An insurance company selected 2000 drivers at random in a particular city to find a relationship between age and accidents. The data obtained are given in the following table:
Age group of drivers (in years) 
Number of accidents in one year 

0 
1 
2 
3 
more than 3 

18 – 29 30 – 50 Above 50 
440 505 360 
160 125 45 
110 60 35 
61 22 15 
35 18 9 
Find the probability of the following events for a driver selected at random from the city:
(i) being 18 – 29 years of age and having exactly 3 accidents in one year.
(ii) being 30 – 50 years of age and having one or more accidents in a year. (iii) having no accident in one year.
Solution
(i) The number of drivers in the age group 18–29 having exactly 3 accidents = 61
Total number of cases = 2000
So, P (driver in age group 18–29 having exactly 3 accidents in one year)
(ii) The number of drivers having in the age group 30–50 and having one or more than one accidents in one year = 125 + 60 + 22 + 18 = 225
P (driver in age group 30–50 having one or more accidents in one year)
(iii) The number of drivers having no accident in one year = 440 + 505 + 360 = 1305
So, P (driver having no accident)