Question of Exercise 1

Question Steps I and II are:

Option 1 both SN1

Option 2 both SN2

Option 3 I SN1, II SN2

Option 4 I SN2, II SN1

The catalyst used in contact process is

A: Al2O3

B: Cr2O3

C: V2O5

D: MnO2

Solution:

Explanation:

• Contact process
• By contact process, H2SO4(Sulphuric acid) is prepared in presence of V2O5(Vanadium oxide).

SO2 (g)+1/2O2 (g) SO3 (g)

(Sulphur dioxide) (Oxygen) (Sulphur trioxide)

• The catalyst in the above reaction is V2O5.

Hence, Option (C) is correct.

What is collodion

Solution:

Explanation:

Collodion is a flammable, syrupy 4% solution of Nitro cellulose prepared in a mix of alcohol and ether.

Collodion solutions are of two types:

• Flexible collodion
• Non-flexible collodion

The two types of collodions find different kinds of utility, e.g: Flexible collodion solutions are used in surgical dressings whereas Non-flexible collodion is used in theatrical make-up, photography, etc.

Collodion solutions also find utility in:

• Electro- enecephalography
• Optic cleaning
• Microscopic study
• Nail polish, etc.

Final Answer: Collodion solution is a solution of nitrocellulose in ether and alcohol.

Aluminium crystallises in a cubic close packed structure

Its metallic radius is 125 pm.(i) What is the length of the side of the unit cell?(ii) How many unit cells are there in 1.00 cm3 of aluminium?

Solution:

Explanation:

The length of the side of the unit cell =354pm

The number of unit cells in 1.00 cm^3 of aluminium =2.27×1022

Draw the structure of and identify the number

of single P - O bonds .P4O6

Solution:

Solution:

It is the anhydride of orthophosphoric acid,  (phosphorus trioxide) therefore also known as phosphorous oxide or phosphorous anhydride. P4O6

It is a solid soft white color. It is an anhydride of an acid so it behaves as  an acidic and will hydrolyze in water to generate phosphorous acid. Phosphorus trioxide is a dimer with the formula . P4O6

Structure of can be shown as: P4O6

Number of single P-O bonds are 12 as shown in the figure.

If NaCl is doped with 10-3 mol percent

of  What is the concentration of cation vacancies?SrC12

Solution:

Solution:

NaCl is doped with 10-3  mol percent of  SrC12

Then we can define that 100 moles of NaCl are doped with 0.001 moles of SrC12

Thus 1 mole of NaCl is doped with 0.001/100=10-5 moles of SrC12

This can also be defined as 10-5 moles of Sr2+ cations.

This defines that one Sr2+ ion creates one cation vacancy.

So 10-5 moles of Sr2+ will create 10-5  moles of cation vacancies which will be calculated by just multiplying it by avogadro number

10-5×6.022×1023=6.022×1018

Final answer: Thus, 6.0221018 cation vacancies per mole of NaCl.