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NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 Continuity and Differentiability

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 are created by our experts to help students to understand the concepts of the chapter better. Solve these questions to ace your examinations.
authorImageKrati Saraswat18 Jan, 2024
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NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 (Continuity and Differentiability)

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 Continuity and Differentiability is prepared by the academic team of Physics Wallah. We have prepared NCERT Solutions for all exercises of Chapter 5. Given below is step by step solutions of all questions given in NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 Continuity and Differentiability.

NCERT Solutions for Class 12 Maths Chapter 5 Miscellaneous Exercise

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 Overview

NCERT Solutions for Class 12 Maths Chapter 5 contains all the important topics for the exams. Our experts created these questions for the students to ace the examination. This article contains all the important questions and their easy to understand answers for the better understanding. Students are advised to go through these questions to clarify their concepts better. These questions are created to help students in the better understanding of the NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1

Solve The Following Questions NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 Continuity and Differentiability:

Question 1. Prove that the function f(x) = 5x - 3 is continuous at x = 0, at  x = - 3 and x = 5 Solution : chapter 5-Continuity & Differentiability Exercise 5.1

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.2

Question 2. Examine the continuity of the function f(x) = 2x 2 - 1 at x = 3 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 Thus, f is continuous at x = 3

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.3

Question 3. Examine the following functions for continuity. (a) chapter 5-Continuity & Differentiability Exercise 5.1 (c) chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 chapter 5-Continuity & Differentiability Exercise 5.1 chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all real numbers greater than 5. Hence, f is continuous at every real number and therefore, it is a continuous function.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.4

Question 4. Prove that the function f(x) = x n is continuous at x = n, where n is a positive integer. Solution : The given function is f (x) = xn It is evident that f is defined at all positive integers, n, and its value at n is nn. chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at n, where n is a positive integer.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.5

Question 5. Is the function f defined by chapter 5-Continuity & Differentiability Exercise 5.1 continuous at x = 0? At x = 1? At x = 2? Solution : The given function f is chapter 5-Continuity & Differentiability Exercise 5.1 At x = 0, It is evident that f is defined at 0 and its value at 0 is 0. chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at x = 0 At x = 1, f is defined at 1 and its value at 1 is 1. The left hand limit of f at x = 1 is, chapter 5-Continuity & Differentiability Exercise 5.1 The right hand limit of f at x = 1 is, chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is not continuous at x = 1 At x = 2, f is defined at 2 and its value at 2 is 5. chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at x = 2

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

Question 6. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 It is observed that the left and right hand limit of f at x = 2 do not coincide. Therefore, f is not continuous at x = 2 Hence, x = 2 is the only point of discontinuity of f.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.7

Question 7. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : The given function f is chapter 5-Continuity & Differentiability Exercise 5.1 The given function f is defined at all the points of the real line. Let c be a point on the real line. Case I: chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x, such that x < −3 Case II: chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at x = −3 Case III: chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous in (−3, 3). Case IV: If c = 3, then the left hand limit of f at x = 3 is, chapter 5-Continuity & Differentiability Exercise 5.1 The right hand limit of f at x = 3 is, chapter 5-Continuity & Differentiability Exercise 5.1 It is observed that the left and right hand limit of f at x = 3 do not coincide. Therefore, f is not continuous at x = 3 Case V: chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x, such that x > 3 Hence, x = 3 is the only point of discontinuity of f.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.8

Question 8. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 chapter 5-Continuity & Differentiability Exercise 5.1

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.3

Question 9. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.4

Question 10. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x , such that x > 1 Hence, the given function f has no point of discontinuity.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.5

Question 11. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x, such that x > 2 Thus, the given function f is continuous at every point on the real line. Hence, f has no point of discontinuity.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

Question 12. Find all points of discontinuity of f, where f is defined by chapter 5-Continuity & Differentiability Exercise 5.1 Solution : The given function f is chapter 5-Continuity & Differentiability Exercise 5.1 The given function f is defined at all the points of the real line. Let c be a point on the real line. chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x, such that x > 1 Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.7

Question 13. Is the function defined by chapter 5-Continuity & Differentiability Exercise 5.1 a continuous function? Solution : The given function is chapter 5-Continuity & Differentiability Exercise 5.1 The given function f is defined at all the points of the real line. Let c be a point on the real line. Case I: chapter 5-Continuity & Differentiability Exercise 5.1 Therefore, f is continuous at all points x, such that x > 1 Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.8

Question 14. Discuss the continuity of the function f, where f is defined by f = NCERT Solutions class 12 Continuity & Differentiability Solution : The given function is f = NCERT Solutions class 12 Continuity & Differentiability The given function is defined at all points of the interval [0, 10]. Let c be a point in the interval [0, 10]. Case I: NCERT Solutions class 12 Continuity & Differentiability NCERT Solutions class 12 Continuity & Differentiability Therefore, f is continuous at all points of the interval (3, 10]. Hence, f is not continuous at x = 1 and x = 3 Question 15. Discuss the continuity of the function f, where f is defined by NCERT Solutions class 12 Continuity & Differentiability Solution : The given function is NCERT Solutions class 12 Continuity & Differentiability The given function is defined at all points of the real line. Let c be a point on the real line. Case I: NCERT Solutions class 12 Continuity & Differentiability NCERT Solutions class 12 Continuity & Differentiability Question 16. Discuss the continuity of the function f, where f is defined by NCERT Solutions class 12 Continuity & Differentiability Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability The given function is defined at all points of the real line. Let c be a point on the real line. Case I: NCERT Solutions class 12 Continuity & Differentiability NCERT Solutions class 12 Continuity & Differentiability Therefore, f is continuous at all points x, such that x > 1 Thus, from the above observations, it can be concluded that f is continuous at all points of the real line. Question 17. Find the relationship between a and b so that the function f defined by NCERT Solutions class 12 Continuity & Differentiability is continuous at x = 3. Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability If f is continuous at x = 3, then NCERT Solutions class 12 Continuity & Differentiability Question 18. For what value of λ is the function defined by NCERT Solutions class 12 Continuity & Differentiability continuous at x = 0? What about continuity at x = 1? Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability If f is continuous at x = 0, then NCERT Solutions class 12 Continuity & Differentiability Therefore, for any values of λ, f is continuous at x = 1 Question 19. Show that the function defined by Chapter%205_html_m40f6c85a.gif is discontinuous at all integral point. Here [denotes the greatest integer less than or equal to x. Solution : The given function is Chapter%205_html_m40f6c85a.gif It is evident that g is defined at all integral points. Let n be an integer. Then, NCERT Solutions class 12 Continuity & Differentiability It is observed that the left and right hand limits of f at x = n do not coincide. Therefore, f is not continuous at x = n Hence, g is discontinuous at all integral points. Question 20. Is the function defined by NCERT Solutions class 12 Continuity & Differentiability/add3190.gif continuous at x = π ? Solution : The given function is NCERT Solutions class 12 Continuity & Differentiability/add3190.gif It is evident that f is defined at x = π NCERT Solutions class 12 Continuity & Differentiability Therefore, the given function f is continuous at x = π Question 21. Discuss the continuity of the following functions. (a) f (x) = sin x + cos x (b) f (x) = sin x − cos x (c) f (x) = sin x × cos x Solution : It is known that if g and h are two continuous functions, then g + h, g - h and g.h  are also continuous. It has to proved first that g (x) = sin x and h (x) = cos x are continuous functions. Let g (x) = sin x It is evident that g (x) = sin x is defined for every real number. Let c be a real number. Put x = c + h If x → c, then h → 0 NCERT Solutions class 12 Continuity & Differentiability Therefore, g is a continuous function. Let h (x) = cos x It is evident that h (x) = cos x is defined for every real number. Let c be a real number. Put x = c + h If x → c, then h → 0 h (c) = cos c NCERT Solutions class 12 Continuity & Differentiability Therefore, h is a continuous function. Therefore, it can be concluded that (a) f (x) = g (x) + h (x) = sin x + cos x is a continuous function (b) f (x) = g (x) − h (x) = sin x − cos x is a continuous function (c) f (x) = g (x) × h (x) = sin x × cos x is a continuous function Question 22. Discuss the continuity of the cosine, cosecant, secant and cotangent functions, Solution : It is known that if g and h are two continuous functions, then It has to be proved first that g (x) = sin x and h (x) = cos x are continuous functions. Let g (x) = sin x It is evident that g (x) = sin x is defined for every real number. Let c be a real number. Put x = c + h If x → c, then h → 0 NCERT Solutions class 12 Continuity & Differentiability Therefore, g is a continuous function. Let h (x) = cos x It is evident that h (x) = cos x is defined for every real number. Let c be a real number. Put x = c + h If x → c, then h → 0 h (c) = cos c NCERT Solutions class 12 Continuity & Differentiability Therefore, h (x) = cos x is continuous function. It can be concluded that, NCERT Solutions class 12 Continuity & Differentiability Question 23. Find the points of discontinuity of f, where NCERT Solutions class 12 Continuity & Differentiability/24e9506.gif Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability/24e9506.gif It is evident that f is defined at all points of the real line. Let c be a real number. Case I: NCERT Solutions class 12 Continuity & Differentiability/f62ef9c.gif Therefore, f is continuous at x = 0 From the above observations, it can be concluded that f is continuous at all points of the real line. Thus, f has no point of discontinuity. Question 24. Determine if f defined by NCERT Solutions class 12 Continuity & Differentiability/f52e85.gif is a continuous function? Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability/f52e85.gif It is evident that f is defined at all points of the real line. Let c be a real number. Case I: NCERT Solutions class 12 Continuity & Differentiability Therefore, f is continuous at x = 0 From the above observations, it can be concluded that f is continuous at every point of the real line. Thus, f is a continuous function. Question 25. Examine the continuity of f, where f is defined by NCERT Solutions class 12 Continuity & Differentiability Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability It is evident that f is defined at all points of the real line. Let c be a real number. Case I: NCERT Solutions class 12 Continuity & Differentiability Therefore, f is continuous at x = 0 From the above observations, it can be concluded that f is continuous at every point of the real line. Thus, f is a continuous function. Question 26. Find the values of k so that the function f is continuous at the indicated point. NCERT Solutions class 12 Continuity & Differentiability Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability The given function f is continuous at x = π/2 , if f is defined at x = π/2 and if the value of the f at x = π/2 equals the limit of f at x = π/2 . It is evident that f is defined at x = π/2 and f( π/2) = 3 NCERT Solutions class 12 Continuity & Differentiability Therefore, the required value of k is 6. Question 27. Find the values of k so that the function f is continuous at the indicated point. NCERT Solutions class 12 Continuity & Differentiability Solution : The given function is NCERT Solutions class 12 Continuity & Differentiability The given function f is continuous at x = 2, if f is defined at x = 2 and if the value of f at x = 2 equals the limit of f at x = 2 It is evident that f is defined at x = 2 and f(2) = k(2) 2 = 4k NCERT Solutions class 12 Continuity & Differentiability Therefore, the required value of k is 3/4. Question 28. Find the values of k so that the function f is continuous at the indicated point. NCERT Solutions class 12 Continuity & Differentiability Solution : The given function is NCERT Solutions class 12 Continuity & Differentiability The given function f is continuous at x = p, if f is defined at x = p and if the value of f at x = p equals the limit of f at x = p It is evident that f is defined at x = p and f(π) = kπ + 1 NCERT Solutions class 12 Continuity & Differentiability Therefore, the required value of k is -2/π Question 29. Find the values of k so that the function f is continuous at the indicated point. NCERT Solutions class 12 Continuity & Differentiability Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability The given function f is continuous at x = 5, if f is defined at x = 5 and if the value of f at x = 5 equals the limit of f at x = 5 It is evident that f is defined at x = 5 and f(5) = kx + 1 = 5k + 1 NCERT Solutions class 12 Continuity & Differentiability Therefore, the required value of k is 9/5 Question 30. Find the values of a and b such that the function defined by NCERT Solutions class 12 Continuity & Differentiability is a continuous function. Solution : The given function f is NCERT Solutions class 12 Continuity & Differentiability It is evident that the given function f is defined at all points of the real line. If f is a continuous function, then f is continuous at all real numbers. In particular, f is continuous at x = 2 and x = 10 Since f is continuous at x = 2, we obtain NCERT Solutions class 12 Continuity & Differentiability Therefore, the values of a and b for which f is a continuous function are 2 and 1 respectively. Question 31. Show that the function defined by f (x) = cos (x 2 ) is a continuous function. Solution : The given function is f (x) = cos (x 2 ) This function f is defined for every real number and f can be written as the composition of two functions as, f = g o h, where g (x) = cos x and h (x) = x 2 NCERT Solutions class 12 Continuity & Differentiability It has to be first proved that g (x) = cos x and h (x) = x 2 are continuous functions. It is evident that g is defined for every real number. Let c be a real number. Then, g (c) = cos c NCERT Solutions class 12 Continuity & Differentiability Therefore, g (x) = cos x is continuous function. h (x) = x 2 Clearly, h is defined for every real number. Let k be a real number, then h (k) = k 2 NCERT Solutions class 12 Continuity & Differentiability/29f05e7.gif Therefore, h is a continuous function. It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c. Therefore, h is a continuous function. Question 32. Show that the function defined by f(x) = |cos x| is a continuous function. Solution : The given function is f(x) = |cos x| This function f is defined for every real number and f can be written as the composition of two functions as, f = g o h, where g(x) = |x| and h(x) = cos x NCERT Solutions class 12 Continuity & Differentiability It has to be first proved that g(x) = |x| and h(x) = cos x are continuous functions. NCERT Solutions class 12 Continuity & Differentiability Clearly, g is defined for all real numbers. Let c be a real number. Case I: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at all points x, such that x < 0 Case II: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at all points x, such that x > 0 Case III: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at x = 0 From the above three observations, it can be concluded that g is continuous at all points. h (x) = cos x It is evident that h (x) = cos x is defined for every real number. Let c be a real number. Put x = c + h If x → c, then h → 0 h (c) = cos c NCERT Solutions class 12 Continuity & Differentiability Therefore, h (x) = cos x is a continuous function. It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c. Therefore, NCERT Solutions class 12 Continuity & Differentiability is a continuous function. Question 33. Examine that sin|x| is a continuous function. Solution : Let, f(x) = sin|x| This function f is defined for every real number and f can be written as the composition of two functions as, f = g o h, where g (x) = |x| and h (x) = sin x NCERT Solutions class 12 Continuity & Differentiability It has to be proved first that g (x) = |x| and h (x) = sin x are continuous functions. NCERT Solutions class 12 Continuity & Differentiability Clearly, g is defined for all real numbers. Let c be a real number. Case I: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at all points x, such that x < 0 Case II: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at all points x, such that x > 0 Case III: NCERT Solutions class 12 Continuity & Differentiability Therefore, g is continuous at x = 0 From the above three observations, it can be concluded that g is continuous at all points. h (x) = sin x It is evident that h (x) = sin x is defined for every real number. Let c be a real number. Put x = c + k If x → c, then k → 0 h (c) = sin c NCERT Solutions class 12 Continuity & Differentiability Therefore, h is a continuous function. It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c. Therefore, NCERT Solutions class 12 Continuity & Differentiability is a continuous function. Question 34. Find all the points of discontinuity of f defined by f(x) = |x| - |x + 1|. Solution : The given function is f(x) = |x| - |x + 1| The two functions, g and h, are defined as NCERT Solutions class 12 Continuity & Differentiability NCERT Solutions class 12 Continuity & Differentiability Therefore, h is continuous at x = −1 From the above three observations, it can be concluded that h is continuous at all points of the real line. g and h are continuous functions. Therefore, f = g − h is also a continuous function. Therefore, f has no point of discontinuity.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.1 FAQs

What are the conditions for continuity and differentiability?

If f is differentiable at x=a, then f is continuous at x=a. Equivalently, if f fails to be continuous at x=a, then f will not be differentiable at x=a. A function can be continuous at a point, but not be differentiable there.

What are the 3 conditions of continuity?

The three conditions of continuity are as follows: The function is expressed at x = a. The limit of the function as the approaching of x takes place, a exists. The limit of the function as the approaching of x takes place, a is equal to the function value f(a).

What is the SI unit of equation of continuity?

the continuity equation can be written as, A × v = constant. In this equation A indicates the area of cross section of the fluid and v indicates the speed. SI unit of A is m² and SI unit of v is m/s.

What is the concept of continuity?

A function is said to be continuous in a given interval if there is no break in the graph of the function in the entire interval range.

Is continuity necessary for integration?

Every continuous function is integrable, but there are integrable functions which are not continuous.
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