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RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 (Exercise 10B)

Here, we have provided RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2. Students can view these RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 before exams for better understanding.
authorImageAnanya Gupta2 Aug, 2024
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RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2: RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 help students learn about profit and loss in an easy-to-understand way.

This exercise covers different problems involving profit, loss, and discounts. Each solution is broken down into simple steps making it easier for students to follow and understand. By practicing these solutions, students can improve their skills in handling real-life financial situations and get ready for their exams with more confidence.

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RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 Overview

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 provide a detailed overview of profit and loss problems with practical applications. This exercise focuses on various types of problems, including calculating profit percentages, loss percentages, and discount amounts. It guides students through the process of determining profit or loss based on given cost price and selling price, as well as applying discounts to marked prices. Each problem is explained with step-by-step solutions, ensuring students understand how to apply the concepts correctly. This exercise helps build a strong foundation in financial mathematics, making it easier for students to tackle similar problems in their exams.

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 PDF

The PDF for RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 is available below. This resource provides detailed solutions and explanations for various profit and loss problems, helping students understand key concepts and solve related exercises with confidence. By referring to this PDF students can access step-by-step solutions and gain a clearer grasp of how to handle questions involving profit percentages, loss percentages, and discounts. For easy access, download the PDF through the provided link to enhance your preparation and understanding of the chapter.

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 PDF

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 (Exercise 10B)

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 are available below. This resource provide detailed solutions and explanations for problems related to operations on profit and loss.

(1) The marked price of a water cooler is Rs 4650. The shopkeeper offers an off-season discount of 18% on it. Find its selling price.

(2)  The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season. Find the rate of discount given by him.

(3) Find the rate of discount being given on a shirt whose selling price is Rs 1092 after deducting a discount of Rs 208 on its marked price.

(4) After allowing a discount of 8% on a toy, it is sold for Rs 216.20. Find the marked price of the toy.

Solution: Selling price = Rs 216.20 Rate of discount = 8%

(5)  A tea set bought for Rs 528 after getting a discount of 12% on its marked price. Find the marked price of tea set.

(6) A dealer marks his goods at 35% above the cost price and allows a discount of 20% on the marked price. Find his gain or loss per cent.

Solution: Let the cost price be Rs 100. Then, the market price = Rs (100 + 35) = Rs 135

(7) A cellphone was marked at 40% above the cost price and discount of 30% was given on its marked price. Find the gain or loss per cent made by the shopkeeper.

Solution: Let the Cost price be Rs 100. Market price = Rs (100 + 40) = Rs 140

(8) A dealer purchased a fan for Rs 1080. After allowing a discount of 25% on its marked price, he gains 25%. Find the marked price of fan.

⇒ 75x = 135000 ⇒ x = 1800 Hence, the market price is Rs 1800.

(9) A dealer bought a refrigerator for Rs 11515. After allowing a discount of 16% on its marked price, he gains 20%. Find the marked price of the refrigerator.

⇒ 84x = 1381800 ⇒ x = 16450 Hence, the market price is Rs 16450.

(10) A jeweller allows a discount of 16% to his customers and still gains 20%. Find the marked price of a ring which costs the jeweller Rs 1190.

⇒ 84x = 142800 ⇒ x = 1700 Hence, the market price is Rs 1700.

(11) After allowing a discount of 10% on the marked price, a trader still makes a gain of 17%. By what per cent is the marked price above the cost price?

Solution: Let the cost price be Rs 100. Selling price = Rs (100 + 17) = Rs 117 Let the market price be Rs x. ⇒ x = 130 Hence, the market price is (130 – 100) = 30% above the cost price.

(12) How much per cent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 10% on the marked price, he gains 8%?

Solution: Let the cost price be Rs x. Selling price = Rs (100 + 8) = Rs 108 Let the market price be Rs x. Hence, the market price is (120 – 100) = 20% above the cost price.

(13) The marked price of TV is Rs 18500. A dealer allows two successive discounts of 20% and 5%. For how much is the TV available?

(14) Find the single discount which is equivalent to two successive discounts of 20% and 5%.

Solution: Let the market price be Rs 100.

Benefits of RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2

  • Clear Understanding : The solutions provide detailed, step-by-step explanations, helping students grasp the concepts of profit and loss more effectively.
  • Practice and Application : By working through these solutions students gain hands-on practice with different types of profit and loss problems, reinforcing their understanding and application of the concepts.
  • Enhanced Problem-Solving Skills : The exercise covers various scenarios and problem types, allowing students to develop and refine their problem-solving skills in financial mathematics.
  • Exam Preparation : The structured approach of the solutions helps students prepare better for exams by familiarizing them with the types of questions that may appear and how to approach them.
  • Confidence Building : With detailed explanations and solutions, students can build confidence in their ability to tackle profit and loss problems, reducing exam-related stress.
  • Time Efficiency : The clear solutions save time by providing direct and effective methods to solve problems, helping students complete their practice more efficiently.
  • Concept Reinforcement : The exercise helps reinforce key concepts related to profit, loss, and discounts, ensuring that students have a solid understanding before moving on to more complex topics.

RS Aggarwal Solutions for Class 8 Maths Chapter 10 Exercise 10.2 FAQs

What is covered in Exercise 10.2 of Chapter 10?

Exercise 10.2 covers problems related to profit and loss, including calculating profit percentages, loss percentages, and discounts on marked prices.

What if I don’t understand the explanation for a particular problem?

If you find any explanation unclear, refer to the detailed steps and worked-out examples provided in the solutions. You can also seek additional help from teachers or online resources for further clarification.

How can these solutions help with exam preparation?

These solutions provide practice with various problem types, reinforcing your understanding of profit and loss concepts, and providing strategies for solving similar problems in exams.

Can I use these solutions for self-study?

Yes, these solutions are designed for self-study, providing clear explanations and methods to practice and understand profit and loss problems on your own.
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