RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3:
For Class 8 Maths Chapter 18 Exercise 18.3 the solutions provided a clear and thorough approach to calculating the area of trapeziums and polygons.
This exercise builds on the foundational concepts from the chapter and helps solidify your understanding. The solutions guide you through each problem with step-by-step instructions, ensuring that you can apply the relevant formulas correctly and solve the exercises with confidence.
RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 Area Of A Trapezium And A Polygon Overview
Exercise 18.3 in RS Aggarwal's Class 8 Maths Chapter 18 focuses on calculating the area of trapeziums and various polygons. To solve these problems, start by identifying the shape and noting the dimensions provided, such as side lengths or heights.
For trapeziums, you need to understand the relationship between the parallel sides and the height. For polygons, recognize the number of sides and their lengths to apply the correct area calculation method.
The exercise guides you through each step, ensuring you accurately determine the area based on given dimensions. This practice helps build a strong foundation in geometry by applying theoretical concepts to practical problems. Reviewing solutions and checking your work will reinforce your understanding and accuracy.
RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 PDF
For RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 you can access the detailed PDF link below. This PDF contains comprehensive solutions and step-by-step explanations for the exercise, which focuses on calculating the area of trapeziums and polygons. Reviewing the solutions provided in the PDF will help you understand the problem-solving approach and apply the concepts effectively to similar problems. The PDF is a valuable resource for mastering this chapter and enhancing your understanding of geometric calculations.
RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 PDF
RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 (Ex 18C)
Below we have provided RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3 Area Of A Trapezium And A Polygon-
Tick (√) the correct answer in each of the following:
(Question 1) The parallel sides of a trapezium measure 14 cm and 18 cm and the distance between them is 9 cm. The area of the trapezium is
Ans: (b) 144 cm
2
(Question 2)
The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128
c
m
2
. The distance between the parallel sides is
(a) 9 cm (b) 7 cm
(c) 8 cm (d) 12.5 cm
(Question 3) The parallel sides of a trapezium are in the ratio 3 : 4 and the perpendicular distance between them is 12 cm. If the area of the trapezium is 630 cm
2
, then its shorter of the parallel sides is
Solution:
(a) 45 cm
Let the length of the parallel sides are 3x cm and 4x cm.
Hence, the lengths of the parallel sides are 45 cm and 60 cm.
Then, a shorter parallel side is 45 cm.
(Question 4) The area of a trapezium is 180 cm
2
and its height is 9 cm. If one the parallel side is longer than the other by 6 cm, the length of the longer of the parallel sides is
Solution:
(b) 23 cm
Let the lengths of the parallel sides are x cm and (x + 6) cm.
Then, the longer side is (17+6) = 23 cm
(Question 5) In the given figure, AB
∥
DC and DA
⊥
AB. If DC = 7 cm, BC = 10 cm, AB = 13 cm and CL
⊥ AB, the area of trap. ABCD is
Solution:
Given:
-
ABCD is a trapezium with AB∥DC and DA ⊥ AB
-
DC= 7cm, BC =10cm, AB= 13 cm and CL ⊥AB
To Find:
-
Draw the figure
-
Area of the trapezium
-
Pythagorean theorem
: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.
-
Area of Trapezium
= (1/2)(
Sum of Parallel sides
) x (
Distance b/w Parallel sides
)
Step 1:
Refer the attached figure
DA ⊥ AB and CL ⊥ AB Hence
DA = CL , DC = AL
Step 2:
AB = AL + LB
AB = DC + LB
13 = 7 + LB
LB = 6 cm
Step 3:
Using Pythagorean Theorem
BC² = CL² + LB²
=> 10² = CL² + 6²
=> CL = 8 cm
Hence DA = 8 cm
Step 4:
Find Area of Trapezium
= (1/2)(AB + DC ) x DA
= (1/2) (13 + 7 ) x 8
= 80 cm²
The
area of trapezium
is
80 cm²
Benefits of RS Aggarwal Solutions for Class 8 Maths Chapter 18 Exercise 18.3
-
Clear Explanations
: The solutions provide clear step-by-step explanations, helping students understand how to approach and solve problems related to the area of trapeziums and polygons.
-
Concept Reinforcement
: By working through these solutions students reinforce their understanding of geometric concepts and improve their problem-solving skills.
-
Practice and Confidence
: The exercise allows students to practice a variety of problems, which builds confidence and prepares them for exams.
-
Error Identification
: Solutions help students identify common mistakes and learn the correct methods, ensuring they avoid errors in future problems.
-
Exam Preparation
: Detailed solutions are useful for exam preparation, as they cover important types of questions and demonstrate effective problem-solving strategies.
