RD Sharma Solutions for Class 6 Maths Chapter 7 Exercise 7.2: RD Sharma’s Exercise 7.2 focuses on converting fractions and mixed numbers into decimals, understanding place value, and plotting decimals on a number line.
Students learn to write expressions like “three tenths” as 0.3, expand values such as 279.5, and convert simple fractions (e.g., 3/2 = 1.5) into precise decimal form.
Aligned with the CBSE syllabus and exam pattern, these solutions also serve as great practice for school tests and model papers. Reviewing them alongside previous-year papers can boost accuracy and exam readiness. Below is the link to download the complete PDF.
Here is what is covered in RD Sharma Solutions for Class 6 Maths Chapter 7 Exercise 7.2 (Decimals):
Converting verbal expressions into decimal numbers (e.g., "three tenths" to 0.3).
Writing mixed number expressions as decimals (e.g., "twenty-two and six tenths" to 22.6).
Expanding numbers into hundreds, tens, ones, and tenths, then writing them as decimals.
Converting simple fractions (like 22/10, 3/2, 2/5) into decimal form.
Plotting and identifying decimal values on a number line.
Finding two whole numbers between which a given decimal lies.
Determining the nearest whole number to a given decimal.
Building strong understanding of place value and decimal representation.
RD Sharma Solutions for Class 6 Maths Chapter 7 Exercise 7.2 cover important decimal concepts such as conversion of fractions, place value, and representing decimals on a number line.
These solutions are aligned with the CBSE Class 6 syllabus and help students strengthen their understanding for exams. For clear, step-by-step explanations, check the complete solutions provided below.
1. Write each of the following as decimals:
(i) Three tenths
(ii) Two ones and five tenths
(iii) Thirty and one tenths
(iv) Twenty two and six tenths
(v) One hundred, two ones and three tenths
Solution:
(i) Three tenths
It can be written as
3/10 = 0.3
(ii) Two ones and five tenths
It can be written as
2 + 5/10 = 2.5
(iii) Thirty and one tenths
It can be written as
30 + 1/10 = 30.1
(iv) Twenty two and six tenths
It can be written as
22 + 6/10 = 22.6
(v) One hundred, two ones and three tenths
It can be written as
100 + 2 + 3/10 = 102.3
2. Write each of the following as decimals:
(i) 30 + 6 + 2/10
(ii) 700 + 5 + 7/10
(iii) 200 + 60 + 5 + 1/10
(iv) 200 + 70 + 9 + 5/10
Solution:
(i) 30 + 6 + 2/10
In the above question
We know that
3 tens, 6 ones and 2 tenths
Hence, the decimal is 36.2.
(ii) 700 + 5 + 7/10
In the above question
We know that
7 hundreds, 5 ones and 7 tenths
Hence, the decimal is 705.7.
(iii) 200 + 60 + 5 + 1/10
In the above question
We know that
2 hundreds, 6 tens, 5 ones and 1 tenths.
Hence, the decimal is 265.1.
(iv) 200 + 70 + 9 + 5/10
In the above question
We know that
2 hundreds, 7 tens, 9 ones and 5 tenths
Hence, the decimal is 279.5.
3. Write each of the following as decimals:
(i) 22/10
(ii) 3/2
(iii) 2/5
Solution:
(i) 22/10
Here the denominator is ten
Hence, the decimal is 2.2
(ii) 3/2
Multiplying the fraction by 5
We get
(3/2) × (5/5) = 15/10 = 1.5
(iii) 2/5
Multiplying the fraction by 2
We get
(2/5) × (2/2) = 4/10 = 0.4
4. Write each of the following as decimals:
(i) 40 2/5
(ii) 39 2/10
(iii) 4 3/5
(iv) 25 1/2
Solution:
(i) 40 2/5
In order to write in decimal we should make the denominator 10
So we get
40 + [(2/5) × (2/2)] = 40 + 4/10 = 40.4
(ii) 39 2/10
It can be written as
39 + 2/10 = 39 + 0.2 = 39.2
(iii) 4 3/5
In order to write in decimal we should make the denominator 10
So we get
4 + [(3/5) × (2/2)] = 4 + 6/10 = 4.6
(iv) 25 1/2
In order to write in decimal we should make the denominator 10
So we get
25+ [(1/2) × (5/5)] = 25 + 5/10 = 25.5
5. Write the following decimals as fractions. Reduce the fractions to lowest form:
(i) 3.8
(ii) 21.2
(iii) 6.4
(iv) 1.0
Solution:
(i) 3.8
It can be written as
= 3 + 8 tenths
On further calculation
= 3 + 8/10
We get
= 3(10/10) + 8/10
By further simplification
= 30/10 + 8/10
= 38/10
So we get
= 19/5
(ii) 21.2
It can be written as
= 21 + 2 tenths
On further calculation
= 21 + 2/10
We get
= 21(10/10) + 2/10
By further simplification
= 210/10 + 2/10
= 212/10
So we get
= 106/5
(iii) 6.4
It can be written as
= 6 + 4 tenths
On further calculation
= 6 + 4/10
We get
= 6(10/10) + 4/10
By further simplification
= 60/10 + 4/10
= 64/10
So we get
= 32/5
(iv) 1.0
Here, the number after decimal is zero so the fraction is 1.
6. Represent the following decimal numbers on the number line:
(i) 0.2
(ii) 1.9
(iii) 1.1
(iv) 2.5
Solution:
(i) 0.2 can be represented on the number line as given below:
(ii) 1.9 can be represented on the number line as given below:
(iii) 1.1 can be represented on the number line as given below:
(iv) 2.5 can be represented on the number line as given below:
7. Between which two whole numbers on the number line are the given numbers? Which one is nearer the number?
(i) 0.8
(ii) 5.1
(iii) 2.6
(iv) 6.4
(v) 9.0
(vi) 4.9
Solution:
(i) We know that
0.8 is 8 units from 0 and 2 units from 1
Hence, it is nearer to 1.
(ii) We know that
5.1 is 1 unit from 5 and 9 units from 6
Hence, it is nearer to 5.
(iii) We know that
2.6 is 6 units from 2 and 4 units from 3
Hence, it is nearer to 3.
(iv) We know that
6.4 is 4 units from 6 and 6 units from 7
Hence, it is nearer to 6.
(v) We know that
9.0 is a whole number
Hence, it is nearer to 9.
(vi) We know that
4.9 is 9 units from 4 and 1 unit from 5
Hence, it is nearer to 5.
8. Write the decimal number represented by the points on the given number line: A, B, C, D.
Solution:
A – We know that A is at eighth place between the numbers 0 and 1
Hence, the decimal is 0.8
B – We know that B is at third place between the numbers 1 and 2
Hence, the decimal is 1.3
C – We know that C is at second place between the numbers 2 and 3
Hence, the decimal is 1.9
D – We know that D is at ninth place between the numbers 2 and 3
Hence, the decimal is 2.6
RD Sharma Solutions for Class 6 Maths Chapter 7 Exercise 7.2 provide detailed and step-by-step explanations to help students understand the concepts of decimals effectively.
These solutions are designed as per the latest CBSE syllabus and are useful for building a strong foundation in mathematics. Practicing these solutions will help students improve accuracy and problem-solving skills.
The answers are presented in a simple and clear format for easy understanding. Below is the link to download the PDF of Exercise 7.2 solutions.
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Below we have provided the benefits of using RD Sharma chapter 7 ex 7.2 -
Concept Clarity:
The solutions explain decimal operations like addition, subtraction, comparison, and place value clearly, helping students build a strong foundation.
Step-by-Step Explanations:
Each problem is solved in a detailed, structured manner, which is especially helpful for understanding multi-step decimal calculations.
Aligned with CBSE Curriculum:
The solutions strictly follow the latest CBSE guidelines, making them ideal for school exams and class tests.
Improved Accuracy:
Regular practice with these solutions helps reduce careless mistakes in decimal placement and operations.
Boosts Confidence:
Understanding complex decimal concepts through solved examples gives students more confidence during exams.
Practice for Word Problems:
Exercise 7.2 includes real-life word problems involving decimals, improving analytical and application-based skills.
Self-Study Friendly:
The language and steps used are easy enough for students to learn independently without needing constant teacher support.