
(a) P(AB) = P(A) + P(B) - P(AB)
(b)
=1 - P(A)
(c) P(ABC) = P(A) + P(B) + P(C) - P(AB) - P(AC) - P(BC) + P(ABC)
(d)
= 1 - P(A) - P(B) - P(C) + P(AB) + P(AC) + P(BC) - P(ABC)
An important class of questions asked in probability are those in which it is required to prove that certain events are independent or mutually exclusive.
For independence of events, find P(A), P(B) and P(AB)
Verify that P(AB) = P(A). P(B)
while for mutual exclusiveness, find P(AB) and show that P(AB) = 0
OR find P(AB), P(A) & P(B) and show that P(AB) = P(A) + P(B).
Note : One important distinction has to be made between pairwise independence and
independence in general. Events A1 ,..., An are pairwise independent if
P(Ai Aj) = P(Ai). P(Aj) i, j, i j, i, j {1,...,n}
and A1 ,..., An are independent if for all k , 2 ≤ k ≤ n

Hence independence pair wise independence
But not necessarily the other way round.
