Type Of Chemical Reactions In Carbonyl Compounds
Aldehydes and Ketones of Class 12
(i) Addition across C = O bond.
(ii) Replacement of carbonyl oxygen by other groups.
(iii) Oxidation
(iv) Reduction
(v) Reaction with alkalies
(vi) Miscellaneous reactions
1. Addition across C = O bond
Sr. No. |
Addition of |
Substrate |
Product |
1. |
Hydrogen cyanide |
|
|
2. |
Sodium bisulphite (NaHSO3) |
|
|
3. |
Grignard reagent (RMgX) followed by hydrolysis |
HCHO |
H3C - CH2 - OH(1° alcohol) |
Aldehydes (except formaldehyde) |
2° alcohol |
||
Ketones |
3° alcohol |
||
4. |
Alcohols (R⎯OH) |
|
Hemiacetal which finally converts to acetal |
2. Replacement of carbonyl oxygen atom with other groups
(a) Reaction with ammonia derivatives
Aldehydes & ketones react with a number of NH3 derivatives such as hydroxyl amine, hydrazine, semicarbazide etc, in weak acidic medium. In general, if we represent these derivatives by NH2 ⎯G, then their reaction with aldehydes & ketones can be represented as follows:
Ammonia derivatives & their products with carbonyl compounds
⎯G |
Ammonia Derivative |
Product obtained |
⎯OH |
NH2OH Hydroxylamine |
Oxime |
⎯NH2 |
NH2NH2 Hydrazine |
Hydrazone |
⎯NHC6H5 |
NH2NHC6H5 Phenyl hydrazine |
Phenyl Hydrazone |
|
2, 4 – dinitrophenyl hydrazine |
|
⎯NHCONH2 |
|
|
(b) Reaction with ammonia
Like ammonia derivatives, ammonia also reacts with aldehyde (except formaldehyde) & ketones to form the products, called imines.
However, formaldehyde reacts with NH3 to form hexamethylene tetramine, (CH2)6N4 also known as urotropine as shown below:
Acetone reacts with NH3 to form diacetonamine
(c) Reaction with primary amines
Aldehydes & ketones react with 10 amines to form Schiff's bases. These compounds are also called imines.
(d) Reaction with PCl5 or SOCl2 (thionyl chloride)
Aldehydes or ketones with PCl5 or thionyl chloride to form geminal dihalides.
3. Oxidation
Aldehydes are easily oxidised to carboxylic acids containing the same number of carbon atoms, as in parent aldehyde.
The reason for this easy oxidation is the presence of a hydrogen atom on the carbonyl carbon, which can be converted into ⎯OH group without involving the cleavage of any other bond. Hence, aldehydes are oxidised not only by strong oxidizing agent but also by weak oxidizing agents. As a result, aldehydes act as strong reducing agents.
- Aldehydes reduce Tollen’s reagent to Ag & appear in the form of silver mirror. This test is called silver mirror test. It is given by all aldehydes & reducing sugars.
- Aldehydes (except benzaldehyde) reduce Fehling’s solution (Cu+2 reduced to Cu+) which is an alkaline solution of cupric (Cu2+) ion complexed with tartarate ion.
- Aldehydes also reduced Benedict’s solution (Cu2+ complexed with citrate ion) to Cu+.
-
Aldehydes & ketones with a methyl or methylene group adjacent to the carbonyl group are oxidised by SeO2
- Ketones are also oxidised by caro’s acid (H2SO5) or peroxybenzoic acid (C6H5CO3H) to esters.
It is called Bayer villiger oxidation.
It is exactly oxygen insertion between carbonyl carbon & the larger of two groups attached to it.
Haloform Reaction
Due to the formation of yellow ppt. of iodoform in this reaction, it is known as iodoform test & used in for characterizing compound containing CH3CO⎯ or a group like CH3CH2OH which can be easily oxidised to CH3CO⎯ group by halogens.
4. Reduction
Carbonyl compounds can be reduced to 1° or 2° alcohol, by LiAlH4, NaBH4 or direct reduction with H2/Ni.
(a)
with LiAlH4 ⎯CHO group is reduced to ⎯CH2OH (1° alcohol) and C = C bond is also reduced when it is in conjugation with carbonyl groups.
|
Group is reduced to |
|
(2° alcohol) |
-
LiAlH4 also reduces ester & acid chloride to alcohols.
(b) NaBH4 has similar function. But this reagent does not affects (C = C) double bond.
NaBH4 does not reduce ester & acid chloride
(c) Amalgamated zinc, Zn(Hg) & conc. HCl (Clemmensen reduction) & hydrazine (NH2 –NH2) followed by reaction with strong base like KOH in alkaline glycol (Wolf Kishner reduction) reduces carbonyl group to alkyl group.
(d) Reduction to pinacol
5. Reaction with Alkalies
(A) Aldol Condensation
Two molecules of an aldehydes or a ketone having atleast one α - hydrogen atom, condense in presence of a dilute alkali to give a β - hydroxyaldehyde or β - hydroxy ketone.
The products of aldol condensation when heated with dilute acids undergo dehydration to form α, β - unsaturated aldehydes or ketones.
In general all aldehydes & ketones which contain α - hydrogen can undergo this reaction. Those which do not contain α - hydrogen like HCHO, C6H5CHO etc, do not undergo this reaction.
Mechanism
Mechanism involves formation of carbanions (i) a nucleophile form first molecules which is condensed with second molecule.
Aldol product on dehydration give α, β - unsaturated ketones.
(B) Cannizzaro’s reaction
Aldehydes that have no α-hydrogen atom (or acidic hydrogen) undergo cannizzaro reaction (CR) in which disproportionation reaction takes place one being reduced to alcohol & other being oxidised to salt of the corresponding acid. The reaction lakes place with 50% aqueous or ethanolic alkali solution.
When an aldehyde (showing CR) is treated with HCHO & 50% base, then HCHO undergo oxidation (rather than any other aldehyde). This reaction is called crossed CR.
CR involving different aldehydes or same aldehydes is proton (H+) hydride (H−) transfer reaction.
Mechanism
Step I
Step II
When the reaction is carried out in D2O instead of in H2O, it is found that there is no new C – D bond formation. This indicate that the hydrogen must come from aldehyde & not from the solvent.
(C) Perkin reaction
In this reaction aromatic aldehyde is heated with an acid anhydride & its corresponding sodium salt to form condensation products which on hydrolysis gives α, β - unsaturated acids. Acetic anhydride & sodium acetate are commonly used in this reaction.
6. Miscellaneous reactions
(i) Formation of phorone
Three moles of acetone condense in the presence of dry HCl to form phorone.
(ii) Formation of mesitylene
Three moles of acetone on refluxing with conc. Sulphuric acid produces mesitylene as one of the products.
(iii) Reaction with alc. KCN
On heating with ethanolic solution of KCN, two molecules of aromatic aldehyde undergo condensation to form benzoin. It is called benzoin condensation.
(iv) Reaction with chloroform
Ketones condenses with chloroform in presence of alkali to form chloretone.