Question
Find the length of a chord of a circle which is at a distance of 6 cm from the centre of the circle. The radius of the circle is 10 cm.
Solution
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Sol. AB is a chord of the circle whose distance from the centreO is 6cm. Draw OM⊥AB. Then M is mid-point of AB and AM = BM = 
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Now, in right angledΔOMA, we have
OA = 10 cm and OM = 6cm
By Pythagoras Theorem, we have
⇒ 
= 
= 100 – 36 = 64
8 cm
⇒ AB = (2 × 8) cm = 16 cm
Hence, length of the chord AB is 16 cm
