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INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

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INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

Work, Power and Energy of Class 9

INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

(i) For a freely falling body, potential energy changes into kinetic energy.

Let a body of mass m be at rest at a point at height (h) from the ground.

At highest point (h) :

Potential energy of the body U1 = mgh

Kinetic energy of the body K1 = 0 [INTERCOVERSION OF POTENTIAL AND KINEIC ENERGYu = 0] body is at rest.

As the body falls freely, it gains velocity and reduces height. Let the body have velocity v when it reaches the ground.

At lowest point:

Potential energy of the body,U2= 0 [INTERCOVERSION OF POTENTIAL AND KINEIC ENERGYh = 0]

Kinetic energy of the body,K2 = INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

From third equation of motion, v2 = u2 + 2gh

We have, v2 = 2gh [INTERCOVERSION OF POTENTIAL AND KINEIC ENERGYu = 0]

Hence, final kinetic energy INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

= mgh = Initial potential energy

(ii) For an upward projected body, kinetic energy changes into potential energy.

Let a body of mass m be projected upwards with a velocity u from a point on the ground.

At lowest point :

Kinetic energy of the body, INTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

Potential energy of the body, U2= 0

As the body rises upward, it gains height and loses velocity.

Let the body reach highest point height h where velocity becomes zero.

At highest point:

Kinetic energy of the body, K2 = 0

Potential energy of the body U2 = mgh

From third equation of motion, v2 = u2 + 2gh

We have 0 = u2 - 2gh

(INTERCOVERSION OF POTENTIAL AND KINEIC ENERGYv = 0 and g is negative for upward motion)

or u2 = 2gh

Hence, final P.E. = mgh = mINTERCOVERSION OF POTENTIAL AND KINEIC ENERGY

P.E. =INTERCOVERSION OF POTENTIAL AND KINEIC ENERGYmu2 = Initial K.E.

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