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NCERT Solutions For Class 11 Maths chapter-8 Binomial Theorem Exercise 8.2

NCERT Solutions For Class 11 Maths chapter-8 Binomial Theorem Exercise 8.2

NCERT Solutions for Class-11 Maths Chapter-8 Binomial Theorem


NCERT Solutions For Class 11 Maths Chapter-8 Binomial Theorem Exercise 8.2 prepared by the expert of Physics Wallah score more with Physics Wallah NCERT Class 11 maths solutions. You can download solution of all chapters from Physics Wallah NCERT solutions of class 11.


NCERT Solutions for Class-11 Maths Exercise 8.2


Find the coefficient of:

Question 1. Find the coefficient of x 5 in (x + 3) 8

Solution : It is known that (r+1) th term, (T r+1 ). in the binomial expansion of (a+b) n is given by T r+1 = n C r a n−r b r

Assuming that x 2
occurs in the (r+1) n term of the expansion (x+3) 8 , we obtain T r+1 = a C r (x) 8-r (3) r

Comparing the indices of x
in x5 in T r+1 . We obtain r = 3 Thus, the coefficient of x 5 is 8 C 3 (3) 3 =8! / 3!5!×3 3

=(8⋅7⋅6⋅5!  /  3⋅2.5!)∗3 3 =1512

Question 2. Find the coefficient of a 5 b 7 in (a – 2b) 12

Solution :
General form of the expansion ( r + 1) th is (T r+2 )………(i)

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image004.png

Write the general term in the expansion of

Question 3. Write the general term in the expansion of (x 2 – y) 6

Solution :
It is known that the general term T r+1 { which is the (r+1) n term } in the binomial expansion of (a+b)n is given by T r+1 = n C r a n -r b r .

Thus, the general term in the expansion of (x 2 −y 6 )
is T r+1 = 6 C r (x 2 ) 6−r (−y) r = (−1) r6 C r - x 12 −2r ⋅y r

Question 4. Write the general term in the expansion of (x 2 – yx) 12 , x ≠ 0

Solution :
General form of the expansion T r+1 is

{ which is the (r+1)th term } in the binomial expansion of (a+b)n is given by Tr+1=nCran−rbr.

Thus, the general term in the expansion of (x2−yx)12
is T r+1 = 12 C r (x 2 ) 12−t (−yx) r

=(−1) r12 C r −x 24−2r −y r

=(−1) r−2 C r x 24−r⋅ y r

Question 5. Find the 4 th term in the expansion of (x – 2y) 12 .

Solution :
It is known (r+1) n term, T r+1 . in the binomial expansion of (a+b) n

chapter 8-Binomial Theorem  Exercise 8.2

Question 6. Find the 13 th term in the expansion of NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image034.png

Solution :
It is known (r+1) th term, T r+1 , in the binomial expansion of (a+b) n is given by T ε+1 = n C r a n−1 b r

Thus, the 13 th
term in the expansion of

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image037.png

Find the middle terms in the expansion of:

Question 7. NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image042.png

Solution :
NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image043.png

Question 8. (x/3 + 9y) 10

Solution :
Here (a + b ) n which is an even number.

Therefore, the middle terms are (x/3 + 9y) 10 is 6th term.

General form of the expansion

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image060.png

Question 9. In the expansion of (1 + a) m + n , prove that coefficients of am and an are equal.

Solution :
NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image066.png

Question 10. The coefficients of the (r – 1) th , r th and (r + 1) th terms in the expansion of (x + 1) n are in the ratio 1:3:5. Find n and r.

Solution :
NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem/image076.png

chapter 8-Binomial Theorem  Exercise 8.2

Question 11.  Prove that the coefficient of xn in the expansion of (1 + x) 2n is twice the coefficient of xn in the expansion of (1 + x) 2n–1 .

Solution :

= It is known that (r+1) th term, (T r+1 ), in the binomial expansion of (a+b) n is given by T r+1 = n C r a n−r b r

Assuming that x n
occurs in the (r+1) n term of the expansion of (1+x) 2n , we obtain T r+1 = 2n Cr(1) 2n−r (x) r

= 2n C r (x) r

Comparing the indices of x
in xn and in T r+1 , we obtain r=n Therefore, the coefficient of xn in the expansion of (1+x) 2n is

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem

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