A = 110^{0}; ∠N =85^{0}

(iii) Parallelogram HEAR

HE = 5 cm, EA = 6 cm, ∠ R =85^{0}

(iv) Rectangle OKAY

OK = 7 cm, KA = 5 cm

**Solution :**

(i) Given:; MO = 6 cm, OR = 4.5 cm,

∠ M = 60^{0} ∠O =105^{0;} ∠R =105^{0}

To construct: A quadrilateral MORE.

Steps of construction:

(a) Draw a line segment MO = 6 cm.

(b) Construct ∠ R =; 105^{0 }and taking radius 4.5 cm, draw an arc taking O as centre, which intersects at R.

(c) Also construct an angle; at R and 105^{0;} produce the side RE.

(d) Construct another angle of; at point M and produce the side ME. Both sides ME and RE intersect at E.

It is the required quadrilateral MORE.

(ii) Given:; PL = 4 cm, LA = 6.5 cm,

∠ P = 90^{0;} ∠A = 110^{0 }∠N =85^{0}

To construct: A quadrilateral PLAN.

To find:; L =

Steps of construction:

(a) Draw a line segment PL = 4 cm.

(b) Construct angle of; at P and produce the side PN.

(c) Construct angle of; at L and with L as centre, draw an arc of radius 6 cm, which intersects at A.

(d) Construct A =; at A and produce the side AN which intersects PN at N.

It is the required quadrilateral PLAN.

;

(iii) Given:; HE = 5 cm, EA = 6 cm,

∠R =85^{0}

To construct: A parallelogram HEAR.

To find:; ∠H = 180º -85º = 95º

[ Sum of adjacent angle of || gm is 180º ]

Steps of construction:

(a) Draw a line segment HE = 5 cm.

(b) Construct H =; 95º and draw an arc of radius 6 cm with centre H. It intersects AR at R.

(c) Join RH.

(d) Draw ∠R = E = 85º and draw an arc of radius 6 cm with E as a centre which intersects RA at A.

(e) Join RA

It is the required parallelogram HEAR.

(iv) Given:; OK = 7 cm, KA = 5 cm

To construct: A rectangle OKAY.

Steps of construction:

(b) Construct angle; at both points O and K and produce these sides.

(c) Draw two arcs of radius 5 cm from points O and K respectively. These arcs intersect at Y and A.

(d) Join YA.

It is the required rectangle OKAY.

**NCERT Solutions for Class 8 Maths Exercise 4.4**

Draw the following:

**Question 1.**

The square READ with RE = 5.1 cm.

**Solution :**

Given:; RE = 5.1 cm.

To construct: A square READ.

Steps of construction:

(i) Draw RE = 5.1 cm.

(ii) At point E, construct an angle of; 90º and draw an arc of radius 5.1 cm, which intersects at point A.

(iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of radius 5.1 cm which intersects the first arc at point D.

(iv) Join AD and RD.

It is the required square READ.

**Question 2.**

A rhombus whose diagonals are 5.2 cm and 6.4 cm.

**Solution :**

Given:; Diagonals of a rhombus

AC = 5.2 cm and BD = 6.4 cm.

To construct: A rhombus ABCD.

Steps of construction:

(a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.

(b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.

(c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point O, which intersects at B and D.

(d) Join AB, BC, CD and DA.

It is required rhombus ABCD.

**Question 3.**

A rectangle with adjacent sides of length 5 cm and 4 cm.

**Solution :**

Given:; MN = 5 cm and MP = 4 cm.

To construct: A rectangle MNOP

Steps of construction:

(a) Draw a segment MN = 5 cm.

(b) At points M and N, draw perpendiculars of lengths 4 cm and produce them.

(c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q respectively.

(d) Join side PO.

It is required rectangle MNOP.

**Question 4.** A parallelogram OKAY where

OK = 5.5 cm and KA = 4.2 cm.

**Solution :**

Given:; OK = 5.5 cm and KA = 4.2 cm.

To construct: A parallelogram OKAY.

Steps of construction:

(a) Draw a line segment OK = 5.5 cm.

(b) Draw an angle of; at K and draw an arc of radius KA = 4.2 cm, which intersects at point A.

(c) Draw another arc of radius AY = 5.5 cm and at point O, draw another arc of radius 4.2 cm which intersect at Y.

(d) Join AY and OY.

It is the required parallelogram OKAY.

### NCERT Solutions for Class 8 Maths Exercise 4.5

Draw the following:

**Question 1.**

The square READ with RE = 5.1 cm.

**Solution :**

Given:; RE = 5.1 cm.

To construct: A square READ.

Steps of construction:

(i) Draw RE = 5.1 cm.

(ii) At point E, construct an angle of; 90^{0 }and draw an arc of radius 5.1 cm, which intersects at point A.

(iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of radius 5.1 cm which intersects the first arc at point D.

(iv) Join AD and RD.

It is the required square READ.

**Question 2.**

A rhombus whose diagonals are 5.2 cm and 6.4 cm.

**Solution :**

Given:; Diagonals of a rhombus

AC = 5.2 cm and BD = 6.4 cm.

To construct: A rhombus ABCD.

Steps of construction:

(a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.

(b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.

(c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point O, which intersects at B and D.

(d) Join AB, BC, CD and DA.

It is required rhombus ABCD.

**Question 3.**

A rectangle with adjacent sides of length 5 cm and 4 cm.

**Solution :**

Given:; MN = 5 cm and MP = 4 cm.

To construct: A rectangle MNOP

Steps of construction:

(a) Draw a segment MN = 5 cm.

(b) At points M and N, draw perpendiculars of lengths 4 cm and produce them.

(c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q respectively.

(d) Join side PO.

It is required rectangle MNOP.

**Question 4.**

A parallelogram OKAY where

OK = 5.5 cm and KA = 4.2 cm.

**Solution :**

Given:; OK = 5.5 cm and KA = 4.2 cm.

To construct: A parallelogram OKAY.

Steps of construction:

(a) Draw a line segment OK = 5.5 cm.

(b) Draw an angle of 90^{0} at K and draw an arc of radius KA = 4.2 cm, which intersects at point A.

(c) Draw another arc of radius AY = 5.5 cm and at point O, draw another arc of radius 4.2 cm which intersect at Y.

(d) Join AY and OY.

It is the required parallelogram OKAY

### Notes,worksheet and solved question for Maths class 8

- class 8 maths notes on chapter Liner equation in one variable
- class 8 maths notes on chapter algebric expression;
- class 8 maths notes on chapter Mensuration;
- class 8 maths notes on chapter Square and square roots;
- class 8 maths notes on chapter statistice
- class 8 maths notes on chapter practical Geometry
- class 8 maths notes on chapter commericial maths
- class 8 maths notes on chapter solid shape
- class 8 maths notes on chapter quadrilaterals
- class 8 maths notes on chapter exponents
- class 8 maths notes on chapter factorisation;
- class 8 maths notes on chapter inverse proporation;
- class 8 maths notes on chapter cube and cube roots;

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