RD Sharma Solutions for Class 6 Maths Chapter 6 Exercise 6.8 provide students with clear and detailed methods to master the addition and subtraction of fractions, including mixed numbers.
This exercise focuses on simplifying fractions by combining denominators, converting mixed numbers into improper fractions, and solving practical word problems involving fractional quantities.
With step-by-step solutions, students can easily understand how to perform these operations accurately, build confidence in handling fractions, and apply these skills to real-life scenarios effectively.
The solutions also emphasize simplifying the final answers to their lowest terms, ensuring a strong grasp of fraction concepts.
RD Sharma Solutions for Class 6 Maths Chapter 6 Exercise 6.8 Introduction
Exercise 6.8 focuses on the addition and subtraction of fractions, including mixed numbers and word problems. The exercise helps students practice combining fractions with denominators and converting mixed numbers into improper fractions for easier calculations.
Key Concepts Covered:
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Writing fractions as sums or differences
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Adding and subtracting fractions with the same denominator
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Simplifying the results to their lowest terms
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Handling mixed numbers by converting them to improper fractions
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Solving word problems involving fractional quantities
RD Sharma Solutions for Class 6 Chapter 6 Fractions Exercise 6.8
Here are the detailed solutions for RD Sharma Class 6 Maths Chapter 6 Exercise 6.8 on Fractions.
1. Write these fractions appropriately as additions or subtractions:
Solution:
(i) It can be written as
1/5 + 2/5 = 3/5
(ii) It can be written as
3/6 + 2/6 = 5/6
2. Solve:
(i) 5/12 + 1/12
(ii) 3/15 + 7/15
(iii) 3/22 + 7/22
(iv) 1/4 + 0/4
(v) 4/13 + 2/13 + 1/13
(vi) 0/15 + 2/15 + 1/15
(vii) 7/31 – 4/31 + 9/31
(viii) 3 2/7 + 1/7 – 2 3/7
(ix) 2 1/3 – 1 2/3 + 4 1/3
(x) 1 – 2/3 + 7/3
(xi) 16/7 – 5/7 + 9/7
Solution:
(i) 5/12 + 1/12
It can be written as
5/ 12 + 1/12 = (5 + 1)/ 12
On further calculation
5/ 12 + 1/12 = 6/12 = 1/2
(ii) 3/15 + 7/15
It can be written as
3/15 + 7/15 = (3 + 7)/ 15
On further calculation
3/15 + 7/15 = 10/15 = 2/3
(iii) 3/22 + 7/22
It can be written as
3/22 + 7/22 = (3 + 7)/ 22
On further calculation
3/22 + 7/22 = 10/22 = 5/11
(iv) 1/4 + 0/4
It can be written as
1/4 + 0/4 = (1 + 0)/4
On further calculation
1/4 + 0/4 = ¼
(v) 4/13 + 2/13 + 1/13
It can be written as
4/13 + 2/13 + 1/13 = (4 + 2 + 1)/ 13
On further calculation
4/13 + 2/13 + 1/13 = 7/13
(vi) 0/15 + 2/15 + 1/15
It can be written as
0/15 + 2/15 + 1/15 = (0 + 2 + 1)/ 15
On further calculation
0/15 + 2/15 + 1/15 = 3/15 = 1/5
(vii) 7/31 – 4/31 + 9/31
It can be written as
7/31 – 4/31 + 9/31 = (7 – 4 + 9)/ 31
On further calculation
7/31 – 4/31 + 9/31 = 12/31
(viii) 3 2/7 + 1/7 – 2 3/7
It can be written as
3 2/7 + 1/7 – 2 3/7 = (23 + 1 – 17)/ 7
On further calculation
3 2/7 + 1/7 – 2 3/7 = 7/7 = 1
(ix) 2 1/3 – 1 2/3 + 4 1/3
It can be written as
2 1/3 – 1 2/3 + 4 1/3 = (7 – 5 + 13)/ 3
On further calculation
2 1/3 – 1 2/3 + 4 1/3 = 15/3 = 5
(x) 1 – 2/3 + 7/3
It can be written as
1 – 2/3 + 7/3 = (3 – 2 + 7)/3
On further calculation
1 – 2/3 + 7/3 = 8/3
(xi) 16/7 – 5/7 + 9/7
It can be written as
16/7 – 5/7 + 9/7 = (16 – 5 + 9)/ 7
On further calculation
16/7 – 5/7 + 9/7 = 20/7
3. Shikha painted 1/5 of the wall space in her room. Her brother Ravish helped and painted 3/5 of the wall space. How much did they paint together? How much the room is left unpainted?
Solution:
Fraction of wall space painted by Shikha = 1/5
Fraction of wall space painted by Ravish = 3/5
So the wall space painted by both = 1/5 + 3/5
= (1+3)/5
= 4/5
We get the unpainted space = (5 – 4)/ 5 = 1/5
Therefore, Shikha and Ravish painted 4/5 of the wall space together and the room space left unpainted is 1/5.
4. Ramesh bought 2 ½ kg sugar whereas Rohit bought 3 ½ kg of sugar. Find the total amount of sugar bought by both of them.
Solution:
Sugar bought by Ramesh = 2 ½ kg
It can be written as
Sugar bought by Ramesh = ((2 × 2) + 1)/ 2 = 5/2 kg
Sugar bought by Rohit = 3 ½ kg
It can be written as
Sugar bought by Rohit = ((2 × 3) + 1)/ 2 = 7/2 kg
So the total sugar bought by both of them = Sugar bought by Ramesh + Sugar bought by Rohit
By substituting the values
Total sugar bought by both of them = 5/2 + 7/2 = 12/2 = 6kg
Therefore, the total amount of sugar bought by both of them is 6kg.
5. The teacher taught 3/5 of the book, Vivek revised 1/5 more on his own. How much does he still have to revise?
Solution:
We know that
Fraction of book teacher taught = 3/5
Fraction of book Vivek revised = 1/5
So the fraction of book Vivek still have to revise = 3/5 – 1/5
= (3 – 1)/ 5
= 2/5
Hence, Vivek still have to revise 2/5 of the book.
6. Amit was given 5/7 of a bucket of oranges. What fraction of oranges was left in the basket?
Solution:
We know that
Fraction of oranges Amit has = 5/7
So the fraction of oranges left in the basket = 1 – 5/7
= (7 – 5)/ 7
= 2/7
Hence, the fraction of oranges left in the basket is 2/7.
7. Fill in the missing fractions:
(i) 7/10 – ☐ = 3/10
(ii) ☐ – 3/21 = 5/21
(iii) ☐ – 3/6 = 3/6
(iv) ☐ – 5/27 = 12/27
Solution:
(i) 7/10 – ☐ = 3/10
It can be written as
7/10 – 3/10 = ☐
We get
(7 – 3)/ 10 = 2/5
(ii) ☐ – 3/21 = 5/21
It can be written as
☐ = 5/21 + 3/21
We get
(5 + 3)/ 21 = 8/21
(iii) ☐ – 3/6 = 3/6
It can be written as
☐ = 3/6 + 3/6
We get
(3 + 3)/ 6 = 6/6 = 1
(iv) ☐ – 5/27 = 12/27
It can be written as
☐ = 12/27 + 5/27
We get
(12 + 5)/ 27 = 17/27
RD Sharma Solutions for Class 6 Maths Chapter 6 Exercise 6.8 PDF Download
Students can improve their skills in adding and subtracting fractions by using the detailed RD Sharma Solutions for Class 6 Maths Chapter 6 Exercise 6.8. With clear, step-by-step explanations, students can learn to handle fractions confidently and accurately.
You can download the RD Sharma Solutions for Class 6 Maths Chapter 6 Exercise 6.8 PDF from the link below.
