Question of Exercise 1

Square and square roots of Class 8

A school collected Rs. 2304 as fees from its students. If each student paid as much fees as there were students in the school how many students were there in the school?

Frequently Asked Questions

Write the coefficients of x^2 in each of the following

(i) 2 + x^2 + x   

(ii) 2 - x^2 + x^3 

(iii)  pi/2x^2 + x

(iv) √(2)x - 1




A coefficient is a number or quantity that is associated with a variable. It's commonly an integer multiplied by the variable immediately adjacent to it.

(i) 2+x2+x 

The x2 coefficient is 1.

(ii) 2-x2+x3

The x2 coefficient is -1.

(iii) (π/2)x2+x

The x2 coefficient is π /2.


In the provided formulation, there is no x2 term. It can be rewritten as 0x2 +√ 2x - 1

The coefficient of x2 equals 0 because x2 does not exist.

Final Answer:

(i) 2+x2+x , the coefficient of  x2 is 1.

(ii) 2-x2+x3, the coefficient of   x2  is -1.

(iii) (π/2)x2+x, here the coefficient of   x2  is  π/2.

(iv) √2x-1, the coefficient of   x is  0.


Which of the following is are correct

A:6 ÷ 3 =2

B:3 ÷ 6 =1/2 

C:6 ÷ 3 ≠ 3 ÷ 6 

D: None of the above





How many faces and edges does a triangular prism have



  • The triangular prism's sides and bases are either congruent or oblique. 
  • The prism's edges connect to the appropriate sides. 
  • The two bases of this prism are equilateral triangles, and their edges are parallel to one another. 
  • To grasp the structure, look at the diagram below.

triangular prism

  • It contains 9 edges, 5 faces, and 6 vertices in total (which are joined by the rectangular faces).
  • It features three rectangular sides and two triangular bases.
  • The triangular prism is considered to be semiregular if the triangular bases are equilateral and the other faces are squares rather than rectangles.

Final Answer:

5 faces and 9 edges.


Find the cube root of 125



  • A number's cube root is a number that, when multiplied three times, returns the original number 125. 
  • The cube root of 125 is represented as ∛125 using the 3rd root sign.
  • Let P be an integer such that its cube is 125, P3 = 125 or .
  • Assume that P = 1,2,3... and that its cube equals 125.

            1 x 1 x 1 = 1

            2 x 2 x 2 = 8

            3 x 3 x 3 = 27

            4 x 4 x 4 = 64

            5 x 5 x 5 = 125

  • As a result, ∛125 = ∛5x5x5=5 .

Final Answer:

Hence, the cube root of 125 is 5 .

Find the square root of 5



From the question, we have to find the square of pic6.



Final Answer:

Square root is pic8.


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