Emission and Line Spectrum of Hydrogen : Hey there, young scientists! Have you ever wondered what makes up the colourful lights we see in fireworks or neon signs? Or why do certain elements emit specific colours of light when heated or excited? Well, get ready to uncover the mysteries of hydrogen– the simplest and most abundant element in the universe – and its fascinating emission and line spectrum. In this article, we'll embark on an illuminating journey to understand how hydrogen atoms emit light and produce unique spectral lines, all explained in simple terms just for you.
Line Spectrum of Hydrogen : Line spectrum of hydrogen is observed due to excitation or de-exicitation of electron from one stationary orbit to another stationary orbit.
Let electron make transition from n 2 to n 1 ( n 2 > n 1 ) in a H-like sample
Series |
Discovered by |
Regions |
n 2 |
n 1 |
Lyman |
Lyman |
U.V. region |
n 2 = 2, 3, 4… |
n 1 = 1 |
Balmer |
Balmer |
Visible region |
n 2 = 3, 4, 5… |
n 1 = 2 |
Paschen |
Paschen |
Infra red (I.R.) |
n 2 = 4, 5, 6… |
n 1 = 3 |
Brackett |
Brackett |
I.R. region |
n 2 = 5, 6, 7… |
n 1 = 4 |
Pfund |
Pfund |
I.R. region |
n 2 = 6, 7, 8… |
n 1 = 5 |
Humphery |
Humphery |
Far I.R. region |
n 2 = 7, 8, 9… |
n 1 = 6 |
It is first spectral series of H.
It was found to be in ultraviolet region by Lyman in 1898.
For it value of n 1 = 1 and n 2 = 2, 3, 4 where ‘n 1 ’ is ground state and ‘n 2 ’ is called excited state of electron present in a H-atom.
where n
2
> 1 always.
The wavelength of marginal line (i.e. n
2
= ∞) =
for all series. So for lyman series
I st line of lyman series = 2 → 1
II nd line of lyman series = 3 → 1
Last line of lyman series = ∞ → 1
[10.2 eV ≤ (ΔE) lyman ≤ 13.6eV]
where n
2
> 3 always.
where n
2
> 4 always.
∙
where n
2
> 5 always.
∙
where n
2
> 6.
1.
In the spectrum of He
+
ion the wavelength of
line of Balamer series is
x
Å. What is the wavelength of
line of Brackett series.
Sol.:
2. A sample of He + ions in ground state absorbs the radiation of x Å. Subsequently, The sample emit radiation of 6 different wavelength. Calculate the value of x .
Sol.:
3. In a hydrogen spectrum if electron moves from 6 th to 2 nd by transition in multi steps then find out the number of lines in spectrum.
Sol.: Total number of lines = 4 + 3 + 2 + 1 + 0 = 10
Total number of lines =