
(i) For a freely falling body, potential energy changes into kinetic energy.
Let a body of mass m be at rest at a point at height (h) from the ground.
At highest point (h) :
Potential energy of the body U1 = mgh
Kinetic energy of the body K1 = 0 [
u = 0] body is at rest.
As the body falls freely, it gains velocity and reduces height. Let the body have velocity v when it reaches the ground.
At lowest point:
Potential energy of the body,U2= 0 [
h = 0]
Kinetic energy of the body,K2 = 
From third equation of motion, v2 = u2 + 2gh
We have, v2 = 2gh [
u = 0]
Hence, final kinetic energy 
= mgh = Initial potential energy
(ii) For an upward projected body, kinetic energy changes into potential energy.
Let a body of mass m be projected upwards with a velocity u from a point on the ground.
At lowest point :
Kinetic energy of the body, 
Potential energy of the body, U2= 0
As the body rises upward, it gains height and loses velocity.
Let the body reach highest point height h where velocity becomes zero.
At highest point:
Kinetic energy of the body, K2 = 0
Potential energy of the body U2 = mgh
From third equation of motion, v2 = u2 + 2gh
We have 0 = u2 - 2gh
(
v = 0 and g is negative for upward motion)
or u2 = 2gh
Hence, final P.E. = mgh = m
P.E. =
mu2 = Initial K.E.
