
Some arbitrary scales for the quantitative measurement of electronegativities are as under
Pauling's scale – Pauling related the resonance energy(Δ)AB of a molecule AB with the electronegativities of the atoms A and B. If xA and xB are the electronegativities of atoms A and B respectivey then
0.208
= xA – xB if xA> xB
or ΔAB = 23.06 (xA – xB)2
ΔAB = EA-B(experimental) – EA-B(theoretical) where EA-B is the energy of A-B bond. In a purely covalent molecule, AB, the experimental and theoretical values of bond energy A-B are equal.
So ΔAB = 0
Or 0=23.06 (xA – xB)2
Or xA = xB
In an ionic molecule AB, EA-B(experimental) is more than EA-B(Theoretical).
Pauling assumed the electronegativity value of fluorine to be 4 and calculated the electronegativity values of other elements from this value.
ii) Mulliken's electronegativity: According to Mulliken, the electronegativity of an element is the average value of its ionisation potential and electron affinity. Electronegativitiy 
when both are expressed in electron volt

Effective nuclear charge: The electronegativity value increases as the effective nuclear charge on the atomic nucleus increases.
Electronegativity α Effective nuclear charge (Zeff)
Oxidation state of the atom: The electronegativity value increases as the oxidation state (i.e. the number of positive charge) of the atom increases.
Percentage ionic character of the bond = 16Δx+3.5Δx2
If the value of Δx is 2.1 then percentage ionic character is about 50. For example the order of ionic character in H–X bond is as follows–
H–F>H–Cl>H–Br>H–I
because the electronegativity difference of bonded atoms (Δx) decreases.
Bond strength: If the electronegativity difference of covalently bonded atoms (Δx) increases, the bond energy of the covalent bond also increases. For example – the order of the H–X bond strength is –
H–F>H–Cl>H–Br>H–I
As the bond strength is decreasing the acid strength is increasing. So order of increasing acid strength is
HF<HCl<HBr<HI
Acidic and basic nature of oxides of normal elements in a period: The acidic nature of the oxides of normal elements increases as we move from left to right in a period. In a period from left to right the electronegativity of the elements increases. So the difference of the electronegativities of Oxygen and the elements (x0 –xE) decreases. If the (x0 – xE) values is about 2.3 or more then oxide will be basic. If (x0 – xE) values is less than 2.3 the oxide will be acidic. The oxides of the IIIA elements are amphoteric.
The order of acidic or basic nature of the oxides of third period elements may be given as under:
Na2O MgO Al2O3 SiO2 P2O5 SO3 Cl2O7
⎯⎯⎯⎯⎯⎯⎯⎯––––⎯⎯⎯⎯⎯⎯⎯→
The value of x0 – xE is decreasing
Basic nature is decreasing
Acidic nature is increasing
iv) Metallic and non metallic properties of elements
a) The metallic character decreases as the electronegativity of the element
b) On moving from left to right in a period, the electronegativity of the elements increases. So the metallic character decreases.
c) On moving down a group, the electronegativity of the elements decreases. So the metallic character increases.
v) Basic nature of the hydroxides of elements
A hydroxide MOH of an element M may ionise in two ways in water.
M–O–H + H2O
MO– + H3O+ … (1)
M–O–H +H2O
MOH2+ + OH– … (2)
If the ionisation is according to eqn (1) then it is acidic. It is possible when ionic character of O–H bonds is more than the ionic character of M-O bond i.e. x0 – xH> x0–xM where x0, xH and xM are the electronegativities of oxygen, hydrogen and element respectively.
If the ionisation is according to eqn. (2) then it is basic. This is only possible when ionic character of O –H bond is less than M–O bond i.e x0 – xH<x0 –xM
Illustration : Electronegativity of Sn in SnCl2 is different from that of Sn in SnCl4 - explain
Solution: The electronegativity values increases as the oxidation state of the atom increases. So the attractive power of Sn(IV) in SnCl4 for electron is much greater that that of Sn(II) in SnCl2.

