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Worksheet for class 7 maths for chapter-5 Factorisation

Class 7 Maths Worksheets

Worksheet For Class 7 Maths Chapter - Factorisation

In mathematics, factorisation or factoring is defined as breaking or decomposition of an entity (for example, number, matrix, or polynomial) into another product, or common factors, which gives an original number or matrix when repeated together, etc. You will learn this lesson in your lower classes from 6 to 8.

This page consist of subjective questions worksheet for chapter Factorisation of class 7 Maths with detail solutions. Do follow all Class 7 Maths Worksheet prepared by expert faculty members of Physics Wallah.

Before solving worksheet do solve questions of NCERT Text book with the help of Physics Wallah NCERT solutions for class 7 Maths. For additional information related to the subject you can check the Maths Formula section. 

Solved Example:

Q1. Find the H.C.F. of

  1. 6ab2 and 9a2b2
  2. 15x2 y3z4, 20x3 y4z5 and 25x4 y5z6

Solution:

1. H.C.F. of 6ab2 and 9a2b2

= (H.C.F of 6 and 9) x (H.C.F. of ab2 and a2b2)

= 3 ab2

2. H.C.F. of 15x2 y3 z4 ,20x3 y4z5 and 25x4 y5z6

= (H.C.F of 15, 20 and 25) x (x2 y3z4, x3 y4z5 and x4 y5z6 )

= 5x2 y3z4

Q2. Find the H.C.F. of

  1. 6ab2 and 9a2b2
  2. 5x2 y3z4, 20x3 y4z5 and 25x4 y5z6

Solution:

1. H.C.F. of 6ab2 and 9a2b2

= (H.C.F of 6 and 9) x (H.C.F. of ab2 and a2b2)

= 3 ab2

2. H.C.F. of 15x2 y3 z4 ,20x3 y4z5 and 25x4 y5z6

= (H.C.F of 15, 20 and 25) x (x2 y3z4, x3 y4z5 and x4 y5z6 )

= 5x2 y3z4

Q3. Factorise:

  1. 4x2 y + 12 y
  2. 3a2b + 6ab - 24a
  3. 36a3b - 60a2bc
  4. 6xy2 + 9x2 y - 24xy

Solution:

1. H.C.F. of 4x2 y and 12y is 4y

So, 4y is a common factor of each term.

4x2 y + 12y = 4y(x2 + 3)

2. H.C.F. of 3a2b, 6ab and 24a is 3a

3a2b - 6ab -24a = 3a(ab + 2b - 8)

3. H.C.F. of 36a3b and 60a2bc is 12a2b

36a3b - 60a2bc = 12a2b(3a - 5c)

4. H.C.F. of 6xy2,9x2 y and 24xy is 3xy

6xy2 + 9x2 y - 24xy = 3xy(2y + 3x - 8)

Q4. Factorise:

  1. 4x(a + 3b) - 7 y(a + 3b)
  2. a(a3 + 2) - 2(a3 + 2)
  3. 9(x + 2y)3 + 6(x + 2y)2
  4. a(a - b)3 + 3a2b(a - b)

Solution:

1. 4x(a + 3b) - 7 y(a + 3b) = (a + 3b) (4x - 7y)

2. a(a3 + 2) - 2(a3 + 2) = (a3 + 2)(a - 2)

3. 9(x + 2y)3 + 6(x + 2y)2 = 3(x + 2y)2 [3(x + 2 y) + 2]

= 3(x + 2y)2 (3x +6y + 2 )

4. a(a - b)3 + 3a2b(a - b) = a(a - b) [(a - b)2 + 3ab]

= a(a - b)(a2 - 2ab + b2 + 3ab)

= a(a - b)(a2 + ab + b2)

Also Check

  1. RS Aggarwal Class 7 solutions for Maths
  2. Factorisation Mind Map

 

Find below the worksheet-5 for chapter Factorisation











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